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Suppose two dice are tossed and the numbers on the upper faces are observed. Let \(S\) denote the set of all possible pairs that can be observed. [These pairs can be listed, for example, by letting (2,3) denote that a 2 was observed on the first die and a 3 on the second.] a. Define the following subsets of \(S\) : A: The number on the second die is even. B: The sumof the two numbers is even. C: At least one number in the pair is odd. b. List the points in \(A, \bar{C}, A \cap B, A \cap \bar{B}, \bar{A} \cup B,\) and \(\bar{A} \cap C\)

Short Answer

Expert verified
Subsets listed: A, \( \bar{C} \), \( A \cap B \), \( A \cap \bar{B} \), \( \bar{A} \cup B \), and \( \bar{A} \cap C \).

Step by step solution

01

Define the set S

The set \( S \) represents all possible outcomes when two six-sided dice are rolled. Each die has 6 faces, so there are \( 6 \times 6 = 36 \) possible pairs. Thus, \( S = \{ (1,1), (1,2), \ldots, (6,6) \} \).
02

Define subset A

Subset \( A \) consists of all outcomes where the second die shows an even number. The even numbers on a die are 2, 4, and 6. So, \( A \) includes all pairs \( (x, y) \) where \( y \) is even. Thus, \( A = \{ (1,2), (1,4), (1,6), (2,2), (2,4), (2,6), \ldots, (6,2), (6,4), (6,6) \} \).
03

Define subset B

Subset \( B \) contains pairs where the sum of the numbers is even. The sum is even when both numbers are either even or odd. Thus, \( B = \{ (1,1), (1,3), (1,5), (2,2), (2,4), (2,6), \ldots, (6,2), (6,4), (6,6) \} \).
04

Define subset C

Subset \( C \) includes pairs with at least one odd number. Therefore, \( C = \{ (1,1), (1,2), (1,3), (1,4), \ldots, (6,1), (6,3), (6,5) \} \).
05

Find \( \bar{C} \)

The complement \( \bar{C} \) consists of pairs that have no odd numbers, which means both numbers in the pair are even. Thus, \( \bar{C} = \{ (2,2), (2,4), (2,6), \ldots, (6,2), (6,4), (6,6) \} \).
06

Find \( A \cap B \)

Intersection \( A \cap B \) consists of pairs in both sets \( A \) and \( B \). These pairs have the second die with an even number and the sum being even. Thus, \( A \cap B = \{ (2,2), (2,4), (2,6), (4,2), (4,4), (4,6), (6,2), (6,4), (6,6) \} \).
07

Find \( A \cap \bar{B} \)

Set \( \bar{B} \) consists of pairs with an odd sum. \( A \cap \bar{B} \) consists of pairs in \( A \) but not in \( B \), i.e., pairs where the second die is even and the sum is odd. \( A \cap \bar{B} = \{ (1,2), (1,4), (1,6), \ldots, (5,6) \} \textrm{ (pairs like (1,2) where the sum 3 is odd)} \).
08

Find \( \bar{A} \cup B \)

Union \( \bar{A} \cup B \) includes pairs not in \( A \) or in \( B \). Since not in \( A \) means the second die shows an odd number, and \( B \) contains the even sums, we join these two conditions. Commit only to pairs that show odd second-die values or even sum: \( (1,1), (1,2), \ldots, (6,5), (6,6) \).
09

Find \( \bar{A} \cap C \)

Intersection \( \bar{A} \cap C \) includes pairs where the second number is odd (\( \bar{A} \)) and at least one number is odd (\( C \)). Hence, every such pair would by default have the second number as odd: \( \bar{A} \cap C = \{ (1,1), (1,3), (1,5), \ldots, (6,1), (6,3), (6,5) \} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability Theory is the mathematical study of randomness and uncertainty. It helps us understand how likely events are to happen. In this exercise, we calculate the probability of different outcomes when rolling two dice, each with six faces. The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
For example, when calculating dice probabilities, each roll has 36 possible outcomes (6 for each die). To find the probability of rolling a sum of 4, you identify the pairs that add to 4, such as (1,3) and (2,2), imply that there are three favorable outcomes. Therefore, the probability would be \[\frac{3}{36} = \frac{1}{12}\].
Through probability theory, we understand and anticipate possible outcomes, enhancing decision-making and predictions in uncertain situations.
Set Theory
Set Theory forms a fundamental basis for probability and mathematics. Sets are collections of distinct objects, which can be numbers, people, or other items. In this case, the set consists of ordered pairs representing dice rolls.
When working with sets:
  • Union (\(A \cup B\)) combines elements from two sets.
  • Intersection (\(A \cap B\)) focuses on elements common to both sets.
  • Complement (\(\bar{A}\)) includes elements not in a given set.
Defining subsets based on conditions, like even or odd numbers in dice rolls, allows us to calculate probabilities of complex events. For example, to find the intersection \(A \cap B\), identify pairs common to both conditions: the second die shows an even number, and the sum is even.
Understanding set operations helps break down complex probability tasks, simplifying calculations and providing structured solutions.
Dice Probabilities
Dice Probabilities delve into the likelihood of different scores or outcomes when rolling dice. Each six-sided die has an equal chance to show any number from 1 to 6, leading us to 36 different combinations when two dice are rolled. Calculating specific probabilities involves understanding the behavior of these combinations.
When calculating the probability that the sum of two dice is even, consider that the sum is even if both numbers are either odd or even (e.g., 2+2=4 or 3+3=6). This translates into forming the subset \(B\), focusing on even sums.
  • Even numbers are 2, 4, and 6.
  • Odd pairs include numbers like (1,1), (1,3).
Dice probabilities involve identifying patterns and translating them into mathematical calculations. These probabilities provide insights into expected outcomes, helping us understand chances and improve strategic thinking in games or applied scenarios.

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Most popular questions from this chapter

Americans can be quite suspicious, especially when it comes to government conspiracies. On the question of whether the U.S. Air Force has withheld proof of the existence of intelligent life on other planets, the proportions of Americans with varying opinions are given in the table. $$\begin{array}{lc} \hline \text { Opinion } & \text { Proportion } \\ \hline \text { Very likely } & .24 \\ \text { Somewhat likely } & .24 \\ \text { Unlikely } & .40 \\ \text { Other } & .12 \\ \hline \end{array}$$ Suppose that one American is selected and his or her opinion is recorded. a. What are the simple events for this experiment? b. Are the simple events that you gave in part (a) all equally likely? If not, what are the probabilities that should be assigned to each? c. What is the probability that the person selected finds it at least somewhat likely that the Air Force is withholding information about intelligent life on other planets?

Every person's blood type is \(A, B, A B,\) or O. In addition, each individual either has the Rhesus (Rh) factor \((+)\) or does not \((-) .\) A medical technician records a person's blood type and Rh factor. List the sample space for this experiment.

An experiment consists of tossing a pair of dice. a. Use the combinatorial theorems to determine the number of sample points in the sample space \(S\). b. Find the probability that the sum of the numbers appearing on the dice is equal to 7 .

A boxcar contains six complex electronic systems. Two of the six are to be randomly selected for thorough testing and then classified as defective or not defective. a. If two of the six systems are actually defective, find the probability that at least one of the two systems tested will be defective. Find the probability that both are defective. b. If four of the six systems are actually defective, find the probabilities indicated in part (a).

If \(A\) and \(B\) are independent events, show that \(A\) and \(\bar{B}\) are also independent. Are \(\bar{A}\) and \(\bar{B}\) independent?

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