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In 2013, the Pew Research Foundation reported that "45\% of U.S. adults report that they live with one or more chronic conditions". \({ }^{11}\) However, this value was based on a sample, so it may not be a perfect estimate for the population parameter of interest on its own. The study reported a standard error of about \(1.2 \%\), and a normal model may reasonably be used in this setting. Create a \(95 \%\) confidence interval for the proportion of U.S. adults who live with one or more chronic conditions. Also interpret the confidence interval in the context of the study.

Short Answer

Expert verified
The 95% confidence interval is (42.6%, 47.4%).

Step by step solution

01

Identify the Components

We have a sample proportion \( \hat{p} \) of 0.45, a standard error (SE) of 0.012, and we need to construct a 95% confidence interval. This interval uses a normal distribution, so the critical value (z*) for 95% confidence is 1.96.
02

Calculate the Margin of Error

The margin of error (ME) is calculated using the formula: \( ME = z^* \times SE \). Substitute \( z^* = 1.96 \) and \( SE = 0.012 \):\[ ME = 1.96 \times 0.012 = 0.02352 \]
03

Construct the Confidence Interval

The confidence interval is given by \( \hat{p} \pm ME \). Substitute \( \hat{p} = 0.45 \) and \( ME = 0.02352 \):\[ CI = (0.45 - 0.02352, 0.45 + 0.02352) = (0.42648, 0.47352) \]
04

Interpret the Confidence Interval

The 95% confidence interval for the proportion of U.S. adults with one or more chronic conditions is from approximately 42.6% to 47.4%. This means we are 95% confident that the true proportion of adults with chronic conditions in the population falls within this range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Standard Error
The standard error (SE) is a critical concept when discussing confidence intervals. It measures the variability or dispersion of a sample statistic, like the sample proportion, across different samples taken from the same population. In simpler terms, the standard error provides insight into how much the sample estimate, such as the 0.45 found in the Pew Research Foundation's study, could differ from the actual population parameter every time a new sample is taken.
  • It's calculated as the standard deviation of the sample proportion divided by the square root of the sample size.
  • A smaller standard error indicates that the sample mean is a more precise estimate of the population mean.
  • In the given exercise, the standard error was 0.012, meaning the sample proportion (0.45) has slight variability.
Understanding the standard error helps interpret the reliability of a confidence interval. In the context of the study, a standard error of 1.2% informs us of the expected variation in the estimated proportion of adults with chronic conditions, thereby shaping the confidence interval itself.
The Role of Normal Distribution
The normal distribution plays an essential role in statistics, particularly in constructing confidence intervals. It is a continuous probability distribution characterized by a bell-shaped curve, which is symmetrical around its mean.
For many statistical estimations, especially involving means and proportions, the sampling distribution of the sample statistic tends to be normal if the sample size is sufficiently large, due to the Central Limit Theorem (CLT).
  • In the confidence interval calculation, the normal distribution allows us to compute the critical value (z*), which determines the range of the interval.
  • The bell curve nature means that most data will fall within a few standard deviations of the mean.
In the given problem, it's assumed that a normal model is appropriate, making it feasible to calculate a 95% confidence interval using the z-score approach. This assumption ensures that the constructed interval is robust and reliable.
Calculating the Margin of Error
A key step in constructing a confidence interval is calculating the margin of error (ME). It tells us how much we can expect the sample proportion to vary from the true population proportion.
The margin of error is calculated using the formula: \[ ME = z^* \times SE \]Here, \(z^*\) is the critical value, which depends on the desired level of confidence, and SE is the standard error.
In this problem, using a critical value of 1.96 for a 95% confidence level and an SE of 0.012, the margin of error was calculated to be approximately 0.02352.
  • This means that the sample proportion of 0.45 can vary by a maximum of 0.02352 in either direction due to sampling variability.
  • The larger the margin of error, the less precise the interval. Conversely, a smaller margin of error signals higher precision.
Therefore, understanding and calculating the margin of error is crucial for determining the boundaries of a confidence interval accurately.
Defining the Critical Value
The critical value is an important concept in building a confidence interval. It is a point on the distribution that defines the boundaries of our interval estimate. This value is derived from the normal distribution and reflects the confidence level chosen by the researcher.
For example, to build a 95% confidence interval, we need a critical value (often denoted as \( z^* \)) from the standard normal distribution.
  • The critical value for a 95% confidence level is 1.96, meaning we want the interval to cover 95% of the normal distribution.
  • The greater the confidence level, the higher the critical value, resulting in a wider confidence interval.
  • The critical value directly influences the margin of error, impacting the confidence interval’s width and accuracy.
In the proposition of the exercise, a critical value of 1.96 was used to ensure that the constructed confidence interval is reliable and covers the central 95% of possible sample proportions. Understanding and selecting the correct critical value is fundamental to accurately interpreting statistical data.

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Most popular questions from this chapter

As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective. (a) What population is under consideration in the data set? (b) What parameter is being estimated? (c) What is the point estimate for the parameter? (d) What is the name of the statistic can we use to measure the uncertainty of the point estimate? (e) Compute the value from part (d) for this context. (f) The historical rate of defects is \(10 \%\). Should the engineer be surprised by the observed rate of defects during the current week? (g) Suppose the true population value was found to be \(10 \%\). If we use this proportion to recompute the value in part (e) using \(p=0.1\) instead of \(\hat{p},\) does the resulting value change much?

Write the null and alternative hypotheses in words and then symbols for each of the following situations. (a) A tutoring company would like to understand if most students tend to improve their grades (or not) after they use their services. They sample 200 of the students who used their service in the past year and ask them if their grades have improved or declined from the previous year. (b) Employers at a firm are worried about the effect of March Madness, a basketball championship held each spring in the US, on employee productivity. They estimate that on a regular business day employees spend on average 15 minutes of company time checking personal email, making personal phone calls, etc. They also collect data on how much company time employees spend on such non-business activities during March Madness. They want to determine if these data provide convincing evidence that employee productivity changed during March Madness.

For each of the following situations, state whether the parameter of interest is a mean or a proportion. It may be helpful to examine whether individual responses are numerical or categorical. (a) In a survey, one hundred college students are asked how many hours per week they spend on the Internet. (b) In a survey, one hundred college students are asked: "What percentage of the time you spend on the Internet is part of your course work?" (c) In a survey, one hundred college students are asked whether or not they cited information from Wikipedia in their papers. (d) In a survey, one hundred college students are asked what percentage of their total weekly spending is on alcoholic beverages. (e) In a sample of one hundred recent college graduates, it is found that 85 percent expect to get a job within one year of their graduation date.

For each of the following situations, state whether the parameter of interest is a mean or a proportion. (a) A poll shows that \(64 \%\) of Americans personally worry a great deal about federal spending and the budget deficit. (b) A survey reports that local TV news has shown a \(17 \%\) increase in revenue within a two year period while newspaper revenues decreased by \(6.4 \%\) during this time period. (c) In a survey, high school and college students are asked whether or not they use geolocation services on their smart phones. (d) In a survey, smart phone users are asked whether or not they use a web- based taxi service. (e) In a survey, smart phone users are asked how many times they used a web- based taxi service over the last year.

400 students were randomly sampled from a large university, and 289 said they did not get enough sleep. Conduct a hypothesis test to check whether this represents a statistically significant difference from \(50 \%\), and use a significance level of 0.01 .

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