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(a) Graph f(x)=2cosx2+3andg(x)=4on the same Cartesian plane for the interval 0,4Ï€.

(b) Solve f(x)=g(x)on the interval 0,4Ï€and label the points of intersection on the graph drawn in part (a).

(c) Solve f(x)<g(x) on the interval 0,4Ï€.

(d) Shade the region bounded by f(x)=2cosx2+3andg(x)=4between the two points found in part (b) on the graph drawn in part (a).

Short Answer

Expert verified

Part a. The graph off(x)=2cosx2+3andg(x)=4on the same cartesian plane for the interval0,4Ï€is

Part b. The solution off(x)=g(x)ontheinterval0,4Ï€is2Ï€3,10Ï€3and the points on the graph is

Part c. The solution of f(x)<g(x)ontheinterval0,4Ï€is 2Ï€3<x<10Ï€3.

Part d. The shaded region bounded by f(x)=2cosx2+3andg(x)=4between the two points found in part (b) on the graph drawn in part (a) is

Step by step solution

01

Part (a) Step 1. Given Information 

The given functions aref(x)=2cosx2+3andg(x)=4.

We have to graph the given functions on the same cartesian plane for the interval0,4Ï€.

02

Part (a)  Step 2. Sketch the graph 

The graph of f(x)=2cosx2+3andg(x)=4on the same cartesian plane for the interval 0,4Ï€is

03

Part (b) Step 1. Solving 

We have to solvef(x)=g(x),0≤x≤4π.

f(x)=g(x)2cosx2+3=42cosx2=1cosx2=12x2=Ï€3,5Ï€3x=2Ï€3,10Ï€3

04

Part (c) Step 1. Solving 

We have to solve f(x)<g(x)ontheinterval0,4Ï€.

f(x)<g(x)2cosx2+3<4cosx2<12Ï€3<x2<5Ï€32Ï€3<x<10Ï€3

05

Part (d) Step 1. Shading the region 

The shaded region bounded by f(x)=2cosx2+3andg(x)=4between the two points found in part (b) on the graph drawn in part (a) is

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