/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 Suppose that we have a random sa... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that we have a random sample of four observations from the density function $$ f(y | \theta)=\left\\{\begin{array}{ll} \left(\frac{1}{2 \theta^{3}}\right) y^{2} e^{-y / \theta}, & y>0 \\ 0, & \text { elsewhere } \end{array}\right. $$ a. Find the rejection region for the most powerful test of \(H_{0}: \theta=\theta_{0}\) against \(H_{a}: \theta=\theta_{a},\) assuming that \(\theta_{a}>\theta_{0} .\) [Hint: Make use of the \(\chi^{2}\) distribution.] b. Is the test given in part (a) uniformly most powerful for the alternative \(\theta>\theta_{0} ?\)

Short Answer

Expert verified
The rejection region for the most powerful test is \( \sum y_i > c \). The test is not uniformly most powerful for \( \theta > \theta_0 \).

Step by step solution

01

Define the Likelihood Ratio

For the hypothesis test, we use the likelihood ratio, which is given by the formula: \( \Lambda(y) = \frac{L(\theta_0 | y)}{L(\theta_a | y)} \), where \( L(\theta | y) \) is the likelihood function for the parameter \( \theta \).
02

Write the Likelihood Functions

The likelihood function of a sample for the given distribution is: \[ L(\theta|y) = \prod_{i=1}^{n} \left(\frac{1}{2\theta^{3}}\right)y_i^2 e^{-y_i/\theta} = \left(\frac{1}{2\theta^3}\right)^n \prod_{i=1}^{n} y_i^2 e^{-\sum y_i/\theta}. \] For \( \theta = \theta_0 \) and \( \theta = \theta_a \), compute separately.
03

Form Likelihood Ratio

Insert the likelihood functions into the likelihood ratio: \[ \Lambda(y) = \frac{ \left(\frac{1}{2\theta_0^3}\right)^n \prod_{i=1}^{n} y_i^2 e^{-\sum y_i/\theta_0} }{ \left(\frac{1}{2\theta_a^3}\right)^n \prod_{i=1}^{n} y_i^2 e^{-\sum y_i/\theta_a} }. \] This simplifies to: \[ \Lambda(y) = \left(\frac{\theta_a}{\theta_0}\right)^{3n} e^{-(\sum y_i)(1/\theta_0 - 1/\theta_a)}. \]
04

Determine Rejection Region

The rejection region is formed by the inequality: \[ \Lambda(y) < k \quad \Rightarrow \quad e^{-(\sum y_i)(1/\theta_0 - 1/\theta_a)} < k', \] where \( k' \) is a positive constant derived from \( k \). Solving gives: \[ \sum y_i > c, \] where \( c = \log(k') / [(1/\theta_0) - (1/\theta_a)] \) because \( \theta_a > \theta_0 \).
05

Explore Uniformly Most Powerful Test

For part (b), to verify if the test is uniformly most powerful, observe that the likelihood ratio retains the form of an exponential family test. The rejection region depends only on the sum of the sample values. However, as the exponential distribution is not from a one-parameter exponential family in this case, the test in part (a) cannot be guaranteed to be uniformly most powerful across all \( \theta > \theta_0 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Likelihood Ratio Test
A Likelihood Ratio Test (LRT) is a statistical method used to decide between two competing hypotheses based on the likelihoods given the observed data. Imagine you have a coin, and you're trying to decide if it's fair (i.e., has an equal probability of landing heads or tails) or biased. You'd use the likelihood ratio to evaluate how likely the observed results are under both assumptions and compare them.

For a given hypothesis test, the likelihood ratio is defined as \( \Lambda(y) = \frac{L(\theta_0 | y)}{L(\theta_a | y)} \). Here, \( L(\theta | y) \) is the likelihood function of parameter \( \theta \) given the data \( y \). The basic idea is to compare how likely the observed data is if the null hypothesis \( H_0 \) is true versus if the alternative hypothesis \( H_a \) is true.

The ratio itself quantifies this comparison. A small ratio suggests that the data strongly favors the alternative hypothesis. Once computed, this ratio will guide the creation of a rejection region, which tells us when we should reject \( H_0 \) in favor of \( H_a \). This rejection region often involves critical values determined using theoretical distributions like the chi-square distribution.
Exponential Family
The Exponential Family refers to a set of probability distributions that exhibit certain standard properties, making them particularly tractable for mathematical treatment in statistical sciences. Members of this family include the normal, exponential, Poisson, and gamma distributions, among others. These distributions have the form:
  • \( f(y | \theta) = h(y) \, \exp \left( \eta(\theta) \, T(y) - A(\theta) \right) \)
Here, \( h(y) \) is a baseline measure, \( \eta(\theta) \) is known as the natural parameter, \( T(y) \) is the sufficient statistic, and \( A(\theta) \) is the log-partition function.

