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Torsion during hip external rotation and extension may explain why acetabular labral tears occur in professional athletes. The article "Hip Rotational Velocities During the Full Golf Swing" \((J\). Sport Sci. Med., 2009: 296 - 299) reported on an investigation in which lead hip internal peak rotational velocity \((x)\) and trailing hip peak external rotational velocity \((y)\) were determined for a sample of 15 golfers. Data provided by the article's authors was used to calculate the following summary quantities: $$ \begin{aligned} &S_{x x}=64,732.83, \quad S_{y y}=130,566.96, \\ &S_{x y}=44,185.87 \end{aligned} $$ Separate normal probability plots showed very substantial linear patterns. a. Calculate a point estimate for the population correlation coefficient. b. If the simple linear regression model were fit to the data, what proportion of variation in external velocity could be attributed to the model relationship? What would happen to this proportion if the roles of \(x\) and \(y\) were reversed? Explain. c. Carry out a test at significance level .01 to decide whether there is a linear relationship between the two velocities in the sampled population; your conclusion should be based on a \(P\)-value. d. Would the conclusion of (c) have changed if you had tested appropriate hypotheses to decide whether there is a positive linear association in the population? What if a significance level of \(.05\) rather than \(.01\) had been used?

Short Answer

Expert verified
a. \( r \approx 0.486 \), b. \( r^2 \approx 0.236 \); same if reversed, c. p-value > 0.01, no linear relationship, d. Result may change if one-tailed or \( \alpha = 0.05 \).

Step by step solution

01

Calculate the point estimate for the correlation coefficient

The sample correlation coefficient \( r \) is calculated using the formula:\[ r = \frac{S_{xy}}{\sqrt{S_{xx} \cdot S_{yy}}}\]Substitute the given values:\[ r = \frac{44,185.87}{\sqrt{64,732.83 \cdot 130,566.96}} \]Calculate the values inside the square root and then divide to find \( r \).
02

Calculate proportion of variation explained

The proportion of variation in \( y \) explained by \( x \) is the square of the correlation coefficient, \( r^2 \). Use the \( r \) calculated in Step 1 to find this value.
03

Reversing roles of x and y

Reversing the roles of \( x \) and \( y \) does not change the correlation coefficient \( r \), so the proportion \( r^2 \) remains the same whether predicting \( y \) from \( x \) or \( x \) from \( y \).
04

Hypothesis test for correlation at 0.01 significance

To test if there is a linear relationship, use the hypotheses:- Null Hypothesis (\( H_0 \)): \( \rho = 0 \) (no linear relationship)- Alternative Hypothesis (\( H_a \)): \( \rho eq 0 \) (there is a linear relationship)Calculate the t-statistic:\[t = \frac{r\sqrt{n-2}}{\sqrt{1-r^2}}\]Assuming \( n = 15 \), then find the p-value for this \( t \)-statistic. Compare it against the 0.01 significance level.
05

Conclusion based on two-tailed test

If the p-value is less than 0.01, reject the null hypothesis; otherwise, fail to reject it. This determines if there is a statistically significant linear relationship.
06

Consideration of positive correlation and different significance level

For testing positive correlation, use a one-tailed test. The results might change if the alternative hypothesis becomes \( \rho > 0 \). The lower significance level of 0.05 would make it easier to find a significant result, possibly altering the decision compared to a 0.01 level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Relationship
A linear relationship between two variables implies that there is a consistent, proportional relationship between them. In the context of the correlation coefficient, this means that as one variable increases, the other variable tends to either increase or decrease at a constant rate.

A key characteristic of a linear relationship is that it can be represented graphically as a straight line on a scatter plot. The strength and direction of this relationship are quantified by the correlation coefficient, denoted by \( r \).

When working with data, identifying a linear pattern is often the first step in understanding the connection between two variables. This helps in predicting one variable based on the other, often leading to applications like creating regression models.
Hypothesis Testing
Hypothesis testing is a statistical method that helps us make decisions about a population based on sample data. In the context of this problem, we perform hypothesis testing to determine if there is a significant linear relationship between two types of hip rotational velocities in golfers.

The process begins by setting up two hypotheses:
  • The Null Hypothesis (\( H_0 \)): There is no linear relationship between the variables (\( \rho = 0 \)).
  • The Alternative Hypothesis (\( H_a \)): There is a linear relationship (\( \rho eq 0 \)).
A statistical test, such as a t-test, is done to calculate a test statistic and a p-value, which helps decide whether to reject the null hypothesis. The p-value tells us the probability of observing the data if the null hypothesis is true.

