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Undergraduate students taking an introductory statistics course at Duke University conducted a survey about GPA and major. The side-by-side box plots show the distribution of GPA among three groups of majors. Also provided is the ANOVA output. $$ \begin{array}{lrrrrr} \hline & \text { Df } & \text { Sum Sq } & \text { Mean Sq } & \text { F value } & \operatorname{Pr}(>\mathrm{F}) \\ \hline \text { major } & 2 & 0.03 & 0.015 & 0.185 & 0.8313 \\ \text { Residuals } & 195 & 15.77 & 0.081 & & \\ \hline \end{array} $$ (a) Write the hypotheses for testing for a difference between average GPA across majors. (b) What is the conclusion of the hypothesis test? (c) How many students answered these questions on the survey, i.e. what is the sample size?

Short Answer

Expert verified
(a) H0: \( \mu_1 = \mu_2 = \mu_3 \); H1: at least one \( \mu_i \) differs. (b) Fail to reject H0; no significant difference. (c) Sample size is 198.

Step by step solution

01

Write the Null Hypothesis

The null hypothesis (H0) is that there is no difference in average GPA across the three groups of majors. In statistical terms: \( H_0: \mu_1 = \mu_2 = \mu_3 \), where \( \mu_1, \mu_2, \mu_3 \) are the means of the three groups.
02

Write the Alternative Hypothesis

The alternative hypothesis (H1) is that at least one group has a different average GPA. In statistical terms, it is expressed as: \( H_1: \text{at least one } \mu_i \text{ is different} \).
03

Analyze the ANOVA Output for F-test

From the ANOVA output, the F value is 0.185 and the p-value is 0.8313. A p-value greater than 0.05 indicates that we do not have enough evidence to reject the null hypothesis at the 5% significance level.
04

Conclusion of the Hypothesis Test

Since the p-value is 0.8313, which is larger than 0.05, we fail to reject the null hypothesis. This means there is no statistically significant difference in the average GPA across the three groups of majors.
05

Calculate Sample Size

The degrees of freedom for the residuals is given as 195, which represents \( n - k \), where \( n \) is the total sample size and \( k \) is the number of groups. Here, \( k = 3 \). Therefore, \( n = 195 + 3 = 198 \). The sample size is 198 students.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a method used in statistics to determine whether there is enough evidence to reject a null hypothesis about a population. In the provided context, the null hypothesis \((H_0)\) asserts that there is no difference in average GPA among the three groups of majors. This hypothesis assumes that any observed difference is due to random chance. The alternative hypothesis \((H_1)\), on the other hand, proposes that at least one group has a different average GPA than the others. The process involves comparing calculated statistics from the data with what one expects under the null hypothesis. If the data provides sufficient evidence to the contrary, the null hypothesis is rejected. However, it’s important to note that rejecting the null hypothesis doesn’t prove the alternative; it merely suggests it’s more likely given the evidence.In context, the ANOVA test is performed to investigate whether the observed GPAs can be attributed to actual differences rather than random variation.
Statistical Significance
Statistical significance is a critical concept used to determine if the results of a study are likely to represent true relationships rather than random chance. This is often determined using a p-value—a probability measure that helps understand whether to reject the null hypothesis. In our ANOVA example, the test computes a p-value based on the data collected. A common threshold to determine significance is 0.05. If the p-value is less than this threshold, differences in group means are considered statistically significant. In the exercise, the p-value was 0.8313, which is much larger than 0.05. This high value indicates that the observed differences in GPAs are likely due to random variation, so the null hypothesis should not be rejected. Thus, we conclude that there is no statistically significant difference in GPAs among the different majors.
Box Plot Analysis
Box plots are a graphical representation for examining the distribution of data. They summarize key data points such as median, quartiles, and potential outliers. In the exercise about GPAs and majors, box plots are useful for visually assessing whether variations exist across groups. Each box plot for a major shows a horizontal box that represents the interquartile range (IQR)—the middle 50% of scores. The line within a box marks the median GPA for that group. Whiskers extend from the box to indicate variability outside the upper and lower quartiles. Box plots reveal the spread and central tendency effortlessly and offer a quick visual comparison of different groups. If constructions overlap significantly, it visually suggests no large difference in central tendencies—which aligns with the findings from ANOVA about GPA variations among majors.
P-Value Interpretation
The p-value is pivotal in statistical hypothesis testing as it quantifies the evidence against a null hypothesis. In simple terms, it indicates how likely we would observe the data if the null hypothesis were true. For the GPA and majors example, the calculated p-value was 0.8313. This is interpreted as the probability of obtaining an F-statistic as extreme as the observed value (or more extreme) assuming that no true difference exists in GPA across different majors. Typically, a p-value less than 0.05 would suggest strong evidence to reject the null hypothesis. Hence, a p-value of 0.8313 is quite high, suggesting that the null hypothesis cannot be rejected. This implies there is no significant evidence to claim any difference in GPA based on the data provided.

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Most popular questions from this chapter

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