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Suppose that \(x\) and \(y\) are positive variables and that a sample of \(n\) pairs results in \(r \approx 1\). If the sample correlation coefficient is computed for the \(\left(x, y^{2}\right)\) pairs, will the resulting value also be approximately 1? Explain.

Short Answer

Expert verified
No, the correlation will decrease and will not remain approximately 1.

Step by step solution

01

Understanding Correlation Coefficient

The correlation coefficient, denoted as \( r \), measures the strength and direction of a linear relationship between two variables. If \( r \approx 1 \), it indicates a strong positive linear relationship between the variables.
02

Analyze the Transformation

In the given problem, the transformation is from \( y \) to \( y^2 \). Recall that \( y^2 \) will mostly affect the non-linearity, especially if \( y \) has varied values — it squashes small numbers and enlarges bigger ones, altering the linear relationship.
03

Effect on Linear Relationship

The linear relationship will be disrupted by squaring \( y \), as this transformation generally creates a more quadratic or non-linear relationship, thus potentially reducing the linear correlation.
04

Compute New Correlation

Calculate the new correlation \( r' \) using the pairs \( (x, y^2) \). Since \( r \approx 1 \) for \( (x, y) \), but now \( y \) has been transformed non-linearly, \( r' \) will not remain approximately 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Relationship
In statistics, a linear relationship between two variables, often represented as \( x \) and \( y \), depicts that the two variables move in a constant rate relative to each other. When we talk about a linear relationship, we usually mean that as one variable increases, the other increases at a steady rate, resulting in a straight line when plotted on a graph. This is what is measured by the correlation coefficient, \( r \). An \( r \) value close to 1 suggests a strong positive linear relationship. This means that an increase in one variable results in a proportionate increase in the other.

Understanding a linear relationship is vital as it sets the foundation for predicting outcomes. For example:
  • If \( x \) represents hours of study and \( y \) represents exam scores, a strong linear relationship would imply that more study hours correspond to higher scores.
  • Linear relationships are visualized using scatter plots where data points align closely to a straight line.
Thus, any transformation or alteration in this relationship, like squaring \( y \), must be approached with care as it might disrupt this predictability, turning linear into non-linear.
Transformation Effects
Transformation effects come into play when we alter variables with mathematical operations. The exercise involves squaring \( y \), which transforms it from \( y \) to \( y^2 \). Understanding how transformations like this affect correlations is crucial. Such transformations can straighten non-linear data but can also introduce non-linearity in data that was originally linear.

When we square \( y \), small values of \( y \) become even smaller relative to large values that become much larger. This transformation distorts the original relationship between \( x \) and \( y \).
  • Squaring generally increases the magnitude of differences among values.
  • Larger disparities cause more spread in data points on a scatter plot.
  • This results in the loss of the original straight-line relationship.
Consequently, the correlation coefficient \( r \), which was originally near 1 indicating a strong linear relationship, diminishes when the relationship turns non-linear.
Mathematical Statistics
In mathematical statistics, we utilize various tools to understand and interpret data relationships. The correlation coefficient \( r \) is one such tool that quantifies the direction and strength of a linear relationship between two variables. However, the utility of \( r \) is limited to linear relationships.
  • \( r \) values range from -1 to 1, where values near -1 indicate a strong negative relationship, and values near 1 indicate a strong positive relationship.
  • A value of 0 suggests no linear correlation.
Besides correlation, mathematical statistics extensively study transformations like conversion to \( y^2 \) and their effects. The study of these transformations helps us understand how data behaves under manipulation and guide us in model fitting.When transformations distort relationships, as in the case where linear relationships turn non-linear, the correlation coefficient loses relevance, prompting a need to re-evaluate data through a lens that considers non-linearity. This can include fitting non-linear models or calculating other statistics that capture the essence of transformed data.

