/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 Hydrogen content is conjectured ... [FREE SOLUTION] | 91Ó°ÊÓ

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Hydrogen content is conjectured to be an important factor in porosity of aluminum alloy castings. The article "The Reduced Pressure Test as a Measuring Tool in the Evaluation of Porosity/Hydrogen Content in A1-7 Wt Pct Si-10 Vol Pct SiC(p) Metal Matrix Composite" (Metallurg. Trans., 1993: 1857-1868) gives the accompanying data on \(x=\) content and \(y=\) gas porosity for one particular measurement technique. $$ \begin{array}{l|lllllll} x & .18 & .20 & .21 & .21 & .21 & .22 & .23 \\ \hline y & .46 & .70 & .41 & .45 & .55 & .44 & .24 \\ x & .23 & .24 & .24 & .25 & .28 & .30 & .37 \\ \hline y & .47 & .22 & .80 & .88 & .70 & .72 & .75 \end{array} $$ MINITAB gives the following output in response to a CORRELATION command: Correlation of Hydrcon and Porosity \(=0.449\) a. Test at level \(.05\) to see whether the population correlation coefficient differs from 0 . b. If a simple linear regression analysis had been carried out, what percentage of observed variation in porosity could be attributed to the model relationship?

Short Answer

Expert verified
Fail to reject the null hypothesis; 20.2% of variation in porosity is explained by the model.

Step by step solution

01

Set Up Hypotheses

We want to test if the population correlation coefficient differs from zero. The null hypothesis, \(H_0\), is that the correlation coefficient \(\rho = 0\). The alternative hypothesis, \(H_1\), is that \(\rho eq 0\).
02

Determine Test Statistic

The sample correlation coefficient is given as \(r = 0.449\). Using a t-test for correlation, the test statistic \(t\) is calculated as follows: \[ t = \frac{r\sqrt{n-2}}{\sqrt{1-r^2}} \] where \(n\) is the number of data pairs, \(n = 14\). Thus, \[ t = \frac{0.449\sqrt{14-2}}{\sqrt{1-0.449^2}} \].
03

Calculate Test Statistic

Substitute the values into the formula: \[ t = \frac{0.449\sqrt{12}}{\sqrt{1-0.201601}} \] \[ t \approx \frac{0.449 \times 3.464}{0.8944} \approx \frac{1.554}{0.8944} \approx 1.737 \].
04

Determine Critical Value and Conclusion

For a two-tailed test at significance level \(\alpha = 0.05\), with \(n-2 = 12\) degrees of freedom, the critical t-value is approximately 2.179 (from a t-distribution table). Since \(1.737 < 2.179\), we fail to reject the null hypothesis \(H_0\). There is not enough evidence to conclude that the population correlation coefficient differs from zero.
05

Determine Coefficient of Determination (\(R^2\))

To find the percentage of observed variation explained by the model, use the formula \(R^2 = r^2\). Calculate \(R^2 = 0.449^2 \approx 0.201601\).
06

Interpret \(R^2\)

The coefficient of determination \(R^2\), which is approximately 0.202, indicates that 20.2% of the observed variation in porosity can be attributed to the model relationship.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Testing
Statistical testing is a way of making decisions or inferences about a population, based on a sample. When it comes to correlation, statistical testing helps us determine if there is a significant connection between two variables. In our exercise, we set up a hypothesis test to check whether the correlation coefficient between hydrogen content and gas porosity in aluminum alloy castings differs from zero.

- **Null Hypothesis ( $H_0$):** Indicates that there is no correlation, or $ ho = 0$. - **Alternative Hypothesis ( $H_1$):** Indicates that there is a correlation, or $ ho eq 0$. To evaluate the correlation, we used a t-test for the given sample correlation coefficient of 0.449 and verified it against the critical t-value for 12 degrees of freedom at a 0.05 significance level. Because our calculated t-value was less than the critical value, we concluded there wasn't enough evidence to suggest a significant correlation exists between the variables. This means we failed to reject the null hypothesis.
Linear Regression
Linear regression is a statistical tool used for understanding the relationship between two continuous variables. In this scenario, the relationship was examined between hydrogen content and gas porosity in the casting process. The simplest form of linear regression is the simple linear regression, which fits a straight line through the data.

The model can be represented by the equation:\[ y = mx + c \]where:- \(y\) is the dependent variable (gas porosity),- \(x\) is the independent variable (hydrogen content),- \(m\) is the slope of the line,- \(c\) is the y-intercept.By fitting this model, we aim to predict or explain porosity changes based on changes in hydrogen. Our regression analysis helps us identify trends and make forecasts based on our data. It's crucial to note, however, even with a given correlation, external variables might also affect outcomes. Hence, linear regression models demand careful interpretation.
Coefficient of Determination
The coefficient of determination, denoted as \(R^2\), tells us how well our statistical model explains the variation in the observed data. It's essentially the squared value of the correlation coefficient and is expressed as a percentage.
For our exercise, \(R^2\) was calculated as 0.202, meaning that approximately 20.2% of the variability in gas porosity is accounted for by the hydrogen content model.

This value provides insights into the strength of the relationship. A higher \(R^2\) means more variation is explained by the model, signaling a stronger connection. However, an \(R^2\) of 20.2% implies that while some correlation exists, a substantial amount of the variation is influenced by factors not included in the model. So, while helpful, \(R^2\) should be considered in conjunction with other analytical methods and domain knowledge for decision-making.

