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Show that the mle's of \(\beta_{0}\) and \(\beta_{1}\) are indeed the least squares estimates. [Hint: The pdf of \(Y_{i}\) is normal with mean \(\mu_{i}=\beta_{0}+\beta_{1} x_{i}\) and variance \(\sigma^{2} ;\) the likelihood is the product of the \(n\) pdf's.]

Short Answer

Expert verified
The MLEs of \(\beta_0\) and \(\beta_1\) are the least squares estimates.

Step by step solution

01

Understand the Likelihood Function

First, recognize that the problem requires us to find the Maximum Likelihood Estimators (MLE) for \(\beta_0\) and \(\beta_1\). Given the normal distribution, the probability density function (pdf) of \(Y_i\) is \(f(Y_i) = \frac{1}{\sqrt{2\pi\sigma^2}} e^{-\frac{1}{2\sigma^2}(Y_i - (\beta_0 + \beta_1 x_i))^2}\). The likelihood function \(L(\beta_0, \beta_1)\) is the product of individual pdfs: \[L(\beta_0, \beta_1) = \prod_{i=1}^{n} \frac{1}{\sqrt{2\pi\sigma^2}} e^{-\frac{1}{2\sigma^2}(Y_i - (\beta_0 + \beta_1 x_i))^2}\].
02

Form the Log-Likelihood Function

The next step is to take the natural logarithm of the likelihood function to simplify the maximizing process. The log-likelihood function is \( \ln L(\beta_0, \beta_1) = -\frac{n}{2} \ln (2 \pi \sigma^2) - \frac{1}{2\sigma^2} \sum_{i=1}^{n} (Y_i - (\beta_0 + \beta_1 x_i))^2 \).
03

Derive with Respect to Parameters

To find the MLEs, we take partial derivatives of the log-likelihood function with respect to \(\beta_0\) and \(\beta_1\). Set these partial derivatives to zero to find critical points. The derivatives are:- \( \frac{\partial}{\partial \beta_0} = \frac{1}{\sigma^2} \sum_{i=1}^{n} (Y_i - \beta_0 - \beta_1 x_i) = 0 \)- \( \frac{\partial}{\partial \beta_1} = \frac{1}{\sigma^2} \sum_{i=1}^{n} (Y_i - \beta_0 - \beta_1 x_i)x_i = 0 \)
04

Simplify to Least Squares Conditions

Notice that setting these equations to zero is equivalent to solving the normal equations for least squares. The first equation averages the residuals to zero, similar to the mean residual being zero: \(\sum_{i=1}^n (Y_i - \beta_0 - \beta_1 x_i) = 0\). The second equation, \(\sum_{i=1}^{n} x_i(Y_i - \beta_0 - \beta_1 x_i) = 0\), matches the condition for the slope in least squares regression.
05

