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Let \(X\) be a binomial random variable with fixed \(n\). a. Are there values of \(p(0 \leq p \leq 1)\) for which \(V(X)=0\) ? Explain why this is so. b. For what value of \(p\) is \(V(X)\) maximized? [Hint: Either graph \(V(X)\) as a function of \(p\) or else take a derivative.]

Short Answer

Expert verified
a. Yes, for \( p = 0 \) or \( p = 1 \), \( V(X) = 0 \). b. \( V(X) \) is maximized at \( p = \frac{1}{2} \).

Step by step solution

01

Understand Variance of Binomial Distribution

The variance of a binomial distribution is given by the formula \( V(X) = np(1-p) \), where \( n \) is the number of trials and \( p \) is the probability of success in each trial. We need to analyze this variance to address the questions.
02

Analyze Conditions for Zero Variance

For \( V(X) = 0 \), the expression \( np(1-p) = 0 \) must be true. Since \( n \) is fixed and positive, this implies \( p(1-p) = 0 \). This equation holds when \( p = 0 \) or \( p = 1 \). Hence, for these values of \( p \), the variance \( V(X) \) is zero because there's no variability in the outcome - all results are failures or successes, respectively.
03

Set Up for Maximizing Variance

We want to find the value of \( p \) that maximizes \( V(X) = np(1-p) \). This requires differentiating \( np(1-p) \) with respect to \( p \) and finding its critical points by setting the derivative to zero.
04

Take the Derivative of the Variance

Differentiate \( V(X) = np(1-p) \) with respect to \( p \). The derivative is \( \frac{d}{dp} np(1-p) = n(1 - 2p) \). Set this derivative equal to zero to find critical points: \( n(1 - 2p) = 0 \). This implies that \( 1 - 2p = 0 \) or \( p = \frac{1}{2} \).
05

Verify if Critical Point is Maximum

Since \( 0 < p < 1 \), the second derivative test can be applied. Derivative of \( n(1 - 2p) \) yields \( -2n \), which is always negative, indicating a maximum. Thus, \( p = \frac{1}{2} \) is the value for which \( V(X) \) is maximized.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Random Variable
A binomial random variable is a type of discrete random variable that arises when we perform n independent success-failure experiments, commonly referred to as 'trials'. In each trial, there are two possible outcomes—success or failure. The number of successes in these n trials is modeled using a binomial random variable, typically denoted by \( X \). To fully define a binomial random variable, we need to know:
  • The number of trials, \( n \)
  • The probability of success in each trial, \( p \)
Each trial is assumed to have the same probability of success. This fixed probability makes the binomial distribution distinct and predictable. Understanding the conditions under which these define a variable helps in using binomial random variables in various statistical applications, such as quality control and survival analysis.
Probability of Success
The probability of success, denoted as \( p \), is a crucial parameter in the context of binomial distributions. It represents the likelihood of a single trial being successful. Distinguishing the probability of success is vitally important because it determines the distribution's shape and spread.For example:
  • If \( p = 0 \), it means that every trial will result in failure.
  • If \( p = 1 \), every trial will be a success.
  • If \( 0 < p < 1 \), there is a mix of successes and failures across trials.
Especially true for values of \( p \) where the outcomes are not deterministic (i.e., \( 0 < p < 1 \)) is the variability, or spread of results, which can be analyzed further using variance. Hence, identifying the correct \( p \) gives insights into the nature of risk and variability in statistical modeling.
Critical Points Calculation
Critical point calculation is essential when we want to identify when functions reach their maximum or minimum values. For a binomial variance \( V(X) = np(1-p) \), the goal might be to determine the probability \( p \) at which this variance is maximized.To pinpoint this, one must:
  • Take the derivative of the variance function with respect to \( p \): \( \frac{d}{dp} np(1-p) = n(1 - 2p) \).
  • Set the derivative equal to zero, \( n(1 - 2p) = 0 \), to find critical points.
  • This results in \( 1 - 2p = 0 \), leading to \( p = \frac{1}{2} \).
This approach aids in determining the specific probability value that might result in maximum variance, providing deeper insight into the distribution's behavior.
Maximizing Variance
When analyzing the variance within a binomial distribution, a common question might be to determine for which probability of success \( p \) the variance is maximized. As discussed, variance is represented by \( V(X) = np(1-p) \).Determining Maximizing Points
  • Differentiation: We first differentiate \( V(X) \) to find a critical point: \( \frac{d}{dp} np(1-p) = n(1 - 2p) \).
  • Solving: Setting the derivative to zero gives us \( p = \frac{1}{2} \), indicating where the function potentially reaches a maximum.
  • Verification: The second derivative test confirms this point is a maximum since the second derivative, \( -2n \), is negative, indicating a concave down curve.
By establishing \( p = \frac{1}{2} \), maximum variance is achieved. This is a vital insight for understanding the nature of a binomial spread, emphasizing that when outcomes are highly varied across all trials, such variance is maximized. This theory helps in diverse applications ranging from economics to natural sciences.

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