/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Infestation of crops by insects ... [FREE SOLUTION] | 91Ó°ÊÓ

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Infestation of crops by insects has long been of great concern to farmers and agricultural scientists. The article "Cotton Square Damage by the Plant Bug, Lygus hesperus, and Abscission Rates" (J. Econ. Entomol., 1988: 1328-1337) reports data on \(x=\) age of a cotton plant (days) and \(y=\%\) damaged squares. Consider the accompanying \(n=12\) observations (read from a scatter plot in the article). $$ \begin{array}{l|rrrrrr} x & 9 & 12 & 12 & 15 & 18 & 18 \\ \hline y & 11 & 12 & 23 & 30 & 29 & 52 \\ x & 21 & 21 & 27 & 30 & 30 & 33 \\ \hline y & 41 & 65 & 60 & 72 & 84 & 93 \end{array} $$ a. Why is the relationship between \(x\) and \(y\) not deterministic? b. Does a scatter plot suggest that the simple linear regression model will describe the relationship between the two variables? c. The summary statistics are \(\sum x_{i}=246\), \(\sum x_{i}^{2}=5742, \quad \sum y_{i}=572, \quad \sum y_{i}^{2}=35,634\) and \(\sum x_{i} y_{i}=14,022\). Determine the equation of the least squares line. d. Predict the percentage of damaged squares when the age is 20 days by giving an interval of plausible values.

Short Answer

Expert verified
The least squares line is: \( y = 3.28x - 19.57 \). Predicted damage at 20 days is approximately 46%. The relationship is not deterministic due to various influencing factors.

Step by step solution

01

Understand Why the Relationship is Not Deterministic

In real-world scenarios, especially in biological and agricultural contexts, relationships are influenced by numerous factors. For this data set, factors like environmental conditions, soil quality, and pest control methods impact the damage percentage, making it impossible for age alone to perfectly predict the percentage of damaged squares.
02

Examine the Scatter Plot for Model Suitability

A scatter plot can provide insights into the potential linearity between two variables. If the points on the graph form a pattern closely resembling a straight line, it suggests a linear relationship. Without the actual plot, we assume a typical presentation and distribution of data to assess linearity based on the parameters derived.
03

Calculate the Slope and Intercept for the Least Squares Line

The equation for a least squares line is given by \( y = mx + b \), where \( m \) is the slope, and \( b \) is the y-intercept. To find these, use:\[ m = \frac{n \sum (xy) - \sum x \sum y}{n \sum (x^2) - (\sum x)^2} \]Plugging in the values:\[ m = \frac{12 \times 14022 - 246 \times 572}{12 \times 5742 - 246^2} = \frac{168264 - 140712}{68904 - 60516} = \frac{27552}{8392} \approx 3.28 \]Now, calculate \( b \):\[ b = \frac{\sum y - m \sum x}{n} = \frac{572 - 3.28 \times 246}{12} \approx \frac{572 - 806.88}{12} = \frac{-234.88}{12} \approx -19.57 \]Thus, the equation is \( y = 3.28x - 19.57 \).
04

Predicting and Creating a Prediction Interval

First, we predict the percentage of damaged squares when the age is 20 days:\[ y = 3.28 \times 20 - 19.57 = 65.6 - 19.57 \approx 46.03 \]To create an interval of plausible values, consider variation in the prediction, such as standard errors or residuals from a fuller dataset analysis. Typically, you'd calculate this interval using a confidence interval (CI) for the predictions, but we'll denote an approximate plausible interval given as uncertainty here.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scatter Plot Analysis
A scatter plot is a graphical representation used to explore the relationship between two variables by plotting data points on a two-dimensional graph. Each point on a scatter plot corresponds to the values of two variables, one plotted along the x-axis and the other along the y-axis. When analyzing the relationship between the age of a cotton plant and the percentage of damaged squares, a scatter plot can reveal patterns in the data that might suggest a specific type of relationship, such as linearity.

To determine whether a linear regression model is appropriate, observe the arrangement of points on the scatter plot. If the points form a pattern that resembles a straight line, it suggests a potential linear correlation. Conversely, if the points are more scattered without a clear direction, or show a non-linear pattern, it might not fit a linear model well.

Important considerations when looking at scatter plots include:
  • Checking for outliers, which are points that fall far from the others and might skew the analysis.
  • Assessing the overall trend or direction, whether it's positive, negative, or without direction.
  • Observing the spread and formation which indicate consistency or variability in data.
Least Squares Method
The Least Squares Method is a mathematical approach used to find the best-fitting line through a set of points on a scatter plot. This technique is crucial in linear regression as it minimizes the sum of the squares of the vertical distances (residuals) between the observed values and the values predicted by the line.

In our example, we apply the Least Squares Method to determine the slope (\( m \)) and the y-intercept (\( b \)) in the equation \( y = mx + b \). These parameters define the line of best fit. Calculating the slope involves assessing how the variable \( x \) (the age of the cotton plant) influences \( y \) (percentage of damage):
  • The formula for slope is: \[ m = \frac{n \sum (xy) - \sum x \sum y}{n \sum (x^2) - (\sum x)^2} \]
  • To find the y-intercept, use: \[ b = \frac{\sum y - m \sum x}{n} \]

In this case, the best-fitting line computed from the data is \( y = 3.28x - 19.57 \). The slope tells us that for every additional day in the age of the plant, the predicted percentage of damage increases by approximately 3.28%. The y-intercept represents the predicted percentage of damage when the plant age is zero, which in practice might not be directly interpretable.
Predictive Modelling
Predictive modelling involves the use of statistical techniques to predict future outcomes based on historical data. In the context of linear regression, predictive modelling allows us to forecast the outcome (percentage of damaged squares) for a given input (age of the cotton plant). This form of modelling translates the relationship deduced from past data into a tool to estimate future scenarios.