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Most popular questions from this chapter

Suppose that \(x\) and \(y\) are positive variables and that a sample of \(n\) pairs results in \(r \approx 1\). If the sample correlation coefficient is computed for the \(\left(x, y^{2}\right)\) pairs, will the resulting value also be approximately 1? Explain.

The \(x\) values and standardized residuals for the chlorine flow/etch rate data of Exercise 51 (Section 12.4) are displayed in the accompanying table. Construct a standardized residual plot and comment on its appearance. $$ \begin{aligned} &\begin{array}{l|rrrrr} x & 1.50 & 1.50 & 2.00 & 2.50 & 2.50 \\ \hline e^{*} & .31 & 1.02 & -1.15 & -1.23 & .23 \end{array}\\\ &\begin{array}{l|rrrr} x & 3.00 & 3.50 & 3.50 & 4.00 \\ \hline e^{*} & .73 & -1.36 & 1.53 & .07 \end{array} \end{aligned} $$

The article "Characterization of Highway Runoff in Austin, Texas, Area" (J. Environ. Engrg., 1998: 131-137) gave a scatter plot, along with the least squares line, of \(x=\) rainfall volume \(\left(\mathrm{m}^{3}\right)\) and \(y=\) runoff volume \(\left(\mathrm{m}^{3}\right)\) for a particular location. The accompanying values were read from the plot. $$ \begin{aligned} &\begin{array}{l|llllllll} x & 5 & 12 & 14 & 17 & 23 & 30 & 40 & 47 \\ \hline y & 4 & 10 & 13 & 15 & 15 & 25 & 27 & 46 \end{array}\\\ &\begin{array}{l|rrrrrrr} x & 55 & 67 & 72 & 81 & 96 & 112 & 127 \\ \hline y & 38 & 46 & 53 & 70 & 82 & 99 & 100 \end{array} \end{aligned} $$ a. Does a scatter plot of the data support the use of the simple linear regression model? b. Calculate point estimates of the slope and intercept of the population regression line. c. Calculate a point estimate of the true average runoff volume when rainfall volume is 50 . d. Calculate a point estimate of the standard deviation \(\sigma\). e. What proportion of the observed variation in runoff volume can be attributed to the simple linear regression relationship between runoff and rainfall?

Plasma etching is essential to the fine-line pattern transfer in current semiconductor processes. The article "Ion Beam-Assisted Etching of Aluminum with Chlorine" (J. Electrochem. Soc., 1985: 2010-2012) gives the accompanying data (read from a graph) on chlorine flow \((x\), in SCCM) through a nozzle used in the etching mechanism and etch rate \((y\), in \(100 \mathrm{~A} / \mathrm{min})\). $$ \begin{array}{l|lrrrrrrrr} x & 1.5 & 1.5 & 2.0 & 2.5 & 2.5 & 3.0 & 3.5 & 3.5 & 4.0 \\ \hline y & 23.0 & 24.5 & 25.0 & 30.0 & 33.5 & 40.0 & 40.5 & 47.0 & 49.0 \end{array} $$ a. Does the simple linear regression model specify a useful relationship between chlorine flow and etch rate? b. Estimate the true average change in etch rate associated with a 1-SCCM increase in flow rate using a \(95 \%\) confidence interval, and interpret the interval. c. Calculate a \(95 \%\) CI for \(\mu_{Y \cdot 3.0}\), the true average etch rate when flow \(=3.0\). Has this average been precisely estimated? d. Calculate a \(95 \%\) PI for a single future observation on etch rate to be made when flow \(=3.0 .\) Is the prediction likely to be accurate? e. Would the \(95 \%\) CI and PI when flow \(=2.5\) be wider or narrower than the corresponding intervals of parts (c) and (d)? Answer without actually computing the intervals. f. Would you recommend calculating a \(95 \%\) PI for a flow of 6.0? Explain. g. Calculate simultaneous CI's for true average etch rate when chlorine flow is \(2.0,2.5\), and \(3.0\), respectively. Your simultaneous confidence level should be at least \(97 \%\).

The Turbine Oil Oxidation Test (TOST) and the Rotating Bomb Oxidation Test (RBOT) are two different procedures for evaluating the oxidation stability of steam turbine oils. The article "Dependence of Oxidation Stability of Steam Turbine Oil on Base Oil Composition" (J. Soc. Tribologists Lubricat. Engrs., Oct. 1997: 19-24) reported the accompanying observations on \(x=\) TOST time (hr) and \(y=\) RBOT time (min) for 12 oil specimens. $$ \begin{array}{lrrrrrr} \text { TOST } & 4200 & 3600 & 3750 & 3675 & 4050 & 2770 \\ \text { RBOT } & 370 & 340 & 375 & 310 & 350 & 200 \\ \text { TOST } & 4870 & 4500 & 3450 & 2700 & 3750 & 3300 \\ \text { RBOT } & 400 & 375 & 285 & 225 & 345 & 285 \end{array} $$ a. Calculate and interpret the value of the sample correlation coefficient (as did the article's authors). b. How would the value of \(r\) be affected if we had let \(x=\) RBOT time and \(y=\) TOST time? c. How would the value of \(r\) be affected if RBOT time were expressed in hours? d. Construct a scatter plot and normal probability plots and comment. e. Carry out a test of hypotheses to decide whether RBOT time and TOST time are linearly related.

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