Chapter 3: Problem 72
Let \(X\) be a binomial random variable with fixed \(n\). a. Are there values of \(p(0 \leq p \leq 1)\) for which \(V(X)=0\) ? Explain why this is so. b. For what value of \(p\) is \(V(X)\) maximized? [Hint: Either graph \(V(X)\) as a function of \(p\) or else take a derivative.]
Short Answer
Expert verified
a. Yes, for \( p = 0 \) or \( p = 1 \), \( V(X) = 0 \). b. \( V(X) \) is maximized at \( p = \frac{1}{2} \).
Step by step solution
01
Understand Variance of Binomial Distribution
The variance of a binomial distribution is given by the formula \( V(X) = np(1-p) \), where \( n \) is the number of trials and \( p \) is the probability of success in each trial. We need to analyze this variance to address the questions.
02
Analyze Conditions for Zero Variance
For \( V(X) = 0 \), the expression \( np(1-p) = 0 \) must be true. Since \( n \) is fixed and positive, this implies \( p(1-p) = 0 \). This equation holds when \( p = 0 \) or \( p = 1 \). Hence, for these values of \( p \), the variance \( V(X) \) is zero because there's no variability in the outcome - all results are failures or successes, respectively.
03
Set Up for Maximizing Variance
We want to find the value of \( p \) that maximizes \( V(X) = np(1-p) \). This requires differentiating \( np(1-p) \) with respect to \( p \) and finding its critical points by setting the derivative to zero.
04
Take the Derivative of the Variance
Differentiate \( V(X) = np(1-p) \) with respect to \( p \). The derivative is \( \frac{d}{dp} np(1-p) = n(1 - 2p) \). Set this derivative equal to zero to find critical points: \( n(1 - 2p) = 0 \). This implies that \( 1 - 2p = 0 \) or \( p = \frac{1}{2} \).
05
Verify if Critical Point is Maximum
Since \( 0 < p < 1 \), the second derivative test can be applied. Derivative of \( n(1 - 2p) \) yields \( -2n \), which is always negative, indicating a maximum. Thus, \( p = \frac{1}{2} \) is the value for which \( V(X) \) is maximized.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Random Variable
A binomial random variable is a type of discrete random variable that arises when we perform n independent success-failure experiments, commonly referred to as 'trials'. In each trial, there are two possible outcomes—success or failure. The number of successes in these n trials is modeled using a binomial random variable, typically denoted by \( X \). To fully define a binomial random variable, we need to know:
- The number of trials, \( n \)
- The probability of success in each trial, \( p \)
Probability of Success
The probability of success, denoted as \( p \), is a crucial parameter in the context of binomial distributions. It represents the likelihood of a single trial being successful. Distinguishing the probability of success is vitally important because it determines the distribution's shape and spread.For example:
- If \( p = 0 \), it means that every trial will result in failure.
- If \( p = 1 \), every trial will be a success.
- If \( 0 < p < 1 \), there is a mix of successes and failures across trials.
Critical Points Calculation
Critical point calculation is essential when we want to identify when functions reach their maximum or minimum values. For a binomial variance \( V(X) = np(1-p) \), the goal might be to determine the probability \( p \) at which this variance is maximized.To pinpoint this, one must:
- Take the derivative of the variance function with respect to \( p \): \( \frac{d}{dp} np(1-p) = n(1 - 2p) \).
- Set the derivative equal to zero, \( n(1 - 2p) = 0 \), to find critical points.
- This results in \( 1 - 2p = 0 \), leading to \( p = \frac{1}{2} \).
Maximizing Variance
When analyzing the variance within a binomial distribution, a common question might be to determine for which probability of success \( p \) the variance is maximized. As discussed, variance is represented by \( V(X) = np(1-p) \).Determining Maximizing Points
- Differentiation: We first differentiate \( V(X) \) to find a critical point: \( \frac{d}{dp} np(1-p) = n(1 - 2p) \).
- Solving: Setting the derivative to zero gives us \( p = \frac{1}{2} \), indicating where the function potentially reaches a maximum.
- Verification: The second derivative test confirms this point is a maximum since the second derivative, \( -2n \), is negative, indicating a concave down curve.