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The symmetric difference between two events \(A\) and \(B\) is the set of all sample points that are in exactly one of the sets and is often denoted \(A \Delta B\). Note that \(A \Delta B=(A \cap B) \cup(\bar{A} \cap B)\). Prove that \(P(A \Delta B)=P(A)+P(B)-2 P(A \cap B)\)

Short Answer

Expert verified
The probability of the symmetric difference is \(P(A) + P(B) - 2P(A \cap B)\).

Step by step solution

01

Understand the Symmetric Difference

The symmetric difference between two events \(A\) and \(B\), denoted \(A \Delta B\), is the set of elements that are in either \(A\) or \(B\), but not in both. It's given by the formula \(A \Delta B = (A \cap \bar{B}) \cup (\bar{A} \cap B)\).
02

Use the Probability Formula for Union and Intersection

The probability of a union of two events \(A\) and \(B\) is given by \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\). This formula highlights that the joint occurrence is counted twice if we merely add the probabilities, thus we subtract it once.
03

Express \(P(A \Delta B)\) in Terms of \(P(A)\) and \(P(B)\)

First re-state the probability of the symmetric difference: \(P(A \Delta B) = P((A \cap \bar{B}) \cup (\bar{A} \cap B))\). This simplifies to \(P(A \Delta B) = P(A) + P(B) - 2P(A \cap B)\) based on the fundamental theorem and considering the overcounting as discussed in the previous step.
04

Conclusion

By applying the principles of probability, we see that to find the symmetric difference's probability, we take the individual probabilities \(P(A)\) and \(P(B)\) and subtract twice the probability of their intersection \(P(A \cap B)\). Therefore, \(P(A \Delta B) = P(A) + P(B) - 2P(A \cap B)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the mathematical framework used to quantify randomness and uncertainty. It provides tools for analyzing random events and understanding their likelihoods. This foundational concept is essential in various fields such as finance, insurance, and science.

In probability theory, events are outcomes or sets of outcomes from a random process. The probability of an event represents the likelihood that it will occur. The values range from 0 to 1, where 0 signifies impossibility and 1 signifies certainty.

Understanding probability theory helps us make informed decisions. It enables us to predict future occurrences and to assign meaningful levels of confidence to those predictions. By mastering this theory, we can evaluate risks and opportunities more accurately.
Set Operations
Set operations are fundamental in probability theory as they allow us to manipulate and understand the relationships between different events. These operations include union, intersection, complement, and difference, among others. In the context of probability, we often describe events using these set operations.

  • **Union**: The union of two sets, denoted as \(A \cup B\), contains all elements that are in either set \(A\) or set \(B\) or both.
  • **Intersection**: The intersection, \(A \cap B\), includes only the elements found in both \(A\) and \(B\).
  • **Complement**: The complement of a set, such as \(\bar{A}\), includes all elements that are not in \(A\).
  • **Difference**: The difference is represented by \(A - B\) or \(A \setminus B\), which includes elements that belong to \(A\) but not \(B\).
Set operations provide a language for describing complex relationships in a structured way. Mastery of these concepts is crucial for solving advanced probability problems, like finding the probability of a symmetric difference as explored in this exercise.
Event Probability
Event probability refers to the chance of a specific event occurring. It's a core concept in probability theory that stems from understanding individual events and how they relate to each other.

To calculate event probability, we first define the total number of possible outcomes in the sample space, which is the set of all possible occurrences. Then, by examining the number of ways a particular event can happen, we calculate its probability as the ratio of favorable outcomes to the total outcomes.

For example, if you roll a fair six-sided die, the probability of rolling a four is \(\frac{1}{6}\) since there is 1 favorable outcome (rolling a four) out of 6 possible outcomes. This idea is expanded further when dealing with more complex events, where the application of set operations, like union and intersection, comes into play. This helps in calculating the combined or joint probabilities of multiple events.
Union and Intersection in Probability
The concepts of union and intersection are key to calculating probabilities involving multiple events. They allow us to understand combined probabilities when considering two or more events together.

The **union** of two events \(A\) and \(B\) represents all outcomes that are in either one of the events or both. This is calculated using the formula: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]This formula helps avoid double counting outcomes that appear in both \(A\) and \(B\).

Meanwhile, the **intersection** of events, \(A \cap B\), accounts for only those outcomes shared by both events. Understanding the values of these probabilities is often challenging but essential in solving problems like the one presented in the exercise.

These concepts are foundational for grasping more advance topics such as symmetric difference. The ability to effectively use intersection and union calculations clarifies the relationships between events and supports accurate probability assessments.

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Most popular questions from this chapter

A brand of automobile comes in five different styles, with four types of engines, with two types of transmissions, and in eight colors. a. How many autos would a dealer have to stock if he included one for each style-engine-transmission combination? b. How many would a distribution center have to carry if all colors of cars were stocked for each combination in part (a)?

Two methods, \(A\) and \(B\), are available for teaching a certain industrial skill. The failure rate is \(20 \%\) for \(A\) and \(10 \%\) for \(B\). However, \(B\) is more expensive and hence is used only \(30 \%\) of the time. \((A\) is used the other \(70 \% .\) ) A worker was taught the skill by one of the methods but failed to learn it correctly. What is the probability that she was taught by method \(A\) ?

A manufacturer has nine distinct motors in stock, two of which came from a particular supplier. The motors must be divided among three production lines, with three motors going to each line. If the assignment of motors to lines is random, find the probability that both motors from the particular supplier are assigned to the first line.

A lie detector will show a positive reading (indicate a lie) \(10 \%\) of the time when a person is telling the truth and \(95 \%\) of the time when the person is lying. Suppose two people are suspects in a one-person crime and (for certain) one is guilty and will lie. Assume further that the lie detector operates independently for the truthful person and the liar. What is the probability that the detector a. shows a positive reading for both suspects? b. shows a positive reading for the guilty suspect and a negative reading for the innocent suspect? c. is completely wrong - that is, that it gives a positive reading for the innocent suspect and a negative reading for the guilty? d. gives a positive reading for either or both of the two suspects?

Of the items produced daily by a factory, \(40 \%\) come from line 1 and \(60 \%\) from line II. Line I has a defect rate of \(8 \%,\) whereas line II has a defect rate of \(10 \% .\) If an item is chosen at random from the day's production, find the probability that it will not be defective.

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