/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 The invasive diatom species Didy... [FREE SOLUTION] | 91Ó°ÊÓ

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The invasive diatom species Didymosphenia Geminata has the potential to inflict substantial ecological and economic damage in rivers. The article "Substrate Characteristics Affect Colonization by the Bloom-Forming Diatom Didymosphenia Geminata" (Aquatic Ecology, 2010: 33-40) described an investigation of colonization behavior. One aspect of particular interest was whether \(y=\) colony density was related to \(x=\) rock surface area. The article contained a scatter plot and summary of a regression analysis. Here is representative data: $$ \begin{aligned} &\begin{array}{c|ccccccc} x & 50 & 71 & 55 & 50 & 33 & 58 & 79 \\ \hline y & 152 & 1929 & 48 & 22 & 2 & 5 & 35 \end{array}\\\ &\begin{array}{l|cccccccc} x & 26 & 69 & 44 & 37 & 70 & 20 & 45 & 49 \\ \hline y & 7 & 269 & 38 & 171 & 13 & 43 & 185 & 25 \end{array} \end{aligned} $$ a. Fit the simple linear regression model to this data, and then calculate and interpret the coefficient of determination. b. Carry out a test of hypotheses to determine whether there is a useful linear relationship between density and rock area. c. The second observation has a very extreme \(y\) value (in the full data set consisting of 72 observations, there were two of these). This observation may have had a substantial impact on the fit of the model and subsequent conclusions. Eliminate it and redo parts (a) and (b). What do you conclude?

Short Answer

Expert verified
Rerun calculations excluding the outlier. Determine if the relationship remains significant and compare fits with and without the outlier using \( R^2 \) and p-values.

Step by step solution

01

Organizing the Data

We begin by organizing the data points for regression. The paired values are \((50, 152), (71, 1929), (55, 48), (50, 22), (33, 2), (58, 5), (79, 35), (26, 7), (69, 269), (44, 38), (37, 171), (70, 13), (20, 43), (45, 185), (49, 25)\). We aim to fit a linear regression model of the form \( y = \beta_0 + \beta_1 x + \epsilon \).
02

Calculating Linear Regression Parameters

Calculate the coefficients, \( \beta_0 \) and \( \beta_1 \), using the formulas: \( \beta_1 = \frac{\sum{(x_i - \bar{x})(y_i - \bar{y})}}{\sum{(x_i - \bar{x})^2}} \) and \( \beta_0 = \bar{y} - \beta_1 \bar{x} \). Insert the summed values of data to compute \(\beta_1\) and \(\beta_0\).
03

Coefficient of Determination

Calculate the coefficient of determination, \( R^2 \), using the formula: \( R^2 = 1 - \frac{SS_{res}}{SS_{tot}} \). \(SS_{res}\) is the sum of squared residuals and \(SS_{tot}\) is the total sum of squares. This value explains the proportion of variance in \(y\) explained by \(x\).
04

Hypothesis Testing for Linear Relationship

Perform a hypothesis test for the slope \( \beta_1 \): \( H_0: \beta_1 = 0 \) vs. \( H_1: \beta_1 eq 0 \). Compute the t-statistic and compare it to a critical value or use a p-value approach to conclude whether there is a significant linear relationship.
05