If the p-value is less than the chosen level of significance, like 0.01 or 0.05, we reject the null hypothesis and conclude that a significant linear relationship exists. Otherwise, we fail to reject the null hypothesis, implying insufficient evidence to claim a relationship.
Regression Model
A regression model is a mathematical representation that describes the relationship between a dependent variable and one or more independent variables. In this context, we are focusing on a simple linear regression model, where we try to express the leading hip internal rotation as a predictor for trailing hip rotation.

The regression model is often written in the form: \[y = a + bx\]where \( y \) is the dependent variable, \( x \) is the independent variable, \( a \) is the y-intercept, and \( b \) is the slope of the line. The slope indicates how much \( y \) changes for a unit change in \( x \).

Creating a regression model involves fitting a line to a set of data points that minimizes the difference between the observed data and the line itself. This difference is known as the residual. Once a model is fit, it can be used to predict values, assess trends, and even test new hypotheses about related phenomena.
Golf Swing Analysis
Golf swing analysis uses various methods, including statistical models, to understand the mechanics of a golfer's swing. The focus here is on examining hip rotational velocities and understanding how they contribute to performance and potential injuries.

By analyzing these velocities, researchers can identify patterns that may predict outcomes such as injury risk or success in golf. This analysis is done through collecting data, calculating statistical measures like means, variances, and correlation coefficients, and fitting regression models to explore relationships between different swing components.

Understanding the correlations between different aspects of the golf swing can inform training regimes and injury prevention strategies, helping golfers optimize their performance and maintain their physical health. This is why studies and data analysis like these are invaluable in professional athletics.

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Most popular questions from this chapter

A sample of \(n=500(x, y)\) pairs was collected and a test of \(H_{0}: \rho=0\) versus \(H_{\mathrm{a}}: \rho \neq 0\) was carried out. The resulting \(P\)-value was computed to be \(.00032\). a. What conclusion would be appropriate at level of significance .001? b. Does this small \(P\)-value indicate that there is a very strong relationship between \(x\) and \(y\) (a value of \(\rho\) that differs considerably from 0\()\) ? Explain. c. Now suppose a sample of \(n=10,000(x, y)\) pairs resulted in \(r=.022\). Test \(H_{0}: \rho=0\) versus \(H_{\mathrm{a}}: \rho \neq 0\) at level .05. Is the result statistically significant? Comment on the practical significance of your analysis.

Infestation of crops by insects has long been of great concern to farmers and agricultural scientists. The article "Cotton Square Damage by the Plant Bug, Lygus hesperus, and Abscission Rates" (J. Econ. Entomol., 1988: 1328-1337) reports data on \(x=\) age of a cotton plant (days) and \(y=\%\) damaged squares. Consider the accompanying \(n=12\) observations (read from a scatter plot in the article). $$ \begin{array}{l|rrrrrr} x & 9 & 12 & 12 & 15 & 18 & 18 \\ \hline y & 11 & 12 & 23 & 30 & 29 & 52 \\ x & 21 & 21 & 27 & 30 & 30 & 33 \\ \hline y & 41 & 65 & 60 & 72 & 84 & 93 \end{array} $$ a. Why is the relationship between \(x\) and \(y\) not deterministic? b. Does a scatter plot suggest that the simple linear regression model will describe the relationship between the two variables? c. The summary statistics are \(\sum x_{i}=246\), \(\sum x_{i}^{2}=5742, \quad \sum y_{i}=572, \quad \sum y_{i}^{2}=35,634\) and \(\sum x_{i} y_{i}=14,022\). Determine the equation of the least squares line. d. Predict the percentage of damaged squares when the age is 20 days by giving an interval of plausible values.