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Most popular questions from this chapter

Cardiorespiratory fitness is widely recognized as a major component of overall physical well-being. Direct measurement of maximal oxygen uptake \(\left(\mathrm{VO}_{2} \max \right)\) is the single best measure of such fitness, but direct measurement is time-consuming and expensive. It is therefore desirable to have a prediction equation for \(\mathrm{VO}_{2}\) max in terms of easily obtained quantities. Consider the variables \(\begin{aligned} y &=\mathrm{VO}_{2} \max (\mathrm{L} / \mathrm{min}) \quad x_{1}=\text { weight }(\mathrm{kg}) \\ x_{2} &=\text { age }(\mathrm{yr}) \\\ x_{3} &=\text { time necessary to walk } 1 \text { mile }(\mathrm{min}) \\\ x_{4} &=\text { heart rate at the end of the walk }(\text { beats } / \mathrm{min}) \end{aligned}\) Here is one possible model, for male students, consistent with the information given in the article "Validation of the Rockport Fitness Walking Test in College Males and Females" (Res. Q. Exercise Sport, 1994: 152–158): $$ \begin{aligned} &Y=5.0+.01 x_{1}-.05 x_{2}-.13 x_{3}-.01 x_{4}+\varepsilon \\ &\sigma=.4 \end{aligned} $$ a. Interpret \(\beta_{1}\) and \(\beta_{3}\). b. What is the expected value of \(\mathrm{VO}_{2} \max\) when weight is \(76 \mathrm{~kg}\), age is 20 year, walk time is \(12 \mathrm{~min}\), and heart rate is 140 beats \(/ \mathrm{min}\) ? c. What is the probability that \(\mathrm{VO}_{2}\) max will be between \(1.00\) and \(2.60\) for a single observation made when the values of the predictors are as stated in part (b)?

As the air temperature drops, river water becomes supercooled and ice crystals form. Such ice can significantly affect the hydraulics of a river. The article "Laboratory Study of Anchor Ice Growth" (J. Cold Regions Engrg., 2001: 60-66) described an experiment in which ice thickness \((\mathrm{mm})\) was studied as a function of elapsed time ( \(\mathrm{hr}\) ) under specified conditions. The following data was read from a graph in the article: \(n=33 ; x=.17, .33, .50, .67, \ldots, 5.50\); \(y=.50,1.25,1.50,2.75,3.50,4.75,5.75,5.60\), \(7.00,8.00,8.25,9.50,10.50,11.00,10.75,12.50\), \(12.25,13.25,15.50,15.00,15.25,16.25,17.25\), \(18.00,18.25,18.15,20.25,19.50,20.00,20.50\), \(20.60,20.50,19.80\). a. The \(r^{2}\) value resulting from a least squares fit is \(.977\). Given the high \(r^{2}\), does it seem appropriate to assume an approximate linear relationship? b. The residuals, listed in the same order as the \(x\) values, are $$ \begin{array}{rrrrrrr} -1.03 & -0.92 & -1.35 & -0.78 & -0.68 & -0.11 & 0.21 \\ -0.59 & 0.13 & 0.45 & 0.06 & 0.62 & 0.94 & 0.80 \\ -0.14 & 0.93 & 0.04 & 0.36 & 1.92 & 0.78 & 0.35 \\ 0.67 & 1.02 & 1.09 & 0.66 & -0.09 & 1.33 & -0.10 \\ -0.24 & -0.43 & -1.01 & -1.75 & -3.14 & & \end{array} $$ Plot the residuals against \(x\), and reconsider the question in (a). What does the plot suggest?

The invasive diatom species Didymosphenia Geminata has the potential to inflict substantial ecological and economic damage in rivers. The article "Substrate Characteristics Affect Colonization by the Bloom-Forming Diatom Didymosphenia Geminata" (Aquatic Ecology, 2010: 33-40) described an investigation of colonization behavior. One aspect of particular interest was whether \(y=\) colony density was related to \(x=\) rock surface area. The article contained a scatter plot and summary of a regression analysis. Here is representative data: $$ \begin{aligned} &\begin{array}{c|ccccccc} x & 50 & 71 & 55 & 50 & 33 & 58 & 79 \\ \hline y & 152 & 1929 & 48 & 22 & 2 & 5 & 35 \end{array}\\\ &\begin{array}{l|cccccccc} x & 26 & 69 & 44 & 37 & 70 & 20 & 45 & 49 \\ \hline y & 7 & 269 & 38 & 171 & 13 & 43 & 185 & 25 \end{array} \end{aligned} $$ a. Fit the simple linear regression model to this data, and then calculate and interpret the coefficient of determination. b. Carry out a test of hypotheses to determine whether there is a useful linear relationship between density and rock area. c. The second observation has a very extreme \(y\) value (in the full data set consisting of 72 observations, there were two of these). This observation may have had a substantial impact on the fit of the model and subsequent conclusions. Eliminate it and redo parts (a) and (b). What do you conclude?

