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Suppose that \(Y_{1}, Y_{2}, \ldots, Y_{n}\) constitute a random sample from a normal distribution with known mean \(\mu\) and unknown variance \(\sigma^{2}\). Find the most powerful \(\alpha\) -level test of \(H_{0}: \sigma^{2}=\sigma_{0}^{2}\) versus \(H_{a}:\) \(\sigma^{2}=\sigma_{1}^{2},\) where \(\sigma_{1}^{2}>\sigma_{0}^{2} .\) Show that this test is equivalent to a \(\chi^{2}\) test. Is the test uniformly most powerful for \(H_{a}: \sigma^{2}>\sigma_{0}^{2} ?\)

Short Answer

Expert verified
The most powerful \(\alpha\)-level test is a \(\chi^2\) test, but it's not uniformly most powerful for all \(\sigma^2 > \sigma_0^2\).

Step by step solution

01

Formulate the Hypotheses

We want to test the null hypothesis \(H_0: \sigma^2 = \sigma_0^2\) against the alternative hypothesis \(H_a: \sigma^2 = \sigma_1^2\), where \(\sigma_1^2 > \sigma_0^2\). This sets up a one-sided test where we are looking for evidence of an increase in the variance from \(\sigma_0^2\) to \(\sigma_1^2\).
02

Select the Test Statistic

The sample variance can be used here. Since the sample \(Y_1, Y_2, \ldots, Y_n\) are from a normal distribution, the test statistic \(T = \frac{(n-1)S^2}{\sigma_0^2}\) follows a \(\chi^2\) distribution with \((n-1)\) degrees of freedom under \(H_0\). Here, \(S^2\) is the sample variance.
03

Define the Rejection Region

To find the most powerful test, we need to reject \(H_0\) for large values of \(T\), aligning with when \(\sigma^2 > \sigma_0^2\). The rejection region for an \(\alpha\)-level \(\chi^2\) test is \(T > \chi^2_{\alpha, n-1}\), where \(\chi^2_{\alpha, n-1}\) is the critical value from the \(\chi^2\) distribution for level \(\alpha\) and \(n-1\) degrees of freedom.
04

Relate Test to Chi-Squared Distribution

The test statistic \(T = \frac{(n-1)S^2}{\sigma_0^2}\) directly specifies that if \(\sigma^2eq \sigma_0^2\), this \(T\) becomes a non-central \(\chi^2\) distribution under \(H_a\). Particularly, it maintains a central \(\chi^2\) distribution under \(H_0\), establishing that our test is indeed a \(\chi^2\) test.
05

Consider Uniform Most Powerful Test

While this test, based on the sample variance and \(\chi^2\) distribution, is most powerful for testing specific alternatives \(\sigma^2 = \sigma_1^2\) vs. \(\sigma^2 = \sigma_0^2\), it is not uniformly most powerful for all \(\sigma^2 > \sigma_0^2\) due to Neyman-Pearson Lemma limitations regarding scope across multiple parameter alternatives.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a fundamental concept in statistics. It provides a method for decision-making based on data from a sample. During hypothesis testing, we start by establishing two opposing hypotheses:

  • The null hypothesis ( H_0 ): This is a statement of no effect or no difference. It is assumed true until evidence suggests otherwise.
  • The alternative hypothesis ( H_a ): This is what you want to prove. It is typically a statement indicating the presence of an effect or difference.
In the context of our exercise, the hypotheses are about variance: - H_0: σ^2 = σ_0^2 (no change in variance) - H_a: σ^2 = σ_1^2 (variance has increased)
A critical aspect is determining which test to use and how much evidence (significance level, α ) is necessary to reject the null hypothesis. If the test's outcome significantly deviates from what is expected under the null hypothesis, we might reject H_0 in favor of H_a , concluding that there is evidence to suggest a change in variance.
Variance Testing
Variance testing specifically examines whether the variance of a sample differs from a specified value. In many industrial processes or research scenarios, keeping track of variance is vital as it can indicate consistency or fluctuation within a system.

In our problem, you are tasked to identify if the variance (random fluctuations in data) has increased. The sample variance is calculated from the data set and compared against a known variance ( σ_0^2 ).

Variance testing using a Chi-squared test helps in these cases where:
  • The data is normally distributed.
  • The variance of the population is important to evaluate.
By using the sample variance and the number of samples (degrees of freedom (n-1) ), a test statistic is computed which can be compared to the critical value from the Chi-squared distribution. If the test statistic falls into the critical region, we may reject the null hypothesis, suggesting a variance different from the expected one.
Most Powerful Test
The concept of the most powerful test originates from the Neyman-Pearson Lemma. It aims to provide a test which, for a particular level of significance ( α ), gives the highest probability of correctly detecting a true alternative hypothesis. In the exercise, identifying the most powerful test helps ensure that if the variance is actually different from σ_0^2 , the test will likely signify it. The strategy is to select test statistics and rejection regions that maximize this probability.

However, it is critical to understand the difference between a powerful test and a uniformly most powerful test:
  • A powerful test provides the highest power against a specific alternative.
  • A uniformly most powerful test is the most powerful across all possible alternatives.
For variance testing where σ^2 > σ_0^2 , the most powerful test is optimal for comparing σ_0^2 against one specific higher value, but not across all higher values.
Normal Distribution
The normal distribution is a continuous probability distribution that is symmetrical on both sides of the mean, creating a bell-shaped curve. It is characterized by its mean ( μ ) and variance ( σ^2 ). In our exercise, the normal distribution plays an essential role: 1. **Properties**: The data provided is assumed to follow a normal distribution, with a specific mean and unknown variance. 2. **Assumption for Tests**: Many statistical tests, including the Chi-squared test, are based on data distributions being normal. This allows for specific mathematical properties and simplifications. 3. **Chi-Squared Distribution**: Derived from variance in a normal distribution, the Chi-squared distribution is utilized when conducting hypothesis tests on variance. Understanding the normal distribution helps students grasp the underlying data properties that justify using specific statistical methods. When variance testing in normally distributed data, leveraging the Chi-squared distribution helps makes determination about changes in the underlying process variance.

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Most popular questions from this chapter

According to the Washington Post, nearly 45\% of all Americans are born with brown eyes, although their eyes don't necessarily stay brown. \(^{\star}\) A random sample of 80 adults found 32 with brown eyes. Is there sufficient evidence at the .01 level to indicate that the proportion of brown eyed adults differs from the proportion of Americans who are born with brown eyes?

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