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In Problems 8–12, use the accompanying graph ofy=f(x)

Does limx→1f(x)exist? If so, what is it? If not, explain why not?

Short Answer

Expert verified

The limit exists that islimx→1f(x)=2

Step by step solution

01

Step 1. General formula

The value of a limit is found by using,

limx→c-f(x)=limx→c+f(x)=limx→cf(x)

It is clear from the graph,

limx→1-f(x)=2limx→1+f(x)=2

02

Step 2. Value of the limit

We have found that,

limx→1-f(x)=2=limx→1+f(x)

Therefore,

limx→1f(x)=2

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