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Find the domain, \(x\) -intercept, and vertical asymptote of the logarithmic function and sketch its graph. $$h(x)=\ln (x+5)$$

Short Answer

Expert verified
The domain of the function \(h(x)=\ln(x+5)\) is \((-5, \infty)\), the x-intercept is at \(-4\), and there is a vertical asymptote at \(x=-5\).

Step by step solution

01

Finding the Domain of the Logarithmic Function

Start by finding the domain of the logarithmic function \(h(x)= \ln (x+5)\). The domain is the set of all possible x-values. The logarithm of a negative number or zero is undefined, so we set \(x+5>0\). Solving this inequality gives \(x > -5\). So, the domain of the function is \(-5 < x < \infty\) or in interval notation \((-5, \infty)\)
02

Finding the x-intercept of the function

The x-intercept is the value of x at which the function equals zero. Thus, we set \(h(x)=0\) and solve for \(x\). Therefore, we get \(0=\ln(x+5)\). This can be changed to exponential form as \(e^0=x+5\). Hence, we get the x-intercept as \(x=e^0-5=1-5=-4\). Thus, the x-intercept is at \(-4\).
03

Finding the Vertical Asymptote

The logarithmic function \(h(x)=\ln(x+5)\) will have a vertical asymptote at \(x=-5\) because as we approach this x-value from the right, the function increases without bound.
04

Graphing the Function

On the graph, mark the x-intercept at \(-4\), the vertical asymptote at \(x=-5\). The function starts from the vertical asymptote and passes through the x-intercept. The line rises to the right of the y-axis and approaches the x-axis but never crosses it. This provides a sketch of the function \(h(x)=\ln(x+5)\).

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