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A classmate claims that the following are true. (a) \(\ln (u+v)=\ln u+\ln v=\ln (u v)\) (b) \(\ln (u-v)=\ln u-\ln v=\ln \frac{u}{v}\) (c) \((\ln u)^{n}=n(\ln u)=\ln u^{n}\) Discuss how you would demonstrate that these claims are not true.

Short Answer

Expert verified
All three claims made by the classmate are not valid. The correct logarithm rules are: \(\ln (u * v) = \ln u + \ln v\), \(\ln u - \ln v = \ln \frac{u}{v}\), and \(n \ln u = \ln (u^n)\).

Step by step solution

01

Check the validity of the first claim

The first claim states that \(\ln (u+v)=\ln u+\ln v=\ln (u v)\). However, the correct logarithm rule is that, \(\ln (u*v) = \ln u + \ln v\). The proposed identity \(\ln (u + v) = \ln u + \ln v\) is not accurate.
02

Check the validity of the second claim

The second claim is \(\ln (u-v)=\ln u-\ln v=\ln \frac{u}{v}\). This claim is also incorrect. According to logarithm rules, \(\ln u - \ln v = \ln \frac{u}{v}\) is valid, however, \(\ln (u - v) = \ln u - \ln v\) is not correct.
03

Check the validity of the third claim

Lastly, the third claim \((\ln u)^{n}=n(\ln u)=\ln u^{n}\) needs to be checked. However, this claim is also not correct. According to logarithm rules, \(n \ln u = \ln (u^n)\) is valid. But, \((\ln u)^n\) does not equal to \(n \ln u\) and does not equal to \(\ln (u^n)\).

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