The article "Validation of the Rockport Fitness Walking Test in College Males and Females" (Res. Q. Exercise Sport, 1994: 152-158) recommended the following estimated regression equation for relating \(y=\mathrm{VO}_{2} \max (\mathrm{L} / \mathrm{min}\), a measure of cardiorespiratory fitness) to the predictors \(x_{1}\) \(=\) gender (female \(=0\), male \(=1\) ), \(x_{2}=\) weight (lb), \(x_{3}=1\)-mile walk time (min), and \(x_{4}=\) heart rate at the end of the walk (beats/min): $$ \begin{aligned} y=& 3.5959+.6566 x_{1}+.0096 x_{2} \\ &-.0996 x_{3}-.0080 x_{4} \end{aligned} $$ a. How would you interpret the estimated coefficient \(-.0996\) ? b. How would you interpret the estimated coefficient .6566? c. Suppose that an observation made on a male whose weight was \(170 \mathrm{lb}\), walk time was \(11 \mathrm{~min}\), and heart rate was 140 beats \(/ \mathrm{min}\) resulted in \(\mathrm{VO}_{2} \mathrm{max}=3.15\). What would you have predicted for \(\mathrm{VO}_{2}\) max in this situation, and what is the value of the corresponding residual? d. Using SSE \(=30.1033\) and SST \(=102.3922\), what proportion of observed variation in \(\mathrm{VO}_{2} \max\) can be attributed to the model relationship? e. Assuming a sample size of \(n=20\), carry out a test of hypotheses to decide whether the chosen model specifies a useful relationship between \(\mathrm{VO}_{2} \max\) and at least one of the predictors.

When a scatter plot of bivariate data shows a pattern resembling an exponentially increasing or decreasing curve, the following multiplicative exponential model is often used: \(Y=\alpha e^{\beta x} \cdot \varepsilon\). a. What does this multiplicative model imply about the relationship between \(Y^{\prime}=\ln (Y)\) and \(x\) ? [Hint: take logs on both sides of the model equation and let \(\beta_{0}=\ln (\alpha), \beta_{1}=\beta, \varepsilon^{\prime}=\ln\) \((\varepsilon)\), and suppose that \(\varepsilon\) has a lognormal distribution.] b. The accompanying data resulted from an investigation of how ethylene content of lettuce seeds \((y\), in \(\mathrm{nL} / \mathrm{g}\) dry \(\mathrm{wt})\) varied with exposure time \((x\), in min) to an ethylene absorbent ("Ethylene Synthesis in Lettuce Seeds: Its Physiological Significance," Plant Physiol., 1972: 719-722). $$ \begin{array}{c|ccccccccccc} x & 2 & 20 & 20 & 30 & 40 & 50 & 60 & 70 & 80 & 90 & 100 \\ \hline y & 408 & 274 & 196 & 137 & 90 & 78 & 51 & 40 & 30 & 22 & 15 \end{array} $$ Fit the simple linear regression model to this data, and check model adequacy using the residuals. c. Is a scatter plot of the data consistent with the exponential regression model? Fit this model by first carrying out a simple linear regression analysis using \(\ln (y)\) as the dependent variable and \(x\) as the independent variable. How good a fit is the simple linear regression model to the "transformed" data [the \((x, \ln (y))\) pairs]? What are point estimates of the parameters \(\alpha\) and \(\beta ?\) d. Obtain a \(95 \%\) prediction interval for ethylene content when exposure time is \(50 \mathrm{~min}\). [Hint: first obtain a PI for \(\ln (y)\) based on the simple linear regression carried out in (c).]

The article "Determination of Biological Maturity and Effect of Harvesting and Drying Conditions on Milling Quality of Paddy" (J. Agric. Engr. Res., 1975: 353-361) reported the following data on date of harvesting ( \(x\), the number of days after flowering) and yield of paddy, a grain farmed in India ( \(y\), in \(\mathrm{kg} / \mathrm{ha}\) ). $$ \begin{aligned} &\begin{array}{l|cccccccc} x & 16 & 18 & 20 & 22 & 24 & 26 & 28 & 30 \\ \hline y & 2508 & 2518 & 3304 & 3423 & 3057 & 3190 & 3500 & 3883 \end{array}\\\ &\begin{array}{c|cccccccc} x & 32 & 34 & 36 & 38 & 40 & 42 & 44 & 46 \\ \hline y & 3823 & 3646 & 3708 & 3333 & 3517 & 3241 & 3103 & 2776 \end{array} \end{aligned} $$ a. Construct a scatter plot of the data. What model is suggested by the plot? b. Use a statistical software package to fit the model suggested in (a) and test its utility. c. Use the software package to obtain a prediction interval for yield when the crop is harvested 25 days after flowering, and also a confidence interval for expected yield in situations where the crop is harvested 25 days after flowering. How do these two intervals compare to each other? Is this result consistent with what you learned in simple linear regression? Explain. d. Use the software package to obtain a PI and CI when \(x=40\). How do these intervals compare to the corresponding intervals obtained in (c)? Is this result consistent with what you learned in simple linear regression? Explain. e. Carry out a test of hypotheses to decide whether the quadratic predictor in the model fit in (b) provides useful information about yield (presuming that the linear predictor remains in the model).

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