/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 103 How does energy intake compare t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

How does energy intake compare to energy expenditure? One aspect of this issue was considered in the article "Measurement of Total Energy Expenditure by the Doubly Labelled Water Method in Professional Soccer Players" (J.Sports Sci., 2002: 391-397), which contained the accompanying data (MJ/day). $$ \begin{array}{lccccccc} \text { Player } & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \text { Expenditure } & 14.4 & 12.1 & 14.3 & 14.2 & 15.2 & 15.5 & 17.8 \\ \text { Intake } & 14.6 & 9.2 & 11.8 & 11.6 & 12.7 & 15.0 & 16.3 \end{array} $$ Test to see whether there is a significant difference between intake and expenditure. Does the conclusion depend on whether a significance level of \(.05, .01\), or \(.001\) is used?

Short Answer

Expert verified
The significant difference between energy intake and expenditure depends on the significance level used. The null hypothesis might be rejected at a more relaxed significance level (e.g., 0.05) but not at a stricter level (e.g., 0.001) due to the smaller tolerance for error.

Step by step solution

01

Define the Hypotheses

To test if there is a significant difference between energy intake and expenditure, we define our null hypothesis as \( H_0: \mu_d = 0 \), which states that the mean difference between intake and expenditure is zero. The alternative hypothesis \( H_a: \mu_d eq 0 \) suggests that there is a non-zero mean difference.
02

Calculate the Differences

Calculate the difference between energy intake and expenditure for each player. The differences are: Player 1: 14.6 - 14.4 = 0.2, Player 2: 9.2 - 12.1 = -2.9, Player 3: 11.8 - 14.3 = -2.5, Player 4: 11.6 - 14.2 = -2.6, Player 5: 12.7 - 15.2 = -2.5, Player 6: 15.0 - 15.5 = -0.5, Player 7: 16.3 - 17.8 = -1.5.
03

Calculate the Mean and Standard Deviation of Differences

The mean of the differences \( \bar{d} \) is calculated as \( \frac{0.2 - 2.9 - 2.5 - 2.6 - 2.5 - 0.5 - 1.5}{7} = -1.89 \). Calculate the standard deviation \( s_d \) of these differences using the formula \( s_d = \sqrt{\frac{\sum (d_i - \bar{d})^2}{n-1}} \).
04

Perform the T-Test

Calculate the test statistic \( t = \frac{\bar{d}}{s_d/\sqrt{n}} \), where \( n \) is the number of players (7 in this case). Compare the calculated t-value to the critical t-values from a t-distribution table. For different significance levels (\(0.05, 0.01, 0.001\)), find the critical t-values corresponding to \( n-1 = 6 \) degrees of freedom.
05

Decision Making

If the absolute value of the calculated t-statistic exceeds the critical value from the t-distribution table for any significance level \( \alpha \), reject the null hypothesis \( H_0 \). Else, fail to reject \( H_0 \). This determines whether the difference is statistically significant.
06

Interpret the Results

Interpret the results from the t-test: If the null hypothesis is rejected, it suggests there is a significant difference between intake and expenditure. If not rejected, there is no statistically significant difference between these two metrics at the chosen significance level.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-test
The t-test is a statistical method used to determine if there is a significant difference between the means of two groups. In our context, it helps compare the energy intake and expenditure among professional soccer players to see if these two sets of data exhibit any meaningful difference.

To conduct a t-test, we start by defining our hypotheses. The null hypothesis ( H_0 ) proposes that there is no difference between the two means. In our exercise about energy balance, it means the average difference between intake and expenditure is zero. The alternative hypothesis ( H_a ) suggests otherwise, indicating that a difference does exist.

The important components of a t-test include the calculated t-value, which represents how different the means are given the variability of the data. A larger absolute t-value suggests more significant differences. We compare this calculated t-value to a critical t-value from the t-distribution to determine if the difference is statistically significant.
statistical significance
Statistical significance is a concept used in hypothesis testing to determine if the results of a study are likely to be true or occurred merely by chance. When we talk about statistical significance in this context, it refers to whether the difference between energy intake and expenditure in players is real or just random variation.
  • If a test is statistically significant, it means we have enough evidence to suggest a real difference exists, not just due to random sampling error.
  • A common practice is to compare the t-value with critical values at various significance levels like 0.05, 0.01, and 0.001. These levels represent the probability thresholds for mistakenly rejecting the null hypothesis.
Assuming different significance levels can affect our conclusions. If our calculated t-value exceeds the critical t-value at a certain level, we reject the null hypothesis, indicating statistical significance and a true difference between intake and expenditure of the soccer players. If not, we fail to reject the null hypothesis, suggesting no significant difference at that level.
paired samples
Paired samples involve two related sets of data, often collected from the same subjects, under different conditions or at different times. In the context of our exercise, the energy intake and expenditure data for each soccer player are paired samples because they reflect two related measurements from the same individuals.