Conclusion

Recognizing these conditions are the same, we conclude that the Maximum Likelihood Estimators \(\beta_0\) and \(\beta_1\) are indeed the least squares estimates of the regression coefficients.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Least Squares Method
The least squares method is a statistical technique used to determine the best-fit line through a set of data points in a way that minimizes the sum of the squares of the vertical distances (residuals) between the data points and the line. This method has wide applications in regression analysis, and it boils down to finding the line that best represents the given data.
The principle behind the least squares method can be visualized easily. Imagine plotting a scatter plot with several data points on a graph. The goal is to draw a line through these points in such a way that the squared differences between the observed data points and the predicted points on the line are minimized. This best-fit line is often used for predictive purposes in linear models.
  • First, the sum of the squared residuals is calculated. Residuals are the differences between observed values and those predicted by the model.
  • The line is then adjusted, minimizing this sum.
  • This results in a set of linear equations, expressed as 'normal equations.'
When applied, the least squares method solves these normal equations to estimate the coefficients of our regression line, providing the most likely value under the assumptions of the model.
Linear Regression
Linear regression is a statistical method used for modeling the relationship between a dependent variable, often termed as response or target, and one or more independent variables (predictors). In its simplest form, linear regression with one independent variable is referred to as simple linear regression. When multiple variables are involved, it is called multiple linear regression.
The foundational assumption of linear regression is that there is a linear relationship between the input variables and the output variable. The equation typically used in linear regression is:
\[ Y = \beta_0 + \beta_1 X_1 + \beta_2 X_2 + \ldots + \beta_n X_n + \epsilon \]
Where:
  • \( Y \) represents the dependent variable we are trying to predict.
  • \( \beta_0 \) is the intercept.
  • \( \beta_1, \beta_2, \ldots, \beta_n \) are the coefficients of the independent variables.
  • \( X_1, X_2, \ldots, X_n \) represent the independent variables.
  • \( \epsilon \) is the error term.
The aim of linear regression is to estimate the coefficients \( \beta_0, \beta_1, \ldots, \beta_n \) that minimize the residual sum of squares between the observed responses in the dataset and the responses predicted by the linear approximation. This is where the least squares method comes into play, providing the most accurate prediction possible given the linear constraints.
Regression Coefficients
In the context of linear regression, regression coefficients are critical as they define the mathematical relationship between each independent variable and the dependent variable. These coefficients encompass both the intercept (\(\beta_0\)) and the slopes (\(\beta_1, \beta_2, \ldots\)).
The intercept \(\beta_0\) is the value at which the fitted line crosses the y-axis when all independent variables are zero. This term represents the expected mean value of the dependent variable when all predictors are inactive or zero.
The slope coefficients, such as \(\beta_1\), indicate the change in the mean of the dependent variable for a one-unit change in the independent variable, holding all other variables constant. Higher absolute values of these coefficients highlight a greater influence of the respective explanatory variables on the dependent variable.
  • The coefficients are determined through fitting the model using methods like the least squares method, aiming at minimizing prediction errors.
  • The accuracy and significance of these coefficients can be evaluated using statistical tests and metrics, including t-tests and p-values.
In linear regression, the ultimate goal is to use these coefficients to make accurate predictions and gain insights into the relationships that dictate the behavior of the response variable.

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Most popular questions from this chapter

Suppose an investigator has data on the amount of shelf space \(x\) devoted to display of a particular product and sales revenue \(y\) for that product. The investigator may wish to fit a model for which the true regression line passes through \((0,0)\). The appropriate model is \(Y=\beta_{1} x+\varepsilon\). Assume that \(\left(x_{1}, y_{1}\right), \ldots,\left(x_{n}, y_{n}\right)\) are observed pairs generated from this model, and derive the least squares estimator of \(\beta_{1}\). [Hint: Write the sum of squared deviations as a function of \(b_{1}\), a trial value, and use calculus to find the minimizing value of \(b_{1}\).]

If there is at least one \(x\) value at which more than one observation has been made, there is a formal test procedure for testing \(H_{0}: \mu_{Y \cdot x}=\beta_{0}+\beta_{1} x\) for some values \(\beta_{0}, \beta_{1}\) (the true regression function is linear) versus \(H_{\mathrm{a}}: H_{0}\) is not true (the true regression function is not linear) Suppose observations are made at \(x_{1}, x_{2}, \ldots, x_{c}\). Let \(Y_{11}, Y_{12}, \ldots, Y_{1 n_{1}}\) denote the \(n_{1}\) observations when \(x=x_{1} ; \ldots ; Y_{c 1}, Y_{c 2}, \ldots, Y_{c n_{c}}\) denote the \(n_{c}\) observations when \(x=x_{c}\). With \(n=\Sigma n_{i}\) (the total number of observations), SSE has \(n-2\) df. We break SSE into two pieces, SSPE (pure error) and SSLF (lack of fit), as follows: $$ \begin{aligned} \mathrm{SSPE} &=\sum_{i} \sum_{j}\left(Y_{i j}-\bar{Y}_{i} .\right)^{2} \\ &=\sum_{i} \sum_{j} Y_{i j}^{2}-\sum_{i} n_{i}\left(\bar{Y}_{i} .\right)^{2} \end{aligned} $$ $$ \text { SSLF }=\text { SSE }-\text { SSPE } $$ The \(n_{i}\) observations at \(x_{i}\) contribute \(n_{i}-1\) df to SSPE, so the number of degrees of freedom for SSPE is \(\Sigma_{i}\left(n_{i}-1\right)=n-c\) and the degrees of freedom for SSLF is \(n-2-(n-c)=c-2\). Let MSPE \(=\operatorname{SSPE} /(n-c), \operatorname{MSLF}=\operatorname{SSLF} /(c-2) .\) Then it can be shown that whereas \(E(\) MSPE \()=\sigma^{2}\) whether or not \(H_{0}\) is true, \(E\) (MSLF) \(=\sigma^{2}\) if \(H_{0}\) is true and \(E(\) MSLF \()>\sigma^{2}\) if \(H_{0}\) is false. Test statistic: \(F=\) MSLF/MSPE Rejection region: \(f \geq F_{\alpha, c-2, n-c}\) The following data comes from the article "Changes in Growth Hormone Status Related to Body Weight of Growing Cattle" (Growth, 1977: 241-247), with \(x=\) body weight and \(y=\) metabolic clearance rate/ body weight. $$ \begin{aligned} &\begin{array}{l|lllllll} x & 110 & 110 & 110 & 230 & 230 & 230 & 360 \\ \hline y & 235 & 198 & 173 & 174 & 149 & 124 & 115 \end{array}\\\ &\begin{array}{r|rrrrrrr} x & 360 & 360 & 360 & 505 & 505 & 505 & 505 \\ \hline y & 130 & 102 & 95 & 122 & 112 & 98 & 96 \end{array} \end{aligned} $$ (So \(c=4, n_{1}=n_{2}=3, n_{3}=n_{4}=4\).) a. Test \(H_{0}\) versus \(H_{\mathrm{a}}\) at level \(.05\) using the lackof-fit test just described. b. Does a scatter plot of the data suggest that the relationship between \(x\) and \(y\) is linear? How does this compare with the result of part (a)? (A nonlinear regression function was used in the article.)

