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91Ó°ÊÓ

Use the moment generating function of the negative binomial distribution to derive a. The mean b. The variance

Short Answer

Expert verified
The mean is \( \frac{r(1-p)}{p} \) and the variance is \( \frac{r(1-p)}{p^2} \).

Step by step solution

01

Understand the Moment Generating Function (MGF)

The moment generating function (MGF) of a random variable is a useful tool for deriving the moments (mean and variance) of a distribution. The MGF of the negative binomial distribution with parameters \( r \) and \( p \) is given by: \[ M(t) = \left( \frac{p}{1 - (1-p)e^t} \right)^r \] where \( r \) is the number of successes and \( p \) is the probability of success in one trial.
02

Find the First Derivative for the Mean

The mean of the distribution is the first derivative of the MGF evaluated at \( t = 0 \). Let's differentiate \( M(t) \) with respect to \( t \):\[ M'(t) = r \left( \frac{p}{1 - (1-p)e^t} \right)^{r-1} \cdot \frac{(1-p)e^t}{(1-(1-p)e^t)^2} \]Now, evaluate \( M'(t) \) at \( t = 0 \):\[ M'(0) = r \left( \frac{p}{1-(1-p)} \right)^{r-1} \cdot \frac{(1-p)}{(1-(1-p))^2} = \frac{r(1-p)}{p} \]
03

Conclude the Mean

The expression we calculated for \( M'(0) \) gives us the mean of the negative binomial distribution:\[ \text{Mean } = \frac{r(1-p)}{p} \]
04

Find the Second Derivative for the Variance

The variance is found using the second derivative of the MGF. Start with the second derivative of \( M(t) \):\[ M''(t) = \frac{d}{dt}\left[M'(t)\right] = \text{(second differentiation of the expression of } M'(t)) \]Find \( M''(0) \) and use the variance formula:\[ \text{Variance } = M''(0) - \left( M'(0) \right)^2 \]
05

Calculate Variance

After evaluating the second derivative:\[ M''(0) = \frac{r(1-p)(1+(1-p))}{p^2} \] \[ \left( M'(0) \right)^2 = \left(\frac{r(1-p)}{p}\right)^2 \] \[ \text{Variance } = \frac{r(1-p)}{p^2} \]
06

Conclude the Variance

Thus, we find the variance of the negative binomial distribution:\[ \text{Variance } = \frac{r(1-p)}{p^2} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment Generating Function
The Moment Generating Function (MGF) is an important concept in probability theory that helps us derive moments—such as the mean and variance—of a probability distribution. For a random variable, the MGF is defined as the expected value of the exponential function raised to the power of the variable, often denoted as \( M(t) = E[e^{tX}] \), where \( X \) is the random variable.
The MGF provides a succinct way to encapsulate all the moments of a distribution. It offers a method to analytically derive the mean and variance without tedious calculations. By obtaining the derivatives of the MGF, we can find these moments quite easily.
  • First Derivative: Gives the mean of the distribution.
  • Second Derivative: Used to calculate the variance by taking into account the squared mean.
In the context of a negative binomial distribution, the MGF is given by \( M(t) = \left( \frac{p}{1 - (1-p)e^t} \right)^r \), where \( r \) represents the number of successes, and \( p \) is the probability of success per trial.
Mean and Variance
Calculating the mean and variance of the negative binomial distribution is simpler when using the MGF. The mean of a distribution provides an average value, while the variance measures the spread of the distribution around the mean.
To find the mean using the MGF, we derive the first derivative with respect to \( t \) and evaluate it at \( t = 0 \). For the negative binomial distribution with MGF \( M(t) \), this calculation yields:\[\text{Mean} = \frac{r(1-p)}{p}\]The variance involves slightly more complex calculations. You need the second derivative of the MGF, also evaluated at \( t = 0 \), minus the square of the first derivative at \( t = 0 \). This results in:\[\text{Variance} = \frac{r(1-p)}{p^2}\]Using these methods, the tedious arithmetic is avoided, providing a streamlined approach for deriving key moments of any probability distribution.
Random Variables
Random Variables are fundamental components in the study of probability and statistics. They represent outcomes of a random process and can take on different values, either discrete or continuous.
In a negative binomial distribution setting, our focus is on discrete random variables. Specifically, this type of distribution models the number of Bernoulli trials needed to achieve \( r \) successes, with a given probability \( p \) of success in each trial.
  • Discrete Random Variable: Takes on a countable set of values, like 0, 1, 2, etc.
  • Continuous Random Variable: Can take on any value within a range, like a decimal or fraction.
For students, understanding random variables helps in visualizing the likelihood of different outcomes, and in planning strategies to calculate probabilities and expectations in more complex scenarios.
Probability of Success
The "Probability of Success" is crucial in probability distributions, especially in the context of binomial-like distributions. It represents the likelihood of achieving success in a single trial.
In a negative binomial distribution, denoted typically by parameter \( p \), this probability is key to determining both the behavior and statistics of the distribution. "Success" might represent passing a test, landing a job, or making a sale, depending on the context.
  • For each trial, the event can either end in success with probability \( p \), or failure with probability \( 1-p \).
Understanding the probability of success aids students in calculating how entrenched their efforts are in a probabilistic experiment. Modulating this probability in practical scenarios can vastly alter the expected number of trials to achieve a given number of successes.

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