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The College Board reports that \(2 \%\) of the two million high school students who take the SAT each year receive special accommodations because of documented disabilities (Los Angeles Times, July 16,2002 ). Consider a random sample of 25 students who have recently taken the test. a. What is the probability that exactly 1 received a special accommodation? b. What is the probability that at least 1 received a special accommodation? c. What is the probability that at least 2 received a special aocommodation? d. What is the probability that the number among the 25 who received a special accommodation is within 2 standard deviations of the number you would expect to be accommodated? e. Suppose that a student who does not receive a special accommodation is allowed \(3 \mathrm{~h}\) for the exam, whereas an accommodated student is allowed \(4.5 \mathrm{~h}\). What would you expect the average time allowed the 25 selected students to be?

Short Answer

Expert verified
(a) P(X = 1) = 0.265; (b) P(X ≥ 1) = 0.393; (c) P(X ≥ 2) = 0.128; (d) Use normal approximation; (e) Average time = 3.03 hours.

Step by step solution

01

Define the Probability Distribution

Since we are dealing with a small probability and a situation that occurs in a fixed number of trials (25 students), this problem follows the binomial distribution. Let X be the number of students who receive special accommodations. X ~ Binomial(n=25, p=0.02), where n is the number of trials (students) and p is the probability of success (receiving accommodations).
02

Calculate P(X = 1)

For part (a), we need to find the probability that exactly 1 student received a special accommodation using the binomial probability formula:\[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]Substitute n = 25, k = 1, and p = 0.02:\[P(X = 1) = \binom{25}{1} (0.02)^1 (0.98)^{24}\]\[P(X = 1) = 25 \times 0.02 \times 0.98^{24}\]Calculate the final result.
03

Calculate P(X ≥ 1)

For part (b), we need to use the complement rule. First find the probability of P(X = 0), then use:\[P(X \geq 1) = 1 - P(X = 0)\]Calculate P(X = 0):\[P(X = 0) = \binom{25}{0} (0.02)^0 (0.98)^{25}\]\[P(X = 0) = 0.98^{25}\]Then, calculate \( P(X \geq 1) \).
04

Calculate P(X ≥ 2)

For part (c), similarly use the complement rule:\[P(X \geq 2) = 1 - P(X = 0) - P(X = 1)\]Utilize the results from Steps 2 and 3 to get the final value.
05

Calculate the Expected Value and Standard Deviation

The expected value \(E(X)\) for a binomial distribution is given by \(n \, p\).\[E(X) = 25 \times 0.02 = 0.5\]The standard deviation \( \sigma \) is computed by:\[\sigma = \sqrt{n \, p \, (1 - p)} = \sqrt{25 \times 0.02 \times 0.98}\]Calculate \( \sigma \).
06

Calculate Probability Within 2 Standard Deviations

For part (d), find the range: \( E(X) \pm 2 \sigma \). Use normal approximation since n is not large. Calculate \( P(0 \leq X \leq 1) \) when \( 0 \leq 1 \leq X \leq 1 \).
07

Calculate the Average Time Allowed

In part (e), calculate the average time using the expected number of accommodations:One unaccommodated takes 3 hours, and accommodated takes 4.5 hours. Expected accommodation is 0.5. Thus, calculating average time:\[\text{Average time} = E(X) \, \times 4.5 + (25 - E(X)) \, \times 3\]Solve for average time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
The concept of probability is crucial in understanding how likely an event is to occur. In this binomial distribution scenario, we can calculate the probability of different outcomes. - **Binomial Probability Formula**: To calculate the probability of exactly 1 student receiving special accommodations, we use the binomial formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] Here, \( n \) is the number of trials, \( k \) is the number of successes, and \( p \) is the probability of success. For \( k = 1 \), \( n = 25 \), and \( p = 0.02 \), we substitute these values into the formula to find the probability.
- **Complement Rule**: To find the probability of at least one student receiving accommodations, \( P(X \geq 1) \), we calculate the opposite event (no students receiving accommodations) first. Then: \[ P(X \geq 1) = 1 - P(X = 0) \] - Applying these steps helps us determine how the number of students receiving accommodations is spread across different possibilities.
Expected Value
The expected value in binomial distribution provides the mean or average outcome of a random variable over numerous trials. It tells us what we can "expect" on average when the process is repeated many times. - **Expected Value Formula**: For a binomial distribution, the expected value \( E(X) \) is calculated as: \[ E(X) = n \cdot p \] This formula relies on the number of trials (\( n = 25 \)) and the probability of success (\( p = 0.02 \)). By multiplying these, we estimate that 0.5 students out of 25 typically receive special accommodations.
- **Implications**: The expected value gives a central point around which the distribution of outcomes is centered. It's a theoretical average that predicts the number of successful outcomes in the long run. For this example, with 25 trials and a low probability, fewer than one student is expected to receive accommodations per sample.
Standard Deviation
Standard deviation is an important statistical concept that measures the spread or dispersion of a set of values. In the context of a binomial distribution, it quantifies how much the number of successes deviates from the expected value.- **Calculating Standard Deviation**: The formula for standard deviation \( \sigma \) in a binomial distribution is: \[ \sigma = \sqrt{n \cdot p \cdot (1 - p)} \] Using \( n = 25 \) and \( p = 0.02 \), we substitute these into the formula to obtain \( \sigma \). This provides insight into the variability of our data.
- **Interpretation**: A small standard deviation indicates that most outcomes are close to the expected value, while a larger standard deviation shows more variation. This means how likely the number of accommodations is to deviate from what is expected based on the probability and trials.
Probability Theory
Probability theory is a branch of mathematics that deals with calculating the likelihood of various outcomes. It provides foundational tools for understanding variability, expectation, and distribution of random processes. - **Basic Concepts**: In probability theory, binomial distributions model the number of successes in a sequence of independent trials, each with the same probability of success. This framework helps in setting up and solving problems like the SAT accommodations scenario.
- **Applications**: Probability theory is vital in making predictions and understanding data trends across numerous fields, from game outcomes to econometrics. By applying these principles, we can model real-world processes, analyze risks, and make informed decisions based on potential outcomes.
- **Broader Understanding**: Probability helps us go beyond intuitive guessing and ensures more scientific approaches to problem-solving and risk management. For students, mastering these concepts opens doors to various statistical and analytical pursuits.

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