/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Let \(Y_{1}, Y_{2}, \ldots, Y_{n... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(Y_{1}, Y_{2}, \ldots, Y_{n}\) denote a random sample of size \(n\) from a population whose density is given by $$f(y)=\left\\{\begin{array}{ll} 3 \beta^{3} y^{-4}, & \beta \leq y \\ 0, & \text { elsewhere } \end{array}\right.$$ where \(\beta>0\) is unknown. (This is one of the Pareto distributions introduced in Exercise \(6.18 .\) ) Consider the estimator \(\widehat{\beta}=\min \left(Y_{1}, Y_{2}, \ldots, Y_{n}\right)\) a. Derive the bias of the estimator \(\widehat{\beta}\). $$\text { b. Derive } \operatorname{MSE}(\widehat{\beta})$$

Short Answer

Expert verified
The bias of \(\widehat{\beta}\) is \(\frac{\beta}{n-1}\), and the MSE is \(\frac{\beta^2}{(n-1)(n-2)} + \frac{\beta^2}{(n-1)^2}\)."

Step by step solution

01

Understand the Estimator and Distribution

We are given an estimator \(\widehat{\beta} = \min(Y_1, Y_2, \ldots, Y_n)\) for the Pareto distribution. The probability density function is valid for \(y \geq \beta\). Thus, \(\widehat{\beta}\) estimates the smallest observed value in our sample, \(\beta\).
02

Derive the Bias - Definition of Bias

Bias is defined as the expected value of the estimator minus the true parameter value, i.e., \(\text{Bias}(\widehat{\beta}) = E[\widehat{\beta}] - \beta\). We need to find \(E[\widehat{\beta}]\) for the given Pareto distribution.
03

Calculate the CDF of the Minimum

For the minimum of a sample from a continuous distribution, the cumulative distribution function (CDF) of \(\hat{\beta} = \min(Y_1, Y_2, \ldots, Y_n)\) is given by \(P(\widehat{\beta} \leq y) = 1 - (1 - P(Y_i \leq y))^n\). Here, \(P(Y_i \leq y) = 1 - (\beta/y)^3\) for \(y \geq \beta\).
04

Find the PDF of the Minimum

Differentiate the CDF of \(\widehat{\beta}\) with respect to \(y\) to get the probability density function (PDF): \(f_{\widehat{\beta}}(y) = 3n\beta^3 y^{-(3n+1)}\) for \(y \geq \beta\).
05

Calculate the Expected Value of the Minimum

The expected value \(E[\widehat{\beta}]\) can be calculated as \(E[\widehat{\beta}] = \int_{\beta}^{\infty} y f_{\widehat{\beta}}(y) \, dy\). Performing this integration results in \(E[\widehat{\beta}] = \beta \frac{n}{n-1}\), assuming \(n > 1\).
06

Derive the Bias Expression

Substituting the expected value in the bias formula, we get \(\text{Bias}(\widehat{\beta}) = \beta \frac{n}{n-1} - \beta = \frac{\beta}{n-1}\).
07

Calculate the Variance

The variance of \(\widehat{\beta}\) is calculated using \(\text{Var}(\widehat{\beta}) = E[\widehat{\beta}^2] - (E[\widehat{\beta}])^2\). Compute \(E[\widehat{\beta}^2]\) using \(E[\widehat{\beta}^2] = \int_{\beta}^{\infty} y^2 f_{\widehat{\beta}}(y) \, dy\). This integration yields \(E[\widehat{\beta}^2] = \beta^2 \frac{n}{n-2}\), assuming \(n > 2\).
08

Solve for Variance

Use \(E[\widehat{\beta}] = \beta \frac{n}{n-1}\) to find variance: \(\text{Var}(\widehat{\beta}) = \frac{\beta^2 n}{n-2} - \left(\frac{\beta n}{n-1}\right)^2\). Simplify to get \(\text{Var}(\widehat{\beta}) = \frac{\beta^2}{(n-1)(n-2)}\).
09

Compute the Mean Squared Error (MSE)

The MSE of the estimator \(\widehat{\beta}\) is defined as \(\text{MSE}(\widehat{\beta}) = \text{Var}(\widehat{\beta}) + (\text{Bias}(\widehat{\beta}))^2\). Substitute the expressions we found: \(\text{MSE}(\widehat{\beta}) = \frac{\beta^2}{(n-1)(n-2)} + \frac{\beta^2}{(n-1)^2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bias of Estimator
The bias of an estimator helps us understand how accurately it can predict the true value of a parameter. It's defined simply as the difference between the expected value of the estimator and the actual parameter value. In mathematical terms, this is expressed as \( \text{Bias}(\widehat{\beta}) = E[\widehat{\beta}] - \beta \).

