/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 121 A sample of \(n=20\) companies w... [FREE SOLUTION] | 91Ó°ÊÓ

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A sample of \(n=20\) companies was selected, and the values of \(y=\) stock price and \(k=15\) predictor variables (such as quarterly dividend, previous year's earnings, and debt ratio) were determined. When the multiple regression model using these 15 predictors was fit to the data, \(R^{2}=.90\) resulted. a. Does the model appear to specify a useful relationship between \(y\) and the predictor variables? Carry out a test using significance level \(.05\). [Hint: The \(F\) critical value for 15 numerator and 4 denominator df is \(5.86\).] b. Based on the result of part (a), does a high \(R^{2}\) value by itself imply that a model is useful? Under what circumstances might you be suspicious of a model with a high \(R^{2}\) value? c. With \(n\) and \(k\) as given previously, how large would \(R^{2}\) have to be for the model to be judged useful at the \(.05\) level of significance?

Short Answer

Expert verified
a. Yes, the model is useful. b. No, a high R² alone doesn't ensure usefulness. c. R² must be > 0.8805.

Step by step solution

01

Determine the null and alternative hypotheses

The null hypothesis \(H_0\) is that there is no relationship between the stock price \(y\) and the predictor variables. The alternative hypothesis \(H_a\) is that there is a significant relationship. Mathematically, \(H_0: \beta_1 = \beta_2 = \ldots = \beta_k = 0\) and \(H_a:\) at least one \(\beta_i eq 0\).
02

Calculate the F-statistic

In multiple regression, the \(F\)-statistic is used to test the overall significance of the model. It is calculated using the formula \[ F = \frac{R^2 / k}{(1 - R^2) / (n - k - 1)} \]. For this problem, \(R^2 = 0.90\), \(k = 15\), and \(n = 20\). Substitute these values to calculate \(F\):\[ F = \frac{0.90 / 15}{(1 - 0.90) / (20 - 15 - 1)} = \frac{0.06}{0.01} = 6.0 \].
03

Compare the F-statistic with the critical value

The critical \(F\) value at a 0.05 significance level with \(15\) numerator and \(4\) denominator degrees of freedom is given as \(5.86\). Since the calculated \(F\)-statistic \(6.0\) is greater than the critical value \(5.86\), we reject the null hypothesis.
04

Evaluate usefulness of R-squared

A high \(R^2\) such as 0.90 suggests that the model explains 90% of the variance, which generally indicates usefulness. However, a high \(R^2\) does not always imply the model is good. It might be due to overfitting, especially when \(n\) is not much larger than \(k\). Check for overfitting by evaluating model assumptions and potential multicollinearity issues.
05

Determine necessary R-squared for model usefulness

To find the minimum \(R^2\) needed for significance, set the critical value \(F = 5.86\) in the \(F\)-statistic formula: \[ F = \frac{R^2 / k}{(1 - R^2) / (n - k - 1)} \]. Solve for \(R^2\):\[ 5.86 = \frac{R^2 / 15}{(1 - R^2) / 4} \]. Rearranging gives \(R^2 = 0.8805\). Thus, an \(R^2 > 0.8805\) is required for a significant model at a 0.05 significance level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions about population parameters based on a sample. In the context of multiple regression, hypothesis testing helps us determine if there is a relationship between the dependent variable (in this case, the stock price \(y\)) and the independent variables (predictors like quarterly dividend, earnings, and debt ratio).

The process begins with defining two opposing hypotheses: the null hypothesis \(H_0\) and the alternative hypothesis \(H_a\). Here, \(H_0: \beta_1 = \beta_2 = \ldots = \beta_k =0\) suggests no relationship between \(y\) and the predictors, while \(H_a\) indicates at least one predictor does contribute significantly, meaning \(\beta_i eq 0\).

Using hypothesis testing in regression analysis, we aim to understand if the model captures a true relationship or if the observed pattern is due to random chance. To assess this, we calculate test statistics, like the \(F\)-statistic, which compares the explained variance to the unexplained variance, helping us decide whether or not to reject \(H_0\).
F-test
The \(F\)-test is a key tool in multiple regression analysis. It evaluates whether a group of variables in the model are jointly significant predictors of the dependent variable. This is done by comparing the model's performance with and without the predictors.

In our example, the \(F\)-statistic is calculated using the formula \( F = \frac{R^2 / k}{(1 - R^2) / (n - k - 1)}\). With \(n=20\) and \(k=15\), we calculate \(F = 6.0\). This statistic is then compared to a critical \(F\) value, which for 15 numerator and 4 denominator degrees of freedom at a significance level of 0.05 is 5.86.