This structure allows for simplified calculations of maximum likelihood estimates and the general form of likelihoods. The problem presented involves a distribution from the exponential family, which helps in building likelihood ratio tests and often results in simpler forms of rejection regions.

Understanding whether a distribution is part of the exponential family is critical for choosing the appropriate statistical methods, especially in hypothesis testing. Distributions not belonging to this family might need different treatments to construct tests or find parameter estimates.
Uniformly Most Powerful Test
A Uniformly Most Powerful (UMP) Test is like finding the "best possible detector" in hypothesis testing. Think of it as the ultimate test strategy that provides the highest probability of correctly rejecting a false null hypothesis, across all possible values of the parameter being tested, within some specified constraints.

To judge if a test is UMP, the test must have the greatest power among all possible tests for every value of \( \theta \) under consideration. This concept guarantees the test's optimality for detecting deviations from the null hypothesis.

In our exercise's context, finding a UMP involves determining if the rejection region we derived remains optimal for all \( \theta > \theta_0 \), not just for specific values like \( \theta_a \). In general, achieving a uniformly most powerful test is challenging and usually depends greatly on the form and nature of the underlying statistical model, like the aforementioned exponential family.

Sometimes, in situations where such optimality for all parameters isn't possible or doesn't exist, conditional optimization approaches or other forms of test may be used to still achieve strong results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A manufacturer of hard safety hats for construction workers is concerned about the mean and the variation of the forces its helmets transmit to wearers when subjected to a standard external force. The manufacturer desires the mean force transmitted by helmets to be 800 pounds (or less), well under the legal 1000 -pound limit, and desires \(\sigma\) to be less than \(40 .\) Tests were run on a random sample of \(n=40\) helmets, and the sample mean and variance were found to be equal to 825 pounds and 2350 pounds \(^{2}\), respectively. a. If \(\mu=800\) and \(\sigma=40,\) is it likely that any helmet subjected to the standard external force will transmit a force to a wearer in excess of 1000 pounds? Explain. b. Do the data provide sufficient evidence to indicate that when subjected to the standard external force, the helmets transmit a mean force exceeding 800 pounds? c. Do the data provide sufficient evidence to indicate that \(\sigma\) exceeds \(40 ?\)

A two-stage clinical trial is planned for testing \(H_{0}: p=.10\) versus \(H_{a}: p>.10,\) where \(p\) is the proportion of responders among patients who were treated by the protocol treatment. At the first = 15 patients are accrued and treated. If 4 or more responders are observed among the (first) 15 patients, \(H_{0}\) is rejected, the study is terminated, and no more patients are accrued. Otherwise, =another 15 patients will be accrued and treated in the second stage. If a total of 6 or more Tesponders are observed among the 30 patients accrued in the two stages ( 15 in the first stage and 15 more in the second stage), then \(H_{0}\) is rejected. For example, if 5 responders are found among the first-stage patients, \(H_{0}\) is rejected and the study is over. However, if 2 responders are found among the first-stage patients, 15 second-stage patients are accrued, and an additional 4 or more Jresponders (for a total of 6 or more among the 30 ) are identified, \(H_{0}\) is rejected and the study is over. a. Use the binomial table to find the numerical value of \(\alpha\) for this testing procedure. b. Use the binomial table to find the probability of rejecting the null hypothesis when using this rejection region if \(p=.30\). c. For the rejection region defined above, find \(\beta\) if \(p=.30\).

The output voltage for an electric circuit is specified to be \(130 .\) A sample of 40 independent readings on the voltage for this circuit gave a sample mean 128.6 and standard deviation \(2.1 .\) Test the hypothesis that the average output voltage is 130 against the alternative that it is less than \(130 .\) Use a test with level. \(05 .\)

A large-sample \(\alpha\) -level test of hypothesis for \(H_{0}: \theta=\theta_{0}\) versus \(H_{a}: \theta>\theta_{0}\) rejects the null hypothesis if $$\frac{\hat{\theta}-\theta_{0}}{\sigma_{\hat{\theta}}}>z_{\alpha}$$ Show that this is equivalent to rejecting \(H_{0}\) if \(\theta_{0}\) is less than the large-sample \(100(1-\alpha) \%\) lower confidence bound for \(\theta\)

Do you believe that an exceptionally high percentage of the executives of large corporations are right-handed? Although \(85 \%\) of the general public is right-handed, a survey of 300 chief executive officers of large corporations found that \(96 \%\) were right-handed. a. Is this difference in percentages statistically significant? Test using \(\alpha=.01\) b. Find the \(p\) -value for the test and explain what it means.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.