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The following is a system of three equations in only two variables. $$\left\\{\begin{array}{r} x-y=1 \\ x+y=1 \\ 2 x-y=1 \end{array}\right.$$ (a) Graph the solution of each of these equations. (b) Is there a single point at which all three lines intersect? (c) Is there one ordered pair \((x, y)\) that satisfies all three equations? Why or why not?

Short Answer

Expert verified
By graphing the three equations, it comes evident if there is a single point at which all lines intersect. If such a point exists, it stands for the values of x and y that solve the entire system. If there isn't, the system has no solution. The solutions should be confirmed by substituting them back into the original equations.

Step by step solution

01

Reformat Equations into y = mx + c

This form is more convenient for graphing. The equations become: \n 1. y = x - 1 2. y = 1 - x 3. y = 2x - 1
02

Graph the Equations

Now, one could graph these equations on a coordinate plane. For this task, it is sufficient by creating a table of at least two values for x and then finding the corresponding y for each one, and afterwards plotting these points and drawing the line through them.
03

Find the Intersection Points

The next step is to identify if there is a single point at which all three lines intersect. This can be done by observing the graph. Alternatively, solve the equations pairwise - first 1 and 2, then 2 and 3, and lastly 1 and 3 - and compare the solutions.
04

Confirm the Solution

Once the point of intersection is found, it should be plugged back into each of the original equations to verify that it indeed solves all three of them. If it does not, error checks need to be performed on earlier steps.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Linear Equations
Understanding how to graph linear equations is essential for solving a system of equations. The standard form of a linear equation is typically expressed as \( Ax + By = C \). However, for graphing purposes, it's often more practical to use the slope-intercept form, \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept, the point where the line crosses the y-axis.

In the given exercise, the equations were reformatted to this user-friendly form. Once reformatted, you can plot the equation by choosing values for x, calculating the corresponding y values, and then placing those points on the graph. For a straight line, only two points are needed to determine the line because a straight line is the shortest distance between two points.

Learning to graph these equations accurately is crucial because visual representation helps verify solutions and understand the relationships between equations in a system. It's also a good practice to label your axes, plot points with precision, and draw the lines using a straight edge.
Solution of a System
The solution of a system of equations refers to the set of values that satisfies all equations in the system simultaneously. In the context of linear equations, this is generally the point where the lines intersect on a graph. When dealing with a system, it's important to find the values for the variables that make all the equations true at the same time.

For example, if you're given a system consisting of two equations with the same two variables, you'll be looking for a pair of x and y values that satisfy both equations. This forms the cornerstone of algebra and helps us solve real-world problems with multiple constraints. In complex systems where graphing may not be feasible or precise, algebraic methods such as substitution or elimination are employed to find the solution. However, graphing provides a visual check that can reinforce algebraic findings.
Point of Intersection
The point of intersection is precisely where two or more lines on a graph cross each other. This single point represents the set of values that solves each of the equations involved. In a system with two variables, such as the one in the exercise, the point of intersection is the ordered pair \((x, y)\) that is the solution to the system.

While graphically a common point of intersection can often be identified by eye, it is always good practice to solve the equations algebraically for confirmation. If lines do not intersect, they may be parallel, indicating that no solution exists that satisfies all the equations, or they may overlap entirely, implying an infinite number of solutions. For the given problem, one would investigate the point(s) of intersection by checking if there is a consistent ordered pair when solving the equations pairwise. The point of intersection is where the logic of the system crystallizes into an exact answer that tells the story of the relationship between the equations.

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Most popular questions from this chapter

Involve positive-integer powers of a square matrix \(A . A^{2}\) is defined as the product \(A A ;\) for \(n \geq 3, A^{n}\) is defined as the product \(\left(A^{n-1}\right) A\) Find \(\left(A^{3}\right)^{-1}\) and \(\left(A^{-1}\right)^{3},\) where \(A=\left[\begin{array}{rr}-5 & -1 \\ 4 & 1\end{array}\right] .\) What do you observe?

For the given matrices \(A, B,\) and \(C,\) evaluate the indicated expression. $$\begin{aligned}&A=\left[\begin{array}{rr}3 & 1 \\\2 & 5 \\\\-2 & 1\end{array}\right] ; \quad B=\left[\begin{array}{rr}-5 & -3 \\\1 & 6 \\\8 & 3\end{array}\right]\\\&C=\left[\begin{array}{rrr}2 & 1 & 1 \\\0 & -1 & 7 \\\3 & 0 & -3\end{array}\right] ; \quad C B+2 A\end{aligned}$$

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