/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 Let \(X\) be the number of point... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(X\) be the number of points earned by a randomly selected student on a 10 point quiz, with possible values \(0,1,2, \ldots, 10\) and pmf \(p(x)\), and suppose the distribution has a skewness of \(c\). Now consider reversing the probabilities in the distribution, so that \(p(0)\) is interchanged with \(p(10)\), \(p(1)\) is interchanged with \(p(9)\), and so on. Show that the skewness of the resulting distribution is \(-c\). [Hint: Let \(Y=10-X\) and show that \(Y\) has the reversed distribution. Use this fact to determine \(\mu_{Y}\) and then the value of skewness for the \(Y\) distribution.]

Short Answer

Expert verified
The skewness of the reversed distribution is \(-c\).

Step by step solution

01

Define Random Variable for Reversed Distribution

Define a new random variable \( Y = 10 - X \) to represent the reversed probability distribution. This step essentially mirrors the distribution, switching \( p(x) \) with \( p(10 - x) \).
02

Determine the Probability Mass Function of Y

Since \( Y = 10 - X \), the probability mass function of \( Y \) becomes \( p_Y(y) = p_X(10 - y) \). This shows that \( Y \) has the mirrored distribution of \( X \).
03

Calculate Mean \( \mu_Y \) for Reversed Distribution

The expectation \( E[Y] = E[10 - X] = 10 - E[X] = 10 - \mu_X \), where \( \mu_X \) is the mean of \( X \). Therefore, \( \mu_Y = 10 - \mu_X \).
04

Find Variance of \( Y \)

The variance is unchanged under linear transformation when the transformation involves a subtraction and this mirrors, so \( \sigma_Y^2 = \sigma_X^2 \).
05

Calculate the Skewness of \( Y \)

The skewness \( \gamma_X \) of a distribution is defined as \( \frac{E[(X-\mu_X)^3]}{\sigma_X^3} = c \). For \( Y \), which is \( 10 - X \), the skewness is \( \gamma_Y = -\gamma_X = -c \). This negative sign emerges because reversing the distribution essentially flips the contribution to skewness points about the center.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Skewness
Skewness is a measure of the asymmetry in a probability distribution. When we talk about skewness, we often refer to how the tails of a distribution are behaving. If the tail on the right side of the distribution is longer or fatter, it’s called "positive skewness." Conversely, if the tail on the left is longer or fatter, it's known as "negative skewness." This concept helps us understand where the majority of data points lie and how much the distribution deviates from a symmetrical bell curve.
In the context of the exercise, changing skewness relates to flipping the distribution. By reversing the distribution of scores a student might earn on a quiz, skewness changes from positive to negative or vice versa. This happens because the contributions to skewness are mirrored, effectively flipping the distribution and changing the sign.
Random Variable
A random variable is a variable whose possible values represent outcomes of a random phenomenon. Random variables can be discrete, representing countable outcomes like the roll of a dice, or continuous, representing data that can take any value within a range.
In the given exercise, the random variable is denoted as \(X\), representing the score a student earns on a quiz. The possible values for \(X\) range from 0 to 10, indicating this is a discrete random variable.
To understand the problem, we redefine it as another random variable \(Y = 10 - X\). This new variable \(Y\) effectively reverses the original distribution, helping us calculate various statistical measures such as mean and skewness.
Probability Mass Function
The Probability Mass Function (PMF) provides the probability that a discrete random variable is exactly equal to a certain value. It's a fundamental concept in probability, especially useful for discrete random variables.
In our exercise, the PMF of the random variable \(X\) is denoted by \(p(x)\). It gives the probabilities of each score a student can achieve on a quiz. When we define the reversed distribution through \(Y = 10 - X\), the PMF alters to \(p_Y(y) = p_X(10 - y)\).
This shows us how reversing the scores also reverses their probabilities, making it essential for comparing skewness between \(X\) and \(Y\). Understanding PMF allows us to calculate further statistical measurements needed to understand the behavior of the distribution.
Variance
Variance is an important statistical measure showing how data points in a dataset are spread out. It tells us how much the values differ from the mean and from each other.
In terms of formulas, variance is expressed as \( \sigma^2 \) and calculated by finding the average of the squared deviations from the mean.
The exercise makes sure to highlight that variance remains unchanged when reversing a distribution via a symmetrical transformation. When we move from \(X\) to \(Y = 10 - X\), the variance \( \sigma_Y^2 \) remains equal to \( \sigma_X^2 \). This consistency is crucial to understanding that while position-based measures such as the mean and skewness may alter, variance stays constant under certain symmetrical data transformations.

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Most popular questions from this chapter

The College Board reports that \(2 \%\) of the two million high school students who take the SAT each year receive special accommodations because of documented disabilities (Los Angeles Times, July 16,2002 ). Consider a random sample of 25 students who have recently taken the test. a. What is the probability that exactly 1 received a special accommodation? b. What is the probability that at least 1 received a special accommodation? c. What is the probability that at least 2 received a special aocommodation? d. What is the probability that the number among the 25 who received a special accommodation is within 2 standard deviations of the number you would expect to be accommodated? e. Suppose that a student who does not receive a special accommodation is allowed \(3 \mathrm{~h}\) for the exam, whereas an accommodated student is allowed \(4.5 \mathrm{~h}\). What would you expect the average time allowed the 25 selected students to be?

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