Conducting a t-test for paired samples is advantageous because it accounts for potential variability between subjects, focusing the analysis solely on the differences caused by the conditions being compared—in this case, energy intake versus expenditure.

Here, we calculate the difference in energy intake and expenditure for each player and then examine these differences to assess any systematic discrepancies. The paired nature of the data helps reduce confounding effects and highlights genuine differences between the two metrics owing to their close link to the same subjects.
energy balance in sports
Energy balance in sports is crucial for athletes, as it directly impacts their performance and recovery. This concept revolves around maintaining a balance between energy intake (what is consumed through food and beverages) and energy expenditure (what is burned through physical activity and resting metabolism).
  • A positive energy balance occurs when intake exceeds expenditure, which can lead to weight gain or increased energy reserves.
  • A negative energy balance occurs when expenditure exceeds intake, potentially leading to weight loss or depletion of energy stores.
Athletes, like soccer players, need to carefully manage their energy intake and expenditure to optimize their performance and health. Mismanagement can lead to fatigue, reduced performance, or even injury.
In this exercise, by analyzing and comparing the energy intake and expenditure, sports scientists aim to ensure players are consuming enough energy to match their expenditure, supporting both performance and recovery.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An experiment was carried out to compare various properties of cotton/polyester spun yarn finished with softener only and yarn finished with softener plus 5\% DP-resin ("Properties of a Fabric Made with Tandem Spun Yarns," Textile Res. \(J ., 1996: 607-611)\). One particularly important characteristic of fabric is its durability, that is, its ability to resist wear. For a sample of 40 softener-only specimens, the sample mean stoll-flex abrasion resistance (cycles) in the filling direction of the yarn was \(3975.0\), with a sample standard deviation of \(245.1\). Another sample of 40 softener-plus specimens gave a sample mean and sample standard deviation of \(2795.0\) and \(293.7\), respectively. Calculate a confidence interval with confidence level \(99 \%\) for the difference between true average abrasion resistances for the two types of fabrics. Does your interval provide convincing evidence that true average resistances differ for the two types of fabrics? Why or why not?

Using the traditional formula, a \(95 \%\) CI for \(p_{1}-p_{2}\) is to be constructed based on equal sample sizes from the two populations. For what value of \(n(=m)\) will the resulting interval have width at most \(.1\) irrespective of the results of the sampling?

Torsion during hip external rotation (ER) and extension may be responsible for certain kinds of injuries in golfers and other athletes. The article "Hip Rotational Velocities during the Full Golf Swing" (J. Sport Sci. Med., 2009: 296-299) reported on a study in which peak ER velocity and peak IR (internal rotation) velocity (both in \(\mathrm{deg} / \mathrm{s}\) ) were determined for a sample of 15 female collegiate golfers during their swings. The following data was supplied by the article's authors. a. Is it plausible that the differences came from a normally distributed population? b. The article reported that Mean \((\pm S D)=\) \(-145.3(68.0)\) for ER velocity and = \(-227.8(96.6)\) for IR velocity. Based just on this information, could a test of hypotheses about the difference between true average IR velocity and true average ER velocity be carried out? Explain. c. Do an appropriate hypothesis test about the difference between true average IR velocity and true average ER velocity and interpret the result.

A study of male navy enlisted personnel was reported in the Bloomington, Illinois, Daily Pantagraph, Aug. 23, 1993. It was found that 90 of 231 left- handers had been hospitalized for injuries, whereas 623 of 2148 right-handers had been hospitalized for injuries. Test for equal population proportions at the \(.01\) level, find the \(P\)-value for the test, and interpret your results. Can it be concluded that there is a causal relationship between handedness and proneness to injury? Explain.

Expert and amateur pianists were compared in a study "Maintaining Excellence: Deliberate Practice and Elite Performance in Young and Older Pianists" (J. Exp. Psychol. Gen., 1996: 331-340). The researchers used a keyboard that allowed measurement of the force applied by a pianist in striking a key. All 48 pianists played Prelude Number 1 from Bach's Well-Tempered Clavier. For 24 amateur pianists the mean force applied was \(74.5\) with standard deviation \(6.29\), and for 24 expert pianists the mean force was \(81.8\) with standard deviation 8.64. Do expert pianists hit the keys harder? Assuming normally distributed data, state and test the relevant hypotheses, and interpret the results.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.