/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 85 Graphical Analysis Use a graphin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graphical Analysis Use a graphing utility to graph \(f\) and \(g\) in the same viewing window and determine which is increasing at the greater rate as \(x\) approaches + \(\infty\). What can you conclude about the rate of growth of the natural logarithmic function? (a) \(f(x)=\ln x, \quad g(x)=\sqrt{x}\) (b) \(f(x)=\ln x, \quad g(x)=\sqrt[4]{x}\)

Short Answer

Expert verified
From the above analysis, it's evident that both the square root function and the fourth root function increase at a slower rate than the natural logarithm function as \(x\) approaches +\(\infty\). Therefore, it can be concluded that the rate of growth of the natural logarithm function is greater than the rate of growth of the root functions as \(x\) goes to +\(\infty\).

Step by step solution

01

Plot the Graphs for (a)

First, use a graphing utility to plot the functions \(f(x) = \ln x\) and \(g(x) = \sqrt{x}\) in the same viewing window. Pay special attention to the behavior of the functions as \(x\) approaches +\(\infty\).
02

Analyze the Graphs for (a)

Next, analyze these graphs to determine which function is increasing at the greater rate as \(x\) approaches +\(\infty\). Observe the points where the two graphs intersect, and which function tends to infinity faster from those points.
03

Plot the Graphs for (b)

Similarly, plot the functions \(f(x) = \ln x\) and \(g(x) = \sqrt[4]{x}\) using the graphing utility.
04

Analyze the Graphs for (b)

Analyze the graphs of these functions as in step 2. Determine which function is growing at a faster rate as \(x\) increases.
05

Draw Conclusions

Based on the analysis, draw conclusions on the rate of growth of these functions as \(x\) approaches +\(\infty\), giving special attention to the rate of growth of the natural logarithmic function. This conclusion would involve comparing the growth rates of the natural logarithm function to the square root and fourth root functions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithmic Function
The natural logarithmic function is represented as \( f(x) = \ln x \). This function is considered one of the most important in mathematics due to its unique properties. When you think about the natural logarithm, it's helpful to remember a few crucial points. For one, \( \ln x \) is only defined for \( x > 0 \). This is because you cannot take the logarithm of a negative number or zero. So, when plotting or analyzing \( \ln x \), focus on the positive x-values.
Moreover, the natural logarithmic function increases monotonically, meaning it continually rises without ever decreasing. However, its rate of increase slows down as \( x \) gets larger.
When \( x = 1 \), \( \ln x = 0 \), and when \( x \) is greater than 1, \( \ln x \) becomes positive.
Another interesting property is its inverse relationship with the exponential function. The equation \( e^{\ln x} = x \) establishes this inverse nature.
So, understanding these properties helps in determining how \( \ln x \) behaves in comparison with other functions as \( x \) approaches infinity.
Growth Rate Comparison
Growth rate comparison becomes especially interesting when analyzing different functions, like those given in our problem: \( f(x) = \ln x \), \( g(x) = \sqrt{x} \), and \( g(x) = \sqrt[4]{x} \). Let us dive into how growth rates can be compared between these functions.
  • For \( \ln x \), as \( x \) increases, the natural logarithm grows indefinitely, albeit at a slower pace.

  • The function \( \sqrt{x} \) grows faster than \( \ln x \). As \( x \) approaches infinity, the square root function becomes large more quickly than the logarithmic function.

  • The function \( \sqrt[4]{x} \), a fourth root, grows even slower than \( \sqrt{x} \), but still faster than \( \ln x \) at high x-values.
Each function exhibits distinct growth behaviors due to their different mathematical properties. Whether you're observing their graphs or evaluating derivatives, it's clear that \( \ln x \) has a slower rate of growth when compared to \( \sqrt{x} \) and \( \sqrt[4]{x} \) as \( x \) grows larger.
Comparing growth rates reveals which function dominates over others as we consider very large values of \( x \).
Behavior as x Approaches Infinity
Understanding the behavior of functions as \( x \) approaches infinity is crucial in determining which function grows faster. To see how each of our functions behave as \( x \) becomes very large can be done by observing their graphs or calculating the limits.
When \( x \rightarrow \infty \), \( \ln x \) steadily increases but at a decreasing rate, practically squeezing through a narrowing pipe. It will grow without bound, but extremely slowly compared to other exponent-based functions like \( \sqrt{x} \) and \( \sqrt[4]{x} \).
For \( \sqrt{x} \), as \( x \) increases, this function grows faster than \( \ln x \), maintaining its increasing trajectory at a consistent pace. This can be graphically observed as it pulls away from \( \ln x \).
With \( \sqrt[4]{x} \), there's an evident slower growth than \( \sqrt{x} \), but it still surpasses \( \ln x \) as \( x \) surges towards infinity. This can be observed visually in graphs where \( \sqrt[4]{x} \) maintains an edge over \( \ln x \), although not as prominent as \( \sqrt{x} \).
In sum, evaluating functions as they approach infinity is like comparing different modes of travel. \( \ln x \) is taking a leisurely stroll, while the roots are moving along at a brisker pace. This understanding is essential for anyone looking to see which functions "outrun" others as \( x \) becomes extremely large.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Population The populations \(P\) (in thousands) of Tallahassee, Florida, from 2005 through 2010 can be modeled by \(P=319.2 e^{k t},\) where \(t\) represents the year, with \(t=5\) corresponding to \(2005 .\) In \(2006,\) the population of Tallahassee was about \(347,000\) (a) Find the value of \(k .\) Is the population increasing or decreasing? Explain. (b) Use the model to predict the populations of Tallahassee in 2015 and \(2020 .\) Are the results reasonable? Explain. (c) According to the model, during what year will the population reach \(410,000 ?\)

Population The populations \(P\) (in thousands) of a city from 2000 through 2010 can be modeled by $$P=\frac{2632}{1+0.083 e^{0.050 t}}$$ where \(t\) represents the year, with \(t=0\) corresponding to 2000 (a) Use the model to find the populations of the city in the years \(2000,2005,\) and 2010 (b) Use a graphing utility to graph the function. (c) Use the graph to determine the year in which the population will reach 2.2 million. (d) Confirm your answer to part (c) algebraically.

Forensics At 8: 30 A.M., a coroner went to the home of a person who had died during the night. In order to estimate the time of death, the coroner took the person's temperature twice. At 9: 00 A.M. the temperature was \(85.7^{\circ} \mathrm{F},\) and at 11: 00 A.M. the temperature was \(82.8^{\circ} \mathrm{F}\). From these two temperatures, the coroner was able to determine that the time elapsed since death and the body temperature were related by the formula $$t=-10 \ln \frac{T-70}{98.6-70}$$ where \(t\) is the time in hours elapsed since the person died and \(T\) is the temperature (in degrees Fahrenheit) of the person's body. (This formula comes from a general cooling principle called Newton's Law of Cooling. It uses the assumptions that the person had a normal body temperature of \(98.6^{\circ} \mathrm{F}\) at death and that the room temperature was a constant \(70^{\circ} \mathrm{F}\).) Use the formula to estimate the time of death of the person.

The graph of \(f(x)=\log _{3} x\) contains the point \((27,3)\)

Exercises \(7-10\), rewrite the logarithm as a ratio of (a) common logarithms and (b) natural logarithms. $$\log _{5} 16$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.