/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Wear resistance of certain nucle... [FREE SOLUTION] | 91Ó°ÊÓ

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Wear resistance of certain nuclear reactor components made of Zircaloy-2 is partly determined by properties of the oxide layer. The following data appears in an article that proposed a new nondestructive testing method to monitor thickness of the layer ("Monitoring of Oxide Layer Thickness on Zircaloy-2 by the Eddy Current Test Method," J. Test. Eval., 1987: 333-336). The variables are \(x=\) oxide-layer thickness \((\mu \mathrm{m})\) and \(y=\) eddycurrent response (arbitrary units). $$ \begin{array}{l|ccccc} x & 0 & 7 & 17 & 114 & 133 \\ \hline y & 20.3 & 19.8 & 19.5 & 15.9 & 15.1 \\ x & 142 & 190 & 218 & 237 & 285 \\ \hline y & 14.7 & 11.9 & 11.5 & 8.3 & 6.6 \end{array} $$ a. The authors summarized the relationship by giving the equation of the least squares line as \(y=20.6-.047 x\). Calculate and plot the residuals against \(x\) and then comment on the appropriateness of the simple linear regression model. b. Use \(s=.7921\) to calculate the standardized residuals from a simple linear regression. Construct a standardized residual plot and comment. Also construct a normal probability plot and comment.

Short Answer

Expert verified
Calculate residuals using given regression, check residual plots for patterns. Standardized residual plot and normal probability plot help evaluate model fit.

Step by step solution

01

Understanding the Given Equation

The equation of the least squares line provided by the authors is \(y = 20.6 - 0.047x\). This equation represents the expected (predicted) relationship between \(x\), the oxide-layer thickness, and \(y\), the eddy current response.
02

Calculate Predicted y-values

For each \(x\) value, we use the equation \(y = 20.6 - 0.047x\) to calculate the predicted \(y\) values. For example, when \(x = 0\), the predicted \(y\) is \(20.6 - 0.047 imes 0 = 20.6\). Repeat this calculation for all \(x\) values.
03

Compute Residuals

Residuals are the differences between the observed \(y\) values and the predicted \(y\) values. For each data point, calculate the residual as \( y_{residual} = y_{observed} - y_{predicted} \).
04

Plot Residuals vs. x

Create a scatter plot of the residuals against the \(x\) values. This plot should help determine if there is a pattern in the residuals, which would indicate non-linearity in the relationship between \(x\) and \(y\). A random pattern suggests the model is appropriate.
05

Calculate Standardized Residuals

Standardized residuals are calculated by dividing each residual by the given standard error, \(s = 0.7921\). Use the formula \(z_{i} = \frac{y_{residual, i}}{s}\) for each residual.
06

Plot Standardized Residuals vs. x

Create a plot of standardized residuals against the \(x\) values. Look for any trends or patterns; ideally, the standardized residuals should be randomly scattered around 0.
07

Construct a Normal Probability Plot

A normal probability plot (or Q-Q plot) plots the standardized residuals against the expected quantiles of the normal distribution. If the points roughly follow a straight line, this suggests the residuals are normally distributed.
08

Conclusion: Comment on Model Appropriateness

Assess the residual plots and normal probability plot: If the residual plots show no clear pattern and the normal probability plot is linear, the linear regression model is appropriate. Otherwise, consider model improvements.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Residual Analysis
Residual analysis is a crucial tool in determining the effectiveness of a simple linear regression model. Residuals are essentially the errors between the observed values and the values predicted by the regression model. To compute a residual, you subtract the predicted value from the observed value:
  • If the residuals are close to zero, the predicted values accurately represent the actual data.
  • Residuals indicate how well your model fits the actual data points.
Plotting these residuals against the independent variable (\(x\)) can unveil patterns or non-linearity. It's important to look for randomness in this plot. A scattered residual plot with no discernible pattern suggests a suitable linear model. However, if a pattern appears, this may suggest that a more complex model is needed. Through residual analysis, you can critically evaluate if the linear model appropriately captures the relationship between variables or if adjustments should be considered for model accuracy.
Least Squares Line
The least squares line is a fundamental concept in linear regression, used to predict the relationship between two variables. It is often referred to as the line of best fit. The idea is to minimize the sum of the squares of the differences (the "errors") between observed values and the values predicted by the linear equation. In the given exercise, the equation is provided as \(y = 20.6 - 0.047x\). This equation implies:
  • For each unit increase in the oxide-layer thickness (\(x\)), the expected value of the eddy current response (\(y\)) decreases by 0.047 units.
  • A constant term of 20.6 represents the \(y\)-intercept, indicating the starting point when \(x = 0\).
Using this line, predictions for \(y\) can be efficiently made for any given \(x\) value. The least squares method ensures that the estimated line minimizes the error in the data, providing the best linear approximation to the observed data. This property makes it an indispensable tool in regression analysis.
Standardized Residuals
Standardized residuals are an essential concept in regression analysis to adjust and scale residuals. They are derived by dividing each residual by the standard error, which normalizes the data by accounting for variability. The formula is:\[z_i = \frac{y_{residual, i}}{s}\] where \(s\) is the given standard error.Standardized residuals allow you to compare residuals on the same scale:
  • A standardized residual near zero indicates a good fit near the mean, close to what the model predicts.
  • Larger standardized residuals suggest a poor fit and potential outliers.
By plotting standardized residuals against \(x\), you can identify any inconsistencies or possible patterns not apparent from the original residuals. Maintaining a random scatter around zero within the plot is ideal. If standardized residuals deviate significantly, it suggests a review of the model may be required, potentially revealing areas where the model does not fit well.
Normal Probability Plot
A normal probability plot, or Q-Q plot, is used to verify the assumption that residuals follow a normal distribution. This plot compares the standardized residuals against expected quantiles of a normal distribution. Creating a normal probability plot involves:
  • Plotting the standardized residuals on the y-axis.
  • The expected normal quantiles on the x-axis.
The purpose is to check for normality:
  • If the points approximately form a straight line, the residuals are likely normally distributed.
  • Deviations from a straight line suggest that the residuals might not be normally distributed.
A normal probability plot is an effective diagnostic tool in regression analysis, identifying departures from normality that can impact model validity. Confirming normality through this plot asserts that the statistical model assumptions hold, enhancing reliability in model predictions.

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Most popular questions from this chapter

The article "Increases in Steroid Binding Globulins Induced by Tamoxifen in Patients with Carcinoma of the Breast" \((J\). Endocrinol., 1978: 219-226) reports data on the effects of the drug tamoxifen on change in the level of cortisol-binding globulin (CBG) of patients during treatment. With age \(=x\) and \(\Delta \mathrm{CBG}=y\), summary values are \(n=26, \sum x_{i}=1613, \sum\left(x_{i}-\bar{x}\right)^{2}=3756.96\), \(\sum y_{i}=281.9, \quad \sum\left(y_{i}-\bar{y}\right)^{2}=465.34, \quad\) and \(\sum x_{i} y_{i}=16,731\) a. Compute a \(90 \%\) CI for the true correlation coefficient \(\rho\). b. Test \(H_{0}: \rho=-.5\) versus \(H_{\mathrm{a}}: \rho<-.5\) at level \(.05\). c. In a regression analysis of \(y\) on \(x\), what proportion of variation in change of cortisol-binding globulin level could be explained by variation in patient age within the sample? d. If you decide to perform a regression analysis with age as the dependent variable, what proportion of variation in age is explainable by variation in \(\triangle \mathrm{CBG}\) ?

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