Since our calculated \(F\)-statistic is larger than the critical \(F\), \(6.0 > 5.86\), we reject the null hypothesis \(H_0\). This implies that the predictors as a group significantly contribute to explaining the variability in the stock prices.
R-squared
\(R^2\), or R-squared, is a statistical measure representing the proportion of variance in the dependent variable that's predictable from the independent variables. It ranges from \(0\) to \(1\), where \(1\) indicates a perfect fit. In multiple regression, a high \(R^2\), like \(0.90\), suggests a strong relationship between predictors and the response variable.

However, an important caveat with R-squared is that it always increases when additional variables are added to the model. This means a high \(R^2\) value may give a false implication of a good model fit, potentially due to overfitting. Overfitting happens when the model is too complex and starts capturing the noise rather than the actual data pattern.

Thus, analysts should not solely rely on \(R^2\) to judge model quality. Instead, they should also consider adjusted \(R^2\), which adjusts for the number of predictors in the model, making it a more reliable metric.
Overfitting
Overfitting occurs in regression analysis when a model is excessively complex, fitting the idiosyncrasies of a dataset rather than reflecting the true relationship. While a high \(R^2\) value might initially appear to be positive, it can be a sign of overfitting, particularly when the sample size \(n\) is not significantly larger than the number of predictors \(k\).

Overfitting compromises the predictive performance on unseen data, as the model has essentially memorized the training data's noise. To mitigate overfitting, one could:
  • Use simpler models with fewer predictor variables.
  • Implement cross-validation techniques to validate the model's generalizability.
  • Apply penalties such as LASSO or Ridge regression that discourage overly complex models.
When constructing models, it's crucial to ensure that complexity aligns with the amount of data available, balancing a model's simplicity and its ability to generalize well to new data.

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Most popular questions from this chapter

Bivariate data often arises from the use of two different techniques to measure the same quantity. As an example, the accompanying observations on \(x=\) hydrogen concentration (ppm) using a gas chromatography method and \(y=\) concentration using a new sensor method were read from a graph in the article "A New Method to Measure the Diffusible Hydrogen Content in Steel Weldments Using a Polymer Electrolyte-Based Hydrogen Sensor" (Welding Res., July 1997: \(251 \mathrm{~s}-256 \mathrm{~s})\). $$ \begin{array}{l|llllllllll} x & 47 & 62 & 65 & 70 & 70 & 78 & 95 & 100 & 114 & 118 \\ \hline y & 38 & 62 & 53 & 67 & 84 & 79 & 93 & 106 & 117 & 116 \\ x & 124 & 127 & 140 & 140 & 140 & 150 & 152 & 164 & 198 & 221 \\ \hline y & 127 & 114 & 134 & 139 & 142 & 170 & 149 & 154 & 200 & 215 \end{array} $$ Construct a scatter plot. Does there appear to be a very strong relationship between the two types of concentration measurements? Do the two methods appear to be measuring roughly the same quantity? Explain your reasoning.

When a scatter plot of bivariate data shows a pattern resembling an exponentially increasing or decreasing curve, the following multiplicative exponential model is often used: \(Y=\alpha e^{\beta x} \cdot \varepsilon\). a. What does this multiplicative model imply about the relationship between \(Y^{\prime}=\ln (Y)\) and \(x\) ? [Hint: take logs on both sides of the model equation and let \(\beta_{0}=\ln (\alpha), \beta_{1}=\beta, \varepsilon^{\prime}=\ln\) \((\varepsilon)\), and suppose that \(\varepsilon\) has a lognormal distribution.] b. The accompanying data resulted from an investigation of how ethylene content of lettuce seeds \((y\), in \(\mathrm{nL} / \mathrm{g}\) dry \(\mathrm{wt})\) varied with exposure time \((x\), in min) to an ethylene absorbent ("Ethylene Synthesis in Lettuce Seeds: Its Physiological Significance," Plant Physiol., 1972: 719-722). $$ \begin{array}{c|ccccccccccc} x & 2 & 20 & 20 & 30 & 40 & 50 & 60 & 70 & 80 & 90 & 100 \\ \hline y & 408 & 274 & 196 & 137 & 90 & 78 & 51 & 40 & 30 & 22 & 15 \end{array} $$ Fit the simple linear regression model to this data, and check model adequacy using the residuals. c. Is a scatter plot of the data consistent with the exponential regression model? Fit this model by first carrying out a simple linear regression analysis using \(\ln (y)\) as the dependent variable and \(x\) as the independent variable. How good a fit is the simple linear regression model to the "transformed" data [the \((x, \ln (y))\) pairs]? What are point estimates of the parameters \(\alpha\) and \(\beta ?\) d. Obtain a \(95 \%\) prediction interval for ethylene content when exposure time is \(50 \mathrm{~min}\). [Hint: first obtain a PI for \(\ln (y)\) based on the simple linear regression carried out in (c).]

