/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Solve the inequality by factorin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the inequality by factoring. $$5 x^{2}-8 x \geq 4$$

Short Answer

Expert verified
The solutions to the inequality are \( x \leq 0.8 \) or \( x \geq 1 \)

Step by step solution

01

Rearrange the inequality

Start by rearranging the inequality and setting it to zero. Subtract 4 from both sides to get: \(5 x^{2} - 8 x - 4 \geq 0\)
02

Factor the quadratic

Now, factor the quadratic. You can factor it as follows: \(5 x^{2} - 8 x - 4 = (5x - 4)(x - 1) \)
03

Find the critical points

Next, find the critical points of the inequality, which occur when the quadratic equals to zero. We get the two critical points by setting each factor equal to zero: \(5x - 4 = 0\) and \(x - 1 = 0\), which gives \(x = 0.8\) and \(x = 1\)
04

Test the intervals

Now test the intervals determined by the critical points. Choosing test points from each interval to put into the original inequality will help decide which intervals are part of the solution. Try \(x = 0.5\), \(x = 0.9\), and \(x = 2\). You will find that \(x = 0.5\), and \(x = 2\) are each greater than 0, while \(x = 0.9\) is not. Thus the solution to the inequality is \( x \leq 0.8 \) or \( x \geq 1 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Quadratics
Factoring quadratics is a method used to simplify a quadratic expression by expressing it as a product of two simpler expressions. This is a powerful tool for solving quadratic equations or inequalities. When the quadratic is in the form of \( ax^2 + bx + c \), the goal is to express it as \((px + q)(rx + s)\), where \(p, q, r,\) and \(s\) are numbers that satisfy the original equation. To factor a quadratic like \(5x^2 - 8x - 4\), you need to find two numbers that multiply to give the product \(a \times c = -20\) and add up to \(b = -8\). In this particular example, the expression is successfully factored into \((5x - 4)(x - 1)\).
  • Start by identifying the coefficients \(a\), \(b\), and \(c\) of the quadratic.
  • Find a pair of numbers that multiply to \(a \times c\) and sum to \(b\).
  • Rewrite the middle term using these two numbers and regroup the terms if needed before factoring by grouping to achieve the final factorization.
Factoring can be seen as "undoing" multiplication, and it makes other steps, like finding critical points, much simpler.
Critical Points
Critical points in solving quadratic inequalities are values of \(x\) where the quadratic expression equals zero. They are crucial because they split the number line into intervals where the expression either satisfies or does not satisfy the inequality. Once a quadratic is factored, like \((5x - 4)(x - 1)\), the critical points are determined by setting each factor equal to zero.
  • For \(5x - 4 = 0\), we find \(x = 0.8\).
  • For \(x - 1 = 0\), we find \(x = 1\).
These points are essential as they mark the boundaries of intervals that need to be tested for the inequality. Critical points serve as the transition between where the quadratic inequality flips from true to false or vice versa. Recognizing these points allows us to break the problem into manageable parts.
Interval Testing
Interval testing is a step where you determine which regions (defined by the critical points) satisfy the inequality. This involves picking test values from intervals split by these critical points. Each interval represents a different segment on the number line where the inequality might behave differently. For this quadratic \((5x - 4)(x - 1) \geq 0\), the critical points divide the line into intervals: \((-\infty, 0.8)\), \((0.8, 1)\), and \((1, \infty)\).
  • Choose a test point from each region, like \(x = 0.5\), \(x = 0.9\), and \(x = 2\).
  • Plug these numbers into the factored inequality \((5x - 4)(x - 1)\).
  • Determine if the result is positive or negative to see if the inequality holds.
Testing intervals is like simple detective work; it reveals where the inequality is true. Once completed, compile the results to identify the solution set: in this case, \(x \leq 0.8\) or \(x \geq 1\). This process ensures accuracy in finding the solution to the inequality.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The shape of the Gateway Arch in St. Louis, Missouri, can be approximated by a parabola. (The actual shape will be discussed in an exercise in the chapter on exponential functions.) The highest point of the arch is approximately 625 feet above the ground, and the arch has a (horizontal) span of approximately 600 feet. (Check your book to see image) (a) Set up a coordinate system with the origin at the midpoint of the base of the arch. What are the \(x\) -intercepts of the parabola, and what do they represent? (b) What do the \(x\)- and \(y\)-coordinates of the vertex of the parabola represent? (c) Write an expression for the quadratic function associated with the parabola. (Hint: Use the vertex form of a quadratic function and find the coefficient \(a .)\) (d) What is the \(y\)-coordinate of a point on the arch whose (horizontal) distance from the axis of symmetry of the parabola is 100 feet?

Graph each quadratic function by finding a suitable viewing window with the help of the TABLE feature of a graphing utility. Also find the vertex of the associated parabola using the graphing utility. $$h(x)=(\sqrt{2}) x^{2}+x+1$$

A rectangular garden plot is to be enclosed with a fence on three of its sides and an existing wall on the fourth side. There is 45 feet of fencing material available. (a) Write an equation relating the amount of available fencing material to the lengths of the three sides that are to be fenced. (b) Use the equation in part (a) to write an expression for the width of the enclosed region in terms of its length. (c) For each value of the length given in the following table of possible dimensions for the garden plot, fill in the value of the corresponding width. Use your expression from part (b) and compute the resulting area. What do you observe about the area of the enclosed region as the dimensions of the garden plot are varied? $$\begin{array}{ccc}\hline \begin{array}{c}\text { Length } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Width } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Total Amount of } \\\\\text { Fencing Material (feet) }\end{array} & \begin{array}{c}\text { Area } \\\\\text { (square feet) }\end{array} \\\\\hline 5 & & 45 \\\10 & & 45 \\\15 & & 45 \\\20 & & 45 \\\30 & & 45 \\\k & & 45 \\\& &\end{array}$$ (d) Write an expression for the area of the garden plot in terms of its length. (e) Find the dimensions that will yield a garden plot with an area of 145 square feet.

The point (2,4) on the graph of \(f(x)=x^{2}\) has been shifted horizontally to the point \((-3,4) .\) Identify the shift and write a new function \(g(x)\) in terms of \(f(x)\).

The range of a quadratic function \(g(x)=a x^{2}+b x+c\) is given by \((-\infty, 2] .\) Is \(a\) positive or negative? Justify your answer.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.