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Llamas are often raised as pets or to carry supplies in mountainous areas. Suppose you are building a rectangular pen for a herd of llamas. You use 500 feet of fencing for the pen. Let x represent the pen’s length (in feet).

a. Write an expression for the width of the pen. Explain the steps you used to find the expression.

b. Use the distributive property to write an expression without parentheses for the area of the pen.

c. Find the width and the area of the pen if the length is 160 feet.

Short Answer

Expert verified
  1. Width:w  =  250  -  xfeet
  2. Area of the pen is 250x  -  x2 sq. feet
  3. Width is 90 feet and Area is 14400 sq. feet.

Step by step solution

01

Apply the concept of Rectangle 

Rectangle is a quadrilateral. Opposite sides are equal and parallel. Measurement of all four angles is900.

02

How to find the Perimeter of the Rectangle? 

Perimeter of rectangle is 2  (length  +  width ) unit.

03

Step 3: Write an expression for the width of the pen. Explain the steps you used to find the expression.

We know that:Perimeter of rectangle is 2  (length  +  width ) unit.

Question given the information length = x feet. Let us assume the width = w feet.

Given: Perimeter is 500 feet.

Width interms of length x feet is

±Ê±ð°ù¾±³¾±ð³Ù±ð°ù â¶Ä‰= â¶Ä‰2 â¶Ä‰(length â¶Ä‰+ â¶Ä‰width )500 â¶Ä‰= â¶Ä‰2 â¶Ä‰( â¶Ä‰x â¶Ä‰+ â¶Ä‰w â¶Ä‰) 500 â¶Ä‰= â¶Ä‰2 x â¶Ä‰+ â¶Ä‰2w â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰Substitute â¶Ä‰Perimeter=500; â¶Ä‰length â¶Ä‰= â¶Ä‰x â¶Ä‰and â¶Ä‰width â¶Ä‰= â¶Ä‰w500 â¶Ä‰âˆ’ â¶Ä‰2x â¶Ä‰= â¶Ä‰2x â¶Ä‰âˆ’ â¶Ä‰2x â¶Ä‰+ â¶Ä‰2w â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰Subtract2xfrombothsides500 â¶Ä‰âˆ’ â¶Ä‰2x â¶Ä‰= â¶Ä‰2w2w â¶Ä‰= â¶Ä‰500 â¶Ä‰âˆ’ â¶Ä‰2x â¶Ä‰â€‰â¶Ä‰â€‰we â¶Ä‰know â¶Ä‰that â¶Ä‰: â¶Ä‰a â¶Ä‰âˆ’ â¶Ä‰b â¶Ä‰= â¶Ä‰c â¶Ä‰and â¶Ä‰c â¶Ä‰= â¶Ä‰a â¶Ä‰âˆ’ â¶Ä‰b â¶Ä‰both â¶Ä‰are â¶Ä‰same.2w2 â¶Ä‰= â¶Ä‰500 â¶Ä‰âˆ’ â¶Ä‰2x2 â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰Divide â¶Ä‰each â¶Ä‰side â¶Ä‰by â¶Ä‰2 â¶Ä‰to â¶Ä‰isolate â¶Ä‰w â¶Ä‰in â¶Ä‰the â¶Ä‰left â¶Ä‰sidew â¶Ä‰= â¶Ä‰250 â¶Ä‰âˆ’ â¶Ä‰x

Width of the pen is w  =  250  -  xfeet

04

(b)Step 1: Apply the concept of Rectangle 

Rectangle is a quadrilateral. Opposite sides are equal and parallel. Measurement of all four angles is900.

05

How to find the area of the Rectangle? 

Area of rectangle is length  ·  height square unit.

06

Step 3: Use the distributive property to write an expression without parentheses for the area of the pen.

According to the question: length = x feet and we have already calculated in part a, the width is w  =  250  -  xfeet.

Area of rectangle is length  ·  heightsquare unit.

A â¶Ä‰= â¶Ä‰Length â¶Ä‰Â·â€‰â¶Ä‰WidthA=x· (250 â¶Ä‰âˆ’ â¶Ä‰x) â¶Ä‰= â¶Ä‰x â¶Ä‰Â·â€‰â¶Ä‰250 â¶Ä‰âˆ’ â¶Ä‰x · x â¶Ä‰= â¶Ä‰250x â¶Ä‰âˆ’ â¶Ä‰x2Area â¶Ä‰= â¶Ä‰250x â¶Ä‰âˆ’ â¶Ä‰x2

Area of the pen is 250x  -  x2 sq feet

07

(c)Find the width and the area of the pen if the length is 160 feet.

Area  =  14400  sq  feet

According to the question: length = x feet = 160 feet

we have already calculated in part a, the width is w  =  250  -  xfeet.

Area of the pen is 250x  -  x2 sq feet

Now substitute x = 160 feet and calculate the area.

Area â¶Ä‰= â¶Ä‰250x â¶Ä‰âˆ’ â¶Ä‰x2 â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰Substitute â¶Ä‰x â¶Ä‰= â¶Ä‰160Area â¶Ä‰= â¶Ä‰250 â¶Ä‰Â·â€‰â¶Ä‰160 â¶Ä‰âˆ’ â¶Ä‰1602 â¶Ä‰= â¶Ä‰40000 â¶Ä‰âˆ’ â¶Ä‰25600= â¶Ä‰14400 â¶Ä‰sq â¶Ä‰feet

Area  =  14400  sq  feet

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