The following data on \(y=\) glucose concentration (g/L) and \(x=\) fermentation time (days) for a particular blend of malt liquor was read from a scatter plot in the article "Improving Fermentation Productivity with Reverse Osmosis" (Food Tech., 1984: 92-96): $$ \begin{array}{l|cccccccc} x & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline y & 74 & 54 & 52 & 51 & 52 & 53 & 58 & 71 \end{array} $$ a. Verify that a scatter plot of the data is consistent with the choice of a quadratic regression model. b. The estimated quadratic regression equation is \(y=84.482-15.875 x+1.7679 x^{2}\). Predict the value of glucose concentration for a fermentation time of 6 days, and compute the corresponding residual. c. Using SSE \(=61.77\), what proportion of observed variation can be attributed to the quadratic regression relationship? d. The \(n=8\) standardized residuals based on the quadratic model are \(1.91,-1.95,-.25\), \(.58, .90, .04,-.66\), and .20. Construct a plot of the standardized residuals versus \(x\) and a normal probability plot. Do the plots exhibit any troublesome features? e. The estimated standard deviation of \(\hat{\mu}_{Y \cdot 6}\)-that is, \(\hat{\beta}_{0}+\hat{\beta}_{1}(6)+\hat{\beta}_{2}(36)-\) is 1.69. Compute a \(95 \%\) CI for \(\mu_{Y \cdot 6}\). f. Compute a \(95 \%\) PI for a glucose concentration observation made after 6 days of fermentation time.

The article "Behavioural Effects of Mobile Telephone Use During Simulated Driving" (Ergonomics, 1995: 2536-2562) reported that for a sample of 20 experimental subjects, the sample correlation coefficient for \(x=\) age and \(y=\) time since the subject had acquired a driving license (yr) was \(.97\). Why do you think the value of \(r\) is so close to 1 ? (The article's authors gave an explanation.)

Hydrogen content is conjectured to be an important factor in porosity of aluminum alloy castings. The article "The Reduced Pressure Test as a Measuring Tool in the Evaluation of Porosity/Hydrogen Content in A1-7 Wt Pct Si-10 Vol Pct SiC(p) Metal Matrix Composite" (Metallurg. Trans., 1993: 1857-1868) gives the accompanying data on \(x=\) content and \(y=\) gas porosity for one particular measurement technique. $$ \begin{array}{l|lllllll} x & .18 & .20 & .21 & .21 & .21 & .22 & .23 \\ \hline y & .46 & .70 & .41 & .45 & .55 & .44 & .24 \\ x & .23 & .24 & .24 & .25 & .28 & .30 & .37 \\ \hline y & .47 & .22 & .80 & .88 & .70 & .72 & .75 \end{array} $$ MINITAB gives the following output in response to a CORRELATION command: Correlation of Hydrcon and Porosity \(=0.449\) a. Test at level \(.05\) to see whether the population correlation coefficient differs from 0 . b. If a simple linear regression analysis had been carried out, what percentage of observed variation in porosity could be attributed to the model relationship?

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