/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 An increase in the rate of consu... [FREE SOLUTION] | 91Ó°ÊÓ

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An increase in the rate of consumer savings frequently is tied to a lack of confidence in the economy and is said to be an indicator of a recessional tendency in the economy. A random sampling of \(n=200\) savings accounts in a local community showed the mean increase in savings account values to be \(7.2 \%\) over the past 12 months, with standard deviation \(5.6 \% .\) Estimate the mean percentage increase in savings account values over the past 12 months for depositors in the community. Place a bound on your error of estimation.

Short Answer

Expert verified
The mean percentage increase in savings accounts is between 6.424% and 7.976% with a margin of error of 0.776%.

Step by step solution

01

Identify the Known Values

We need to estimate the mean percentage increase and the margin of error. We know the sample mean \( \bar{x} = 7.2\% \), the sample standard deviation \( s = 5.6\% \), and the sample size \( n = 200 \).
02

Determine the Critical Value

Since the sample size is large (\(n=200\)), we use the standard normal distribution to find the critical value. For a 95% confidence interval, the critical value \( z \) is approximately 1.96.
03

Calculate the Standard Error

The standard error \( SE \) of the mean is calculated using the formula \( SE = \frac{s}{\sqrt{n}} \). Substituting the known values gives \( SE = \frac{5.6}{\sqrt{200}} \approx 0.396 \).
04

Calculate the Margin of Error

The margin of error \( ME \) is calculated using the formula \( ME = z \times SE \). Substituting the values, we have \( ME = 1.96 \times 0.396 \approx 0.776 \).
05

Establish the Confidence Interval

The confidence interval is found by adding and subtracting the margin of error from the sample mean. Thus, the interval is \( 7.2 - 0.776 \) to \( 7.2 + 0.776 \), resulting in \( (6.424\%, 7.976\%) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, often denoted as \( \bar{x} \), represents the average value from a set of samples. In statistical terms, it is the sum of all observations divided by the number of observations in the sample. For example, if you have collected data from 200 savings account increases and calculated that their mean is 7.2%, this 7.2% is your sample mean.
The sample mean provides a useful estimate of the population mean, which is the average you would expect if you could measure the entire population. However, because it is based on a sample, this mean is only an estimate and has some associated uncertainty.
Understanding the sample mean is crucial because it forms the basis of constructing a confidence interval, which describes the range within which we might expect the true population mean to fall.
Standard Error
The standard error (SE) measures the variability or dispersion of the sample mean. It describes how much the sample mean would vary from one sample to another if you were to repeat your sampling procedure many times. The formula for the standard error of the mean is:
  • \( SE = \frac{s}{\sqrt{n}} \)
where \( s \) is the sample standard deviation and \( n \) is the sample size.
In our case with a sample size of 200 and a standard deviation of 5.6%, the standard error is about 0.396%.
The standard error is crucial for constructing a confidence interval, as it helps you determine the margin of error, showing how much your sample mean can reasonably vary within the population mean.
Margin of Error
The margin of error (ME) quantifies the range of values below and above your sample mean that will likely include the true population mean. It reflects how precise your estimate is, taking into account variability due to the sample size and sample standard deviation.
The margin of error is computed as follows:
  • \( ME = z \times SE \)
where \( z \) is the critical value from the standard normal distribution for the desired confidence level, and \( SE \) is the standard error.
For instance, with a 95% confidence level, the critical value \( z \) is typically 1.96. Using the previous calculation, this results in a margin of error of approximately 0.776%.
This means that the true mean increase in the community's savings accounts is expected to lie within 0.776% above or below the calculated sample mean (7.2%).
Critical Value
The critical value is a factor used to calculate the margin of error and, consequently, the confidence interval. It is determined by the desired confidence level, which reflects how certain you want to be that the interval contains the true population mean.
For most practical purposes, when the sample size is large, the critical value is derived from the standard normal distribution. For instance, a 95% confidence level, which is common in statistics, corresponds to a critical value (\( z \)) of approximately 1.96. This critical value indicates the number of standard deviations a data point must be from the mean for the data to be considered sufficiently close within the desired confidence level.
Understanding the critical value is crucial, as it helps balance your need for precision (small margin of error) against your confidence level (how sure you are of your estimate). The critical value, combined with the standard error, shapes the ultimate size of the confidence interval.

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Most popular questions from this chapter

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