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If \(X\) is a negative binomial rv, then \(Y=r+X\) is the total number of trials necessary to obtain \(r S^{\prime} s\). Obtain the mgf of \(Y\) and then its mean value and variance. Are the mean and variance intuitively consistent with the expressions for \(E(X)\) and \(V(X)\) ? Explain.

Short Answer

Expert verified
The mgf of \( Y \) is \( M_Y(t) = e^{rt} \left( \frac{p}{1 - (1-p) e^t} \right)^r \); mean \( E(Y) = \frac{r}{p} \) and variance \( V(Y) = \frac{r(1-p)}{p^2} \); expressions are consistent.

Step by step solution

01

Understand the Problem

We need to find the moment generating function (mgf) of a random variable \( Y = r + X \), where \( X \) is a negative binomial random variable representing the number of failures before \( r \) successes, and \( Y \) is the total number of trials needed to achieve these \( r \) successes.
02

Recall the MGF of a Negative Binomial Random Variable

The moment generating function of a negative binomial random variable \( X \) with parameters \( r \) (number of successes) and \( p \) (probability of success on each trial) is given by \[ M_X(t) = \left( \frac{p}{1 - (1-p) e^t} \right)^r \].
03

Determine the MGF of Y

Since \( Y = r + X \), the number of successes \( r \) is a constant shift.The mgf of \( Y \) based on the mgf of \( X \) is:\[ M_Y(t) = e^{rt} M_X(t) = e^{rt} \left( \frac{p}{1 - (1-p) e^t} \right)^r \].
04

Calculate the Mean of Y

The mean of a random variable \( Y \) is the first derivative of its mgf evaluated at \( t = 0 \). From the properties of mgfs and the nature of \( Y = r + X \), the mean is:\[ E(Y) = r + E(X) = r + \frac{r(1-p)}{p} = \frac{r}{p} \].
05

Calculate the Variance of Y

The variance of a random variable \( Y \) is given by the second derivative of its mgf at \( t = 0 \) minus the square of the mean. For \( Y = r + X \), the variance remains the same as that of \( X \):\[ V(Y) = V(X) = \frac{r(1-p)}{p^2} \].
06

Consistency Check

The expressions for mean \( E(Y) = \frac{r}{p} \) and variance \( V(Y) = \frac{r(1-p)}{p^2} \) align with the nature of the problem: total trials \( Y \) includes both \( r \) successes and the associated failures \( X \). Hence, the derived expressions are consistent with the properties of \( Y \) and its components.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment Generating Function (MGF)
The Moment Generating Function, abbreviated as MGF, is a powerful tool used in probability theory to describe the distribution of a random variable. It essentially "generates" moments, such as the expected value (mean) and variance, which are crucial in statistical analysis.
The MGF of a random variable, say \( X \), is expressed as \( M_X(t) = E(e^{tX}) \).
For the negative binomial distribution, the MGF helps us derive further insights into the number of trials, such as in our problem where \( Y = r + X \).
The formula given in the original scenario for the negative binomial's MGF is \[ M_X(t) = \left( \frac{p}{1 - (1-p) e^t} \right)^r \]. This tells us that for \( Y \), the MGF is adjusted by a constant shift, showing \( M_Y(t) = e^{rt} M_X(t) \).
From the MGF, we can easily compute the characteristics of interest: the mean and variance of \( Y \). It essentially brings together complex distribution details into a manageable formula that summarizes the behavior of \( X \) and \( Y \).
Mean and Variance
Understanding the mean and variance of a random variable provides insight into its expected value and the variability in its possible outcomes.
For our specific problem, the mean of \( Y = r + X \) uses the properties of MGFs where \( E(Y) = r + E(X) \).
After calculation, we find \[ E(Y) = \frac{r}{p} \]. The mean aligns with our expectation since it accounts for both the number of successes \( r \) and the expected failures before these successes \( \/ \frac{r(1-p)}{p} \).
The variance for \( Y \) is derived similarly, with the variance \( V(Y) = V(X) \), yielding \[ V(Y) = \frac{r(1-p)}{p^2} \].
The consistency check confirms the logical coherence of these results, showing they match the properties derived from the initial problem setup. The mean informs us of the average number of trials expected, while the variance indicates the spread of these trials, highlighting the reliability of this expectation.
Random Variable
A random variable, in the simplest terms, is a variable whose values depend on the outcomes of a random phenomenon. It serves as a bridge between real-world phenomena and probability theory.
In the context of the negative binomial distribution, our random variable \( X \) represents the number of failures before achieving \( r \) successes, while \( Y = r + X \) encompasses the total number of trials.
This transformation allows us to analyze not only the outcomes directly related to failures but also the full trials expected until the successes are reached.
Understanding \( X \) and \( Y \) as random variables helps break down the larger question of probability and distribution into more manageable, familiar parts.
Random variables are foundational in statistical models, allowing us to describe complex random phenomena using interpretable statistical language.
Probability Theory
Probability theory is the mathematical framework that underpins our understanding of phenomena that are subject to chance. It involves the rigorous analysis of random variables, their distributions, and their characteristics.
In our exercise with the negative binomial distribution, probability theory guides us in calculating the probability of various outcomes occurring within a certain number of trials. This is informed by the properties of random variables and their derived functions such as the MGF.
This distribution is particularly relevant when assessing the number of failures before a series of successes occur, a concept smoothly expounded through probability tools.
Using probability theory, we are not only able to compute quantities like means and variances but also test their consistency with initial assumptions and logical outcomes.
The beauty of probability theory lies in its ability to take seemingly unpredictable events and endow them with a probabilistic structure, letting us forecast and appraise the likelihood of various events systematically.

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Most popular questions from this chapter

Suppose that trees are distributed in a forest according to a two-dimensional Poisson process with parameter \(\alpha\), the expected number of trees per acre, equal to 80 . a. What is the probability that in a certain quarter-acre plot, there will be at most 16 trees? b. If the forest covers 85,000 acres, what is the expected number of trees in the forest? c. Suppose you select a point in the forest and construct a circle of radius \(1 \mathrm{mile}\). Let \(X=\) the number of trees within that circular region. What is the pmf of \(X\) ? [Hint: 1 sq mile \(=640\) acres.]

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