Utilization of sucrose as a carbon source for the production of chemicals is uneconomical. Beet molasses is a readily available and lowpriced substitute. The article "Optimization of the Production of \(\beta\)-Carotene from Molasses by Blakeslea trispora" \((J .\) Chem. Tech. Biotech., 2002: 933-943) carried out a multiple regression analysis to relate the dependent variable \(y=\) amount of \(\beta\)-carotene \(\left(\mathrm{g} / \mathrm{dm}^{3}\right)\) to the three predictors: amount of linoleic acid, amount of kerosene, and amount of antioxidant (all \(\mathrm{g} / \mathrm{dm}^{3}\) ). a. Fitting the complete second-order model in the three predictors resulted in \(R^{2}=.987\) and adjusted \(R^{2}=974\), whereas fitting the first-order model gave \(R^{2}=.016\). What would you conclude about the two models? b. For \(x_{1}=x_{2}=30, x_{3}=10\), a statistical software package reported that \(\hat{y}=.66573, s_{\hat{Y}}=.01785\) based on the complete second-order model. Predict the amount of \(\beta\)-carotene that would result from a single experimental run with the designated values of the independent variables, and do so in a way that conveys information about precision and reliability. $$ \begin{array}{lccrc} \hline \text { Obs } & \text { Linoleic } & \text { Kerosene } & \text { Antiox } & \text { Betacaro } \\ \hline 1 & 30.00 & 30.00 & 10.00 & 0.7000 \\ 2 & 30.00 & 30.00 & 10.00 & 0.6300 \\ 3 & 30.00 & 30.00 & 18.41 & 0.0130 \\ 4 & 40.00 & 40.00 & 5.00 & 0.0490 \\ 5 & 30.00 & 30.00 & 10.00 & 0.7000 \\ 6 & 13.18 & 30.00 & 10.00 & 0.1000 \\ 7 & 20.00 & 40.00 & 5.00 & 0.0400 \\ 8 & 20.00 & 40.00 & 15.00 & 0.0065 \\ 9 & 40.00 & 20.00 & 5.00 & 0.2020 \\ 10 & 30.00 & 30.00 & 10.00 & 0.6300 \\ 11 & 30.00 & 30.00 & 1.59 & 0.0400 \\ 12 & 40.00 & 20.00 & 15.00 & 0.1320 \\ 13 & 40.00 & 40.00 & 15.00 & 0.1500 \\ 14 & 30.00 & 30.00 & 10.00 & 0.7000 \\ 15 & 30.00 & 46.82 & 10.00 & 0.3460 \\ 16 & 30.00 & 30.00 & 10.00 & 0.6300 \\ 17 & 30.00 & 13.18 & 10.00 & 0.3970 \\ 18 & 20.00 & 20.00 & 5.00 & 0.2690 \\ 19 & 20.00 & 20.00 & 15.00 & 0.0054 \\ 20 & 46.82 & 30.00 & 10.00 & 0.0640 \\ \hline \end{array} $$

A sample of \(n=500(x, y)\) pairs was collected and a test of \(H_{0}: \rho=0\) versus \(H_{\mathrm{a}}: \rho \neq 0\) was carried out. The resulting \(P\)-value was computed to be \(.00032\). a. What conclusion would be appropriate at level of significance .001? b. Does this small \(P\)-value indicate that there is a very strong relationship between \(x\) and \(y\) (a value of \(\rho\) that differs considerably from 0\()\) ? Explain. c. Now suppose a sample of \(n=10,000(x, y)\) pairs resulted in \(r=.022\). Test \(H_{0}: \rho=0\) versus \(H_{\mathrm{a}}: \rho \neq 0\) at level .05. Is the result statistically significant? Comment on the practical significance of your analysis.

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