Suppose that in a certain chemical process the reaction time \(y\) (hr) is related to the temperature \(\left({ }^{\circ} \mathrm{F}\right)\) in the chamber in which the reaction takes place according to the simple linear regression model with equation \(y=5.00-.01 x\) and \(\sigma=.075\). a. What is the expected change in reaction time for a \(1^{\circ} \mathrm{F}\) increase in temperature? For a \(10^{\circ} \mathrm{F}\) increase in temperature? b. What is the expected reaction time when temperature is \(200^{\circ} \mathrm{F}\) ? When temperature is \(250^{\circ} \mathrm{F}\) ? c. Suppose five observations are made independently on reaction time, each one for a temperature of \(250^{\circ} \mathrm{F}\). What is the probability that all five times are between \(2.4\) and \(2.6 \mathrm{~h}\) ? d. What is the probability that two independently observed reaction times for temperatures \(1^{\circ}\) apart are such that the time at the higher temperature exceeds the time at the lower temperature?

The article "Validation of the Rockport Fitness Walking Test in College Males and Females" (Res. Q. Exercise Sport, 1994: 152-158) recommended the following estimated regression equation for relating \(y=\mathrm{VO}_{2} \max (\mathrm{L} / \mathrm{min}\), a measure of cardiorespiratory fitness) to the predictors \(x_{1}\) \(=\) gender (female \(=0\), male \(=1\) ), \(x_{2}=\) weight (lb), \(x_{3}=1\)-mile walk time (min), and \(x_{4}=\) heart rate at the end of the walk (beats/min): $$ \begin{aligned} y=& 3.5959+.6566 x_{1}+.0096 x_{2} \\ &-.0996 x_{3}-.0080 x_{4} \end{aligned} $$ a. How would you interpret the estimated coefficient \(-.0996\) ? b. How would you interpret the estimated coefficient .6566? c. Suppose that an observation made on a male whose weight was \(170 \mathrm{lb}\), walk time was \(11 \mathrm{~min}\), and heart rate was 140 beats \(/ \mathrm{min}\) resulted in \(\mathrm{VO}_{2} \mathrm{max}=3.15\). What would you have predicted for \(\mathrm{VO}_{2}\) max in this situation, and what is the value of the corresponding residual? d. Using SSE \(=30.1033\) and SST \(=102.3922\), what proportion of observed variation in \(\mathrm{VO}_{2} \max\) can be attributed to the model relationship? e. Assuming a sample size of \(n=20\), carry out a test of hypotheses to decide whether the chosen model specifies a useful relationship between \(\mathrm{VO}_{2} \max\) and at least one of the predictors.

The invasive diatom species Didymosphenia Geminata has the potential to inflict substantial ecological and economic damage in rivers. The article "Substrate Characteristics Affect Colonization by the Bloom-Forming Diatom Didymosphenia Geminata" (Aquatic Ecology, 2010: 33-40) described an investigation of colonization behavior. One aspect of particular interest was whether \(y=\) colony density was related to \(x=\) rock surface area. The article contained a scatter plot and summary of a regression analysis. Here is representative data: $$ \begin{aligned} &\begin{array}{c|ccccccc} x & 50 & 71 & 55 & 50 & 33 & 58 & 79 \\ \hline y & 152 & 1929 & 48 & 22 & 2 & 5 & 35 \end{array}\\\ &\begin{array}{l|cccccccc} x & 26 & 69 & 44 & 37 & 70 & 20 & 45 & 49 \\ \hline y & 7 & 269 & 38 & 171 & 13 & 43 & 185 & 25 \end{array} \end{aligned} $$ a. Fit the simple linear regression model to this data, and then calculate and interpret the coefficient of determination. b. Carry out a test of hypotheses to determine whether there is a useful linear relationship between density and rock area. c. The second observation has a very extreme \(y\) value (in the full data set consisting of 72 observations, there were two of these). This observation may have had a substantial impact on the fit of the model and subsequent conclusions. Eliminate it and redo parts (a) and (b). What do you conclude?

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