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Factoring quadratics is a method used to express a quadratic equation in the form of two binomials multiplied together. Consider the quadratic function given by the exercise: \(g(x) = 2x^{2} + 5x - 3\). The idea is to find two numbers that multiply to the product of the coefficient of \(x^2\) (a) and the constant term (c), while simultaneously adding up to the coefficient of \(x\) (b).

• In our equation, \(a = 2\), \(b = 5\), and \(c = -3\).
• We look for two numbers that multiply to \(2 \, * \, (-3) = -6\) and add to 5.
• The numbers that work are 6 and -1 because \(6 * (-1) = -6\) and \(6 + (-1) = 5\).

Next, rewrite the quadratic expression using these numbers to separate the middle term, \(5x\):
\(g(x) = 2x^{2} + 6x - 1x - 3\).
Then, group the terms to factor by grouping:
\(g(x) = (2x^{2} + 6x) + (-1x - 3)\).
Factor each group:
\(g(x) = 2x(x + 3) - 1(x + 3)\).
Finally, factor out the common binomial:
\(g(x) = (2x - 1)(x + 3)\).
This tells us that the factors of the quadratic are \((2x - 1)\) and \((x + 3)\).

The quadratic formula is a universal tool for solving any quadratic equation of the form \(ax^2 + bx + c = 0\). It states that the solutions for \(x\) can be found using:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula is particularly helpful when the quadratic doesn't easily factor, or when factoring proves to be challenging.
Let's apply this formula to our quadratic \(g(x) = 2x^{2} + 5x - 3\):
- Here, \(a = 2\), \(b = 5\), and \(c = -3\).
- Substitute these values into the quadratic formula:
\[x = \frac{-5 \pm \sqrt{5^2 - 4 * 2 * (-3)}}{2 * 2}\]
- Simplify inside the square root:
\(5^2 = 25\) and \(-4 * 2 * (-3) = 24\), so the expression becomes \(25 + 24 = 49\).
- Applying the square root, \(\sqrt{49} = 7\).
- Substitute back, and simplify:
\[x = \frac{-5 \pm 7}{4}\]
This results in two solutions:

• \(x = \frac{-5 + 7}{4} = 0.5\)
• \(x = \frac{-5 - 7}{4} = -3\)

Using the quadratic formula ensures that all real solutions are found.

The real zeros of a function are the values of \(x\) where the function intersects the x-axis. In simple terms, they are the x-values where \(g(x) = 0\). Finding these zeros can help us understand the behavior and shape of the parabola described by a quadratic function.
The quadratic function \(g(x) = 2x^{2} + 5x - 3\) has its real zeros or x-intercepts where we set \(g(x) = 0\). These are the points that satisfy the equation \((2x - 1)(x + 3) = 0\) derived from our factoring.
- For \((2x - 1) = 0\), solving gives \(x = 0.5\).
- For \((x + 3) = 0\), solving gives \(x = -3\).
Thus, the real zeros are \(x = -3\) and \(x = 0.5\). These are also the x-values that you would see where the parabola crosses the x-axis on a graph. Real zeros provide insights into the nature of quadratic expressions and their graphical representation.