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Evaluate the determinant of \(A\). $$A=\left[\begin{array}{rr} 5 & 2 \\ -2 & 4 \end{array}\right]$$

Short Answer

Expert verified
The determinant of matrix \(A\) is 24.

Step by step solution

01

Identify the elements of the matrix

Given matrix \[A = \{\begin{bmatrix}5 & 2\ -2 & 4\end{bmatrix}\}. The elements of the matrix are a=5, b=2, c=-2 and d=4.
02

Apply the determinant formula to the elements

The formula for a 2x2 matrix determinant is (a*d) - (b*c). Substituting the identified elements, we get: (5*4) - (2*-2).
03

Solve the equation

Solve the equation to find the determinant of the matrix. It becomes 20 - (-4) = 24.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

2x2 Matrix Determinant
Understanding the determinant of a 2x2 matrix is essential for students diving into linear algebra and its applications. Essentially, the determinant provides critical information about the matrix, such as whether it has an inverse and what its scaling factor is. For a 2x2 matrix, calculating the determinant is quite straightforward. Imagine you have a small grid with two rows and two columns filled with numbers. The positions of these numbers are crucial, and each has a unique role to play when we perform the determinant calculation.

When facing a matrix like

A=\[\[\begin{align*}\left[\begin{array}{rr}5 & 2 \-2 & 4 \end{array}\right]\end{align*}\]\]

, envision drawing two diagonals within the grid of numbers. One diagonal connects the top left to the bottom right (elements a and d), and the other from top right to bottom left (elements b and c). The determinant is obtained by multiplying the numbers on the first diagonal and then subtracting the product of the numbers on the second diagonal. It's like a secret code where the difference between these two products reveals important properties about the matrix.
Matrix Elements
Each number in a matrix is known as an element and every element has a specific location, defined by its row and column. In the provided exercise, the matrix

A=\[\[\begin{align*}\left[\begin{array}{rr}5 & 2 \-2 & 4 \end{array}\right]\end{align*}\]\]

consists of four elements: a, b, c, and d. These are not arbitrary labels but specific to their position within the matrix.
  • Element 'a' is at the top left and in this case, it is 5.
  • Element 'b' which is 2, is at the top right position.
  • Element 'c', located at the bottom left, is -2 in this instance.
  • Finally, element 'd' is at the bottom right and is denoted by 4.

Each element is a piece of the puzzle, and determining the properties of the matrix depends on the value and location of these elements. When we talk about calculating determinants, each of these elements plays a role in the formula and ultimately influences the outcome.
Determinant Formula
The determinant formula for a 2x2 matrix might seem like magic at first, but it's actually quite logical. The formula looks simple:

ad - bc

, yet it tells us so much about the matrix. This is the formula used in the exercise for matrix

A=\[\[\begin{align*}\left[\begin{array}{rr}5 & 2 \-2 & 4 \end{array}\right]\end{align*}\]\]

. To put the determinant formula into action, you take the product of the elements on the leading diagonal (that's a and d) and subtract the product of the other diagonal (b and c).

Using the presented exercise, by substituting a = 5, b = 2, c = -2, and d = 4 into the formula, we get

(5 * 4) - (2 * -2)

. When you calculate this, you end up with 20 - (-4), which simplifies to 20 + 4, giving us 24. The determinant of this matrix is 24, and this is more than just a number. It suggests that this particular matrix will scale areas by a factor of 24, and since it’s not zero, we know the matrix is invertible which is vital information in linear transformations and solving systems of equations.

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Most popular questions from this chapter

The following is a system of three equations in only two variables. $$\left\\{\begin{array}{r} x-y=1 \\ x+y=1 \\ 2 x-y=1 \end{array}\right.$$ (a) Graph the solution of each of these equations. (b) Is there a single point at which all three lines intersect? (c) Is there one ordered pair \((x, y)\) that satisfies all three equations? Why or why not?

Time Bill can't afford to spend more than \(\$ 90\) per month on transportation to and from work. The bus fare is only \(\$ 1.50\) one way, but it takes Bill 1 hour and 15 minutes to get to work by bus. If he drives the 20 -mile round trip, his one-way commuting time is reduced to 1 hour, but it costs him S.45 per mile. If he works at least 20 days per month, how often does he need to drive in order to minimize his commuting time and keep within his monthly budget?

Consider the following system of equations. $$\left\\{\begin{array}{l}6 u+6 v-3 w=-3 \\\2 u+2 v-w=-1\end{array}\right.$$ (a) Show that each of the equations in this system is a multiple of the other equation. (b) Explain why this system of equations has infinitely many solutions. (c) Express \(w\) as an equation in \(u\) and \(v\) (d) Give two solutions of this system of equations.

Involve positive-integer powers of a square matrix \(A . A^{2}\) is defined as the product \(A A ;\) for \(n \geq 3, A^{n}\) is defined as the product \(\left(A^{n-1}\right) A\) Find \(\left(A^{3}\right)^{-1}\) and \(\left(A^{-1}\right)^{3},\) where \(A=\left[\begin{array}{rr}-5 & -1 \\ 4 & 1\end{array}\right] .\) What do you observe?

The sum of the squares of two positive integers is \(85 .\) If the squares of the integers differ by 13 find the integers.

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