To derive the bias in our given scenario with the Pareto distribution, we need to calculate the expected value \( E[\widehat{\beta}] \). Using the proven steps, we discover that \( E[\widehat{\beta}] = \beta \frac{n}{n-1} \). This means the estimator's expected value inherently has some bias away from the true value \( \beta \).

So, by substituting this into our bias formula, we find that \( \text{Bias}(\widehat{\beta}) = \frac{\beta}{n-1} \). This indicates that as the sample size \( n \) increases, the bias decreases, meaning that larger samples provide more accurate estimates of \( \beta \).
Mean Squared Error
Mean Squared Error (MSE) is a key measure of an estimator's quality. It combines both bias and variability of an estimator into a single number. Essentially, MSE provides a comprehensive picture of how concentrated or dispersed the estimator values are around the actual parameter.

The MSE is calculated as the sum of the variance of the estimator and its bias squared: \( \text{MSE}(\widehat{\beta}) = \text{Var}(\widehat{\beta}) + (\text{Bias}(\widehat{\beta}))^2 \).

For our Pareto distribution example, we already derived both components:\( \text{Var}(\widehat{\beta}) = \frac{\beta^2}{(n-1)(n-2)} \) and \( \text{Bias}(\widehat{\beta}) = \frac{\beta}{n-1} \).

Plugging these into the MSE formula, we obtain:
  • \( \text{MSE}(\widehat{\beta}) = \frac{\beta^2}{(n-1)(n-2)} + \frac{\beta^2}{(n-1)^2} \)

This formula illustrates how MSE decreases as \( n \) increases, indicating more reliable estimates with larger samples.
Probability Density Function
A Probability Density Function (PDF) is crucial for understanding the likelihood of different outcomes for continuous random variables. It depicts how probabilities of values are distributed across different points in a random variable's scale.

In the given Pareto distribution, the PDF is defined as \( f(y) = 3 \beta^3 y^{-4} \) for \( y \geq \beta \). This function sharply declines as \( y \) increases, demonstrating less probability mass as you move farther from the minimum threshold \( \beta \).

To derive the PDF of the minimum estimator, we differentiate its CDF with respect to \( y \), resulting in \( f_{\widehat{\beta}}(y) = 3n\beta^3 y^{-(3n+1)} \) for \( y \geq \beta \). This reveals that the likelihood of observing the minimum value decreases significantly as the value moves away from \( \beta \).

Understanding and utilizing the PDF is key for calculating expectations and predicting behaviors within a given distribution.
Cumulative Distribution Function
The Cumulative Distribution Function (CDF) is fundamentally important in statistics. It sums up the probability that a random variable takes a value less than or equal to a particular point. The CDF increases stepwise or continuously from 0 to 1.

For a continuous distribution like the Pareto, the CDF can illustrate the spread of probabilities across a range of values. Particularly, for the minimum of a sample, the CDF formula is expressed as \( P(\widehat{\beta} \leq y) = 1 - (1 - P(Y_i \leq y))^n \), where \( P(Y_i \leq y) = 1 - (\beta/y)^3 \) for \( y \geq \beta \). This indicates how likely it is for the minimum observed sample to be less than or equal to a certain amount.

By understanding and utilizing the CDF effectively, we can determine probabilities and glean insights about the behavior and properties of our distribution.

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Most popular questions from this chapter

The ages of a random sample of five university professors are \(39,54,61,72,\) and \(59 .\) Using this information, find a \(99 \%\) confidence interval for the population standard deviation of the ages of all professors at the university, assuming that the ages of university professors are normally distributed.

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