/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Free solutions & answers for Precalculus Enhanced with Graphing Utilities Chapter 14 - (Page 2) [step by step] 9780321795465 | 91Ó°ÊÓ

91Ó°ÊÓ

Chapter 14: A Preview of Calculus: The Limit, Derivative, and Integral of a Function

Q. 10

Page 897

In Problems 9–20, find the slope of the tangent line to the graph of f at the given point. Graph f and the tangent line.

f(x)=-2x+1at-1,3

Q. 10

Page 904

Repeat Problem 9 for f(x)=4x

Q. 10

Page 883

In Problems 7– 42, find each limit algebraically

limx→-3x

Q. 10

Page 876

In Problems 7–16, use a table to find the indicated limit.

10.limx→02-xx2+4.

Q. 11

Page 907

In Problems 8–12, use the accompanying graph ofy=f(x)

Does limx→1f(x)exist? If so, what is it? If not, explain why not?

Q. 11

Page 889

True or False If f is continuous at c, thenlimx→c+f(x)=f(c).

Q. 11

Page 904

The function f(x)=-3x+9 is defined on the interval
[0,3]
(a) Graph f.
In (b)–(e), approximate the area A under f from 0to 3
as follows:
(b) Partition [0,3] into three sub intervals of equal length and choose u as the left endpoint of each sub interval.
(c) Partition [0,3] into three sub intervals of equal length and choose u as the right endpoint of each sub interval.
(d) Partition [0,3] into six sub intervals of equal length and choose u as the left endpoint of each sub interval.
(e) Partition [0,3] into six sub intervals of equal length and choose u as the right endpoint of each sub interval.
(f) What is the actual area A?

Q. 11

Page 883

In Problems 7– 42, find each limit algebraically

limx→-2(5x)

Q. 11

Page 905

find the limit limx→3x4-3x3+x-3x3-3x2+2x-6

Q. 11

Page 897

In Problems 9–20, find the slope of the tangent line to the graph of f at the given point. Graph f and the tangent line.

f(x)=x2+2at-1,3

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