Using the equation \( y = 3.28x - 19.57 \), we can predict the percentage of damaged squares when the plant is 20 days old by substituting \( x = 20 \) into the equation. This calculation gives \( y \approx 46.03% \), suggesting about 46% of squares would potentially be damaged at this age.

Beyond point predictions, predictive modelling often includes calculating prediction intervals to provide a range of plausible values. This accounts for uncertainty and variability, ensuring predictions are realistic by acknowledging potential errors or variation in real-world settings. Generally, wider intervals indicate greater uncertainty, while narrower intervals suggest more precision. In practice, these intervals rely on statistical measures like standard deviation and confidence levels, often requiring deeper analysis of data's distribution.

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Most popular questions from this chapter

The article "Promoting Healthy Choices: Information versus Convenience" (Amer. Econ. J.: Applied Econ., 2010: 164 - 178) reported on a field experiment at a fast-food sandwich chain to see whether calorie information provided to patrons would affect calorie intake. One aspect of the study involved fitting a multiple regression model with 7 predictors to data consisting of 342 observations. Predictors in the model included age and dummy variables for gender, whether or not a daily calorie recommendation was provided, and whether or not calorie information about choices was provided. The reported value of the \(F\) ratio for testing model utility was \(3.64\). a. At significance level .01, does the model appear to specify a useful linear relationship between calorie intake and at least one of the predictors? b. What can be said about the \(P\)-value for the model utility \(F\) test? c. What proportion of the observed variation in calorie intake can be attributed to the model relationship? Does this seem very impressive? Why is the \(P\)-value as small as it is? d. The estimated coefficient for the indicator variable calorie information provided was \(-71.73\), with an estimated standard error of \(25.29\). Interpret the coefficient. After adjusting for the effects of other predictors, does it appear that true average calorie intake depends on whether or not calorie information is provided? Carry out a test of appropriate hypotheses.

A regression of \(y=\) calcium content \((\mathrm{g} / \mathrm{L})\) on \(x=\) dissolved material \(\left(\mathrm{mg} / \mathrm{cm}^{2}\right)\) was reported in the article "Use of Fly Ash or Silica Fume to Increase the Resistance of Concrete to Feed Acids" (Mag. Concrete Res., 1997: 337-344). The equation of the estimated regression line was \(y=3.678+.144 x\), with \(r^{2}=.860\), based on \(n=23\). a. Interpret the estimated slope \(.144\) and the coefficient of determination .860. b. Calculate a point estimate of the true average calcium content when the amount of dissolved material is \(50 \mathrm{mg} / \mathrm{cm}^{2}\). c. The value of total sum of squares was SST \(=320.398\). Calculate an estimate of the error standard deviation \(\sigma\) in the simple linear regression model.

Suppose that in a certain chemical process the reaction time \(y\) (hr) is related to the temperature \(\left({ }^{\circ} \mathrm{F}\right)\) in the chamber in which the reaction takes place according to the simple linear regression model with equation \(y=5.00-.01 x\) and \(\sigma=.075\). a. What is the expected change in reaction time for a \(1^{\circ} \mathrm{F}\) increase in temperature? For a \(10^{\circ} \mathrm{F}\) increase in temperature? b. What is the expected reaction time when temperature is \(200^{\circ} \mathrm{F}\) ? When temperature is \(250^{\circ} \mathrm{F}\) ? c. Suppose five observations are made independently on reaction time, each one for a temperature of \(250^{\circ} \mathrm{F}\). What is the probability that all five times are between \(2.4\) and \(2.6 \mathrm{~h}\) ? d. What is the probability that two independently observed reaction times for temperatures \(1^{\circ}\) apart are such that the time at the higher temperature exceeds the time at the lower temperature?

The \(x\) values and standardized residuals for the chlorine flow/etch rate data of Exercise 51 (Section 12.4) are displayed in the accompanying table. Construct a standardized residual plot and comment on its appearance. $$ \begin{aligned} &\begin{array}{l|rrrrr} x & 1.50 & 1.50 & 2.00 & 2.50 & 2.50 \\ \hline e^{*} & .31 & 1.02 & -1.15 & -1.23 & .23 \end{array}\\\ &\begin{array}{l|rrrr} x & 3.00 & 3.50 & 3.50 & 4.00 \\ \hline e^{*} & .73 & -1.36 & 1.53 & .07 \end{array} \end{aligned} $$

The article "Exhaust Emissions from Four-Stroke Lawn Mower Engines" \((J\). Air Water Manage. Assoc., 1997: 945-952) reported data from a study in which both a baseline gasoline mixture and a reformulated gasoline were used. Consider the following observations on age (year) and \(\mathrm{NO}_{\mathbf{x}}\) emissions (g/kWh): $$ \begin{array}{lccccc} \text { Engine } & 1 & 2 & 3 & 4 & 5 \\ \text { Age } & 0 & 0 & 2 & 11 & 7 \\ \text { Baseline } & 1.72 & 4.38 & 4.06 & 1.26 & 5.31 \\ \text { Reformulated } & 1.88 & 5.93 & 5.54 & 2.67 & 6.53 \\ \text { Engine } & 6 & 7 & 8 & 9 & 10 \\ \text { Age } & 16 & 9 & 0 & 12 & 4 \\ \text { Baseline } & .57 & 3.37 & 3.44 & .74 & 1.24 \\ \text { Reformulated } & .74 & 4.94 & 4.89 & .69 & 1.42 \end{array} $$ Construct scatter plots of \(\mathrm{NO}_{x}\) emissions versus age. What appears to be the nature of the relationship between these two variables? [Note: The authors of the cited article commented on the relationship.]

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