/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 133 A student answers a multiple-cho... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A student answers a multiple-choice examination question that offers four possible answers. Suppose the probability that the student knows the answer to the question is. 8 and the probability that the student will guess is .2. Assume that if the student guesses, the probability of selecting the correct answer is \(.25 .\) If the student correctly answers a question, what is the probability that the student really knew the correct answer?

Short Answer

Expert verified
The probability that the student really knew the correct answer is approximately 0.941 or 94.1%.

Step by step solution

01

Understanding the Problem

We are given a scenario where a student can either know the answer or guess it. We need to find the probability that the student knew the answer given that they answered correctly.
02

Define the Events and Probabilities

Let \( K \) be the event that the student knows the answer and \( C \) be the event that the student answers correctly. We have \( P(K) = 0.8 \) and \( P(G) = 0.2 \). The student guesses correctly with a probability of \( 0.25 \) if they guess.
03

Probability of Answering Correctly

Calculate \( P(C) \), the total probability of answering correctly. This can happen in two ways: either the student knows the answer, or they guess and get it right. \( P(C) = P(K)P(C|K) + P(G)P(C|G) \). The student always answers correctly if they know the answer \( P(C|K) = 1 \), so \( P(C) = 0.8 \times 1 + 0.2 \times 0.25 \).
04

Calculate Total Probability of Correct Answer

Calculate \( P(C) \) using the formula from the previous step: \[ P(C) = 0.8 + 0.2 \times 0.25 = 0.8 + 0.05 = 0.85. \]
05

Use Bayes' Theorem

We are now looking for \( P(K|C) \), the probability that the student knew the answer given that they answered correctly. Using Bayes' Theorem: \[ P(K|C) = \frac{P(C|K)P(K)}{P(C)}. \] Substitute the values we've found: \[ P(K|C) = \frac{1 \times 0.8}{0.85}. \]
06

Calculate Probability Using Bayes' Theorem

Compute \( P(K|C) \): \[ P(K|C) = \frac{0.8}{0.85} = \frac{80}{85}. \]Convert to a simplified fraction or decimal.
07

Simplify the Result

Simplify the fraction:\[ \frac{80}{85} = \frac{16}{17} \approx 0.941. \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability refers to the likelihood of an event occurring given that another event has already occurred. It helps us understand how probabilities change with new information. In the context of the problem, we're interested in the probability that the student truly knew the correct answer given that they answered correctly. This probability is denoted as \( P(K|C) \).

Bayes' Theorem is instrumental in calculating conditional probabilities. It allows us to update our initial beliefs with new evidence. With Bayes' Theorem, we can express the probability of knowing the answer given a correct response as:
  • \( P(K|C) = \frac{P(C|K)P(K)}{P(C)} \)
Here, \( P(C|K) \) represents the probability of answering correctly if the student knows the answer, which is 1 (certain). Bayes' Theorem combines this with the prior probability of knowing the answer (\( P(K) \)) and the total probability of a correct response (\( P(C) \)) to find \( P(K|C) \). This method provides a refined probability that incorporates all available information.
Multiple-Choice Questions
In a multiple-choice question, several potential answers are presented, only one of which is correct. With four choices, a student who doesn't know the answer is left to guess. This guessing introduces a specific probability scenario where guessing correctly corresponds to a probability of \( 0.25 \), assuming each choice has an equal chance.

The problem emphasizes two key strategies for students:
  • Knowing the answer, which equates to a certainty of choosing correctly (\( P(C|K) = 1 \)), and
  • Guessing among the options, which gives a much lower probability of being correct (\( P(C|G) = 0.25 \)).
Multiple-choice exams can employ strategies that utilize probability to approach questions, especially when unsure of the answer. This problem demonstrates how knowing versus guessing affects the overall probability outcome.
Probability Theory
Probability theory is the branch of mathematics concerned with analyzing random experiments and events. It provides a framework for calculating the likelihood of different outcomes. In our exercise, we used probability theory to understand the student's chances of answering the question correctly.

The problem requires the calculation of \( P(C) \), the total probability that the question is answered correctly. This calculation involves combining the probabilities of the independent scenarios: knowing the answer and guessing it correctly. By applying the Law of Total Probability, we add these contributions:
  • Probability of knowing and answering correctly: \( P(K) \times P(C|K) \)
  • Probability of guessing correctly: \( P(G) \times P(C|G) \)
This theoretical foundation ensures accurate and logical outcomes when dealing with probabilistic scenarios, providing insights into how different probabilities interact to contribute to the overall chance of an event happening.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.