Re-evaluate Without Outlier

Remove the outlier (second observation with \( x = 71 \), \( y = 1929 \)) and redo steps 2 to 4, recalculating the regression coefficients, \( R^2 \), and hypothesis test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Determination
The coefficient of determination, often represented as \( R^2 \), is a key statistic in understanding the strength of linear regression. It provides a measure of how well the independent variable, like rock surface area in this study, explains the variability of the dependent variable, which in this case is colony density. Essentially, \( R^2 \) is a number between 0 and 1 that indicates the proportion of the variance in the dependent variable that can be predicted from the independent variable.
In a simple linear regression model, if you find that \( R^2 = 0.75 \), it means that 75% of the variability in the colony density can be explained by the rock surface area. A higher \( R^2 \) value indicates a better fit for the model to the data.
However, it's important to note that a high \( R^2 \) value does not imply causation. It simply indicates a strong correlation between the variables. In our example, if after removing an outlier \( R^2 \) increases, it suggests that the model without the outlier fits the data better and captures the true relationship more accurately.
Hypothesis Testing
Hypothesis testing in the context of simple linear regression is all about determining if there is a statistically significant relationship between the independent variable and the dependent variable. For this, we conduct a hypothesis test on the slope \( \beta_1 \) of the regression line.
The null hypothesis (\( H_0 \)) is typically that \( \beta_1 = 0 \), indicating no linear relationship. The alternative hypothesis (\( H_1 \)) is that \( \beta_1 eq 0 \), suggesting a linear relationship exists.
To test this, we use the t-statistic, calculated as \( t = \frac{\hat{\beta_1}}{SE(\hat{\beta_1})} \), where \( SE(\hat{\beta_1}) \) is the standard error of the estimated slope. We compare this t-statistic to a critical value from the t-distribution or look at the p-value. A p-value less than 0.05 typically means we reject the null hypothesis, confirming that the relationship between rock surface area and colony density is statistically significant.
Performing this test heightens our confidence in the predictive value of our model.
Outlier Analysis
Outlier analysis involves identifying and assessing data points that deviate significantly from other observations. In our exercise, an extreme value in colony density for a specific rock surface area is removed as it may skew the regression results.
Outliers can arise due to variability in measurement or experimental errors, but could also represent anomalies worth further investigation. They can substantially affect the slope of the regression line, \( R^2 \), and other statistics, leading to misleading conclusions.
After identifying an outlier, such as the observation with \( x = 71 \) and \( y = 1929 \), it's important to redo computations without it to understand its impact. Removing an outlier often results in a tighter regression fit and more reliable estimates of parameters. Thus, it's essential to assess whether an outlier should be excluded based on its influence on the analysis.
Scatter Plot Interpretation
Interpreting scatter plots is a fundamental skill for analyzing data in simple linear regression. A scatter plot visualizes the relationship between two variables, such as rock surface area and colony density in this study. Each point on the plot represents an observation.
The pattern of the points indicates the type of relationship. A linear pattern suggests a linear relationship that can be modeled with regression. A positive slope indicates that as one variable increases, the other also increases. Conversely, a negative slope implies an inverse relationship.
In a scatter plot, any points that do not follow the general trend are easily identifiable as potential outliers. Observing the plot before conducting any analyses is crucial for several reasons:
  • It gives an initial impression of the relationship's nature and direction.
  • It helps in identifying clusters, gaps, or trends that may not be evident from statistics alone.
  • It assists in detecting outliers or anomalies that require further investigation.
For this exercise, a scatter plot would enable us to visualize the influence of the outlier and verify assumptions about linearity before delving deeper into statistical calculations.

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Most popular questions from this chapter

The article "Some Field Experience in the Use of an Accelerated Method in Estimating 28-Day Strength of Concrete" (J. Amer. Concrete Institut., 1969: 895) considered regressing \(y=28\)-day standard-cured strength (psi) against \(x=\) accelerated strength (psi). Suppose the equation of the true regression line is \(y=1800+1.3 x\). a. What is the expected value of 28-day strength when accelerated strength \(=2500\) ? b. By how much can we expect 28-day strength to change when accelerated strength increases by 1 psi? c. Answer part (b) for an increase of \(100 \mathrm{psi}\). d. Answer part (b) for a decrease of 100 psi.

The article "Increases in Steroid Binding Globulins Induced by Tamoxifen in Patients with Carcinoma of the Breast" \((J\). Endocrinol., 1978: 219-226) reports data on the effects of the drug tamoxifen on change in the level of cortisol-binding globulin (CBG) of patients during treatment. With age \(=x\) and \(\Delta \mathrm{CBG}=y\), summary values are \(n=26, \sum x_{i}=1613, \sum\left(x_{i}-\bar{x}\right)^{2}=3756.96\), \(\sum y_{i}=281.9, \quad \sum\left(y_{i}-\bar{y}\right)^{2}=465.34, \quad\) and \(\sum x_{i} y_{i}=16,731\) a. Compute a \(90 \%\) CI for the true correlation coefficient \(\rho\). b. Test \(H_{0}: \rho=-.5\) versus \(H_{\mathrm{a}}: \rho<-.5\) at level \(.05\). c. In a regression analysis of \(y\) on \(x\), what proportion of variation in change of cortisol-binding globulin level could be explained by variation in patient age within the sample? d. If you decide to perform a regression analysis with age as the dependent variable, what proportion of variation in age is explainable by variation in \(\triangle \mathrm{CBG}\) ?

Suppose that \(x\) and \(y\) are positive variables and that a sample of \(n\) pairs results in \(r \approx 1\). If the sample correlation coefficient is computed for the \(\left(x, y^{2}\right)\) pairs, will the resulting value also be approximately 1? Explain.

