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The number of requests for assistance received by a towing service is a Poisson process with rate \(\alpha=4 / \mathrm{h}\). a. Compute the probability that exactly ten requests are received during a particular 2-h period. b. If the operators of the towing service take a \(30-\) min break for lunch, what is the probability that they do not miss any calls for assistance? c. How many calls would you expect during their break?

Short Answer

Expert verified
a. Probability of 10 requests is 0.0993. b. Probability of no calls during break is 0.1353. c. Expect 2 calls during the break.

Step by step solution

01

Determine Relevant Parameters for Part a

The problem gives us a Poisson process with a rate of \(\alpha = 4/\mathrm{h}\). For a 2-hour period, the rate becomes:\[\lambda = 4 \times 2 = 8.\]We are asked to find the probability of exactly 10 requests, which means \(k = 10\).
02

Use the Poisson Probability Formula

For a Poisson random variable, the probability of \(k\) events is given by:\[ P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}.\]Substituting \(\lambda = 8\) and \(k = 10\), we have:\[ P(X = 10) = \frac{e^{-8} \times 8^{10}}{10!}.\]
03

Perform the Calculation for Part a

Now we compute:\[ P(X = 10) = \frac{e^{-8} \times 1073741824}{3628800}.\]Using a calculator, this results in approximately 0.0993.
04

Determine Parameters for Part b and c

For a 30-minute break, the time period is \(0.5\) hours. Therefore, the expected number of calls \(\lambda_b\) during the break is:\[ \lambda_b = 4 \times 0.5 = 2. \]
05

Calculate Probability for Part b

We need the probability of receiving no calls during the 30-minute break. This is equivalent to \(k = 0\) in a Poisson process, which is calculated as:\[ P(X = 0) = \frac{e^{-\lambda_b} \times \lambda_b^0}{0!} = e^{-2}.\]Calculating this gives approximately 0.1353.
06

Expectation for Calls in Part c

The expected number of calls during the 30-minute break is simply the rate \(\lambda_b\), which we calculated as 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculations
Probability calculations are a fundamental part of understanding how likely an event is to occur within a given context. In the exercise, we looked at towing service requests and calculated different probabilities.

The main tool for performing these calculations is the Poisson probability formula. This formula provides us with a systematic way to determine the probability of a specific number of events happening.
  • The formula is: \( P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!} \).
  • Here, \( k \) represents the number of times an event occurs, \( e \) is the base of the natural logarithm (approximately equal to 2.718), and \( \lambda \) is the rate of occurrence.
By substituting the given rate and desired number of events into this formula, we can precisely find probabilities such as getting exactly 10 calls in a 2-hour window. It is very useful to understand these calculations as they can apply to diverse real-world problems.
Poisson Distribution
The Poisson distribution is a probability distribution that describes the likelihood that a certain number of events will happen within a fixed time interval or spatial area. This distribution is particularly helpful when dealing with rare events that occur independently.

In the example with the towing service, the Poisson process helps determine the number of calls made within different time spans (like 2 hours or 30 minutes). The key characteristic of a Poisson process is that it is defined by a rate or mean number of events.
  • For the towing service, the rate is \( \alpha = 4/\mathrm{h} \).
  • This means, on average, 4 requests are made every hour.
Applying the Poisson distribution allows us to calculate probabilities for varying numbers of requests in any given time period. This is why we see different formulas applied for the 2-hour period compared to a 30-minute break.
Expected Value
The expected value is a concept from probability theory that gives us a way to predict the average outcome of a random process over long periods. It tells us what we should "expect" to see under normal conditions if the random process is repeated many times.

In the context of the towing service, the expected number of calls during a break gives the value that statistically, we can anticipate.
  • During the 30-minute (0.5-hour) break, the expected calls \( \lambda_b \) is calculated to be 2.
This is achieved through multiplying the rate of occurrences per hour by the number of hours (i.e., \( 4 \times 0.5 \) results in \( 2 \)). Understanding expected value is crucial as it allows businesses and services to plan and allocate resources efficiently, preparing appropriately for typical conditions.
Probability Theory
Probability theory is the mathematical framework that underpins the study of uncertain events. It helps us quantify and predict randomness and variability in a methodical way.

This broad field is essential in understanding and applying models like the Poisson distribution for real-world scenarios. In the exercise, probability theory forms the backbone of analyzing how many calls a towing service would receive.
  • It allows us to find probabilities of exact counts and even consider scenarios like taking an interruption period (e.g., lunch break) into account.
  • More generally, it helps in considering events occurring independently of one another.
As probability theory is deeply entwined with the principles used in this exercise, familiarity with its core ideas can greatly enhance the practical interpretation and application of statistical data.

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