If there is at least one \(x\) value at which more than one observation has been made, there is a formal test procedure for testing \(H_{0}: \mu_{Y \cdot x}=\beta_{0}+\beta_{1} x\) for some values \(\beta_{0}, \beta_{1}\) (the true regression function is linear) versus \(H_{\mathrm{a}}: H_{0}\) is not true (the true regression function is not linear) Suppose observations are made at \(x_{1}, x_{2}, \ldots, x_{c}\). Let \(Y_{11}, Y_{12}, \ldots, Y_{1 n_{1}}\) denote the \(n_{1}\) observations when \(x=x_{1} ; \ldots ; Y_{c 1}, Y_{c 2}, \ldots, Y_{c n_{c}}\) denote the \(n_{c}\) observations when \(x=x_{c}\). With \(n=\Sigma n_{i}\) (the total number of observations), SSE has \(n-2\) df. We break SSE into two pieces, SSPE (pure error) and SSLF (lack of fit), as follows: $$ \begin{aligned} \mathrm{SSPE} &=\sum_{i} \sum_{j}\left(Y_{i j}-\bar{Y}_{i} .\right)^{2} \\ &=\sum_{i} \sum_{j} Y_{i j}^{2}-\sum_{i} n_{i}\left(\bar{Y}_{i} .\right)^{2} \end{aligned} $$ $$ \text { SSLF }=\text { SSE }-\text { SSPE } $$ The \(n_{i}\) observations at \(x_{i}\) contribute \(n_{i}-1\) df to SSPE, so the number of degrees of freedom for SSPE is \(\Sigma_{i}\left(n_{i}-1\right)=n-c\) and the degrees of freedom for SSLF is \(n-2-(n-c)=c-2\). Let MSPE \(=\operatorname{SSPE} /(n-c), \operatorname{MSLF}=\operatorname{SSLF} /(c-2) .\) Then it can be shown that whereas \(E(\) MSPE \()=\sigma^{2}\) whether or not \(H_{0}\) is true, \(E\) (MSLF) \(=\sigma^{2}\) if \(H_{0}\) is true and \(E(\) MSLF \()>\sigma^{2}\) if \(H_{0}\) is false. Test statistic: \(F=\) MSLF/MSPE Rejection region: \(f \geq F_{\alpha, c-2, n-c}\) The following data comes from the article "Changes in Growth Hormone Status Related to Body Weight of Growing Cattle" (Growth, 1977: 241-247), with \(x=\) body weight and \(y=\) metabolic clearance rate/ body weight. $$ \begin{aligned} &\begin{array}{l|lllllll} x & 110 & 110 & 110 & 230 & 230 & 230 & 360 \\ \hline y & 235 & 198 & 173 & 174 & 149 & 124 & 115 \end{array}\\\ &\begin{array}{r|rrrrrrr} x & 360 & 360 & 360 & 505 & 505 & 505 & 505 \\ \hline y & 130 & 102 & 95 & 122 & 112 & 98 & 96 \end{array} \end{aligned} $$ (So \(c=4, n_{1}=n_{2}=3, n_{3}=n_{4}=4\).) a. Test \(H_{0}\) versus \(H_{\mathrm{a}}\) at level \(.05\) using the lackof-fit test just described. b. Does a scatter plot of the data suggest that the relationship between \(x\) and \(y\) is linear? How does this compare with the result of part (a)? (A nonlinear regression function was used in the article.)

The flow rate \(y\left(\mathrm{~m}^{3} / \mathrm{min}\right)\) in a device used for airquality measurement depends on the pressure drop \(x\) (in. of water) across the device's filter. Suppose that for \(x\) values between 5 and 20 , the two variables are related according to the simple linear regression model with true regression line \(y=-.12+.095 x\). a. What is the expected change in flow rate associated with a 1-in. increase in pressure drop? Explain. b. What change in flow rate can be expected when pressure drop decreases by 5 in.? c. What is the expected flow rate for a pressure drop of 10 in.? A drop of 15 in.? d. Suppose \(\sigma=.025\) and consider a pressure drop of \(10 \mathrm{in}\). What is the probability that the observed value of flow rate will exceed \(.835\) ? That observed flow rate will exceed .840? e. What is the probability that an observation on flow rate when pressure drop is 10 in. will exceed an observation on flow rate made when pressure drop is 11 in.?

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