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A bacteria culture is started with 300 bacteria. After 4 hours, the population has grown to 500 bacteria. If the population grows exponentially, a. Write a recursive formula for the number of bacteria b. Write an explicit formula for the number of bacteria c. If this trend continues, how many bacteria will there be in 1 day? d. How long does it take for the culture to triple in size?

Short Answer

Expert verified
(a) Recursive: \( P_{n+1} = P_n \times e^{0.142} \); (b) Explicit: \( P(t) = 300 \times e^{0.142t} \); (c) 9054 bacteria after 1 day; (d) ~7.63 hours to triple.

Step by step solution

01

Understand the concept of exponential growth

Exponential growth can be described using the formula \( P(t) = P_0 imes e^{rt} \), where \( P(t) \) is the population at time \( t \), \( P_0 \) is the initial population, and \( r \) is the growth rate. Our goal is to determine \( r \) and express this growth in both recursive and explicit formulas.
02

Calculate growth rate using initial and final populations

We know \( P_0 = 300 \) and \( P(4) = 500 \) after 4 hours. Using the formula, \[ 500 = 300 imes e^{4r} \]. Divide both sides by 300: \( \frac{500}{300} = e^{4r} \), which simplifies to \( \frac{5}{3} = e^{4r} \). Take the natural logarithm of both sides: \( \ln(\frac{5}{3}) = 4r \). Solve for \( r \): \( r = \frac{\ln(\frac{5}{3})}{4} \approx 0.142 \).
03

Construct recursive and explicit formulas

**(a) Recursive Formula**:With \( P_0 = 300 \), the recursive formula is \( P_{n+1} = P_n imes e^{h \times r} \), where \( h \) is the number of hours per step. Since \( h = 1 \), \( P_{n+1} = P_n imes e^{0.142} \).**(b) Explicit Formula**:Use the growth rate: \( P(t) = 300 imes e^{0.142t} \).
04

Calculate bacteria population after 1 day

**(c) Find \( P(24) \):**Using the explicit formula from Step 3, substitute \( t = 24 \) hours:\( P(24) = 300 \times e^{0.142 imes 24} = 300 \times e^{3.408} \approx 300 \times 30.18 = 9054 \).Therefore, there will be approximately 9054 bacteria after 1 day.
05

Determine time to triple the starting population

**(d) Solve \( P(t) = 900 \):**Since tripling 300 bacteria is 900, use the formula to find \( t \):\( 900 = 300 \times e^{0.142t} \). Simplify: \( 3 = e^{0.142t} \).Take the natural logarithm: \( \ln(3) = 0.142t \).Solve for \( t \): \( t = \frac{\ln(3)}{0.142} \approx 7.63 \).It takes approximately 7.63 hours to triple.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recursive Formula
When dealing with exponential growth, a recursive formula provides a way to find the next term based on its predecessor. In this scenario, we are looking at a bacteria population that starts at 300 and grows exponentially. The recursive formula is great when you want to calculate step-by-step and see how each new population figure depends on the previous one.
Here's how the recursive formula works in our example: each hour, the population grows by multiplying by a factor of the growth rate, expressed as the continuous compounding factor. We already calculated that the growth rate is approximately 0.142. So, we get the recursive formula:
  • \( P_{n+1} = P_n \times e^{0.142} \)
  • Here, \( P_{n+1} \) is the population after the next hour, and \( P_n \) is the current population.
This formula lets us compute the population incrementally, making it easy to track what happens at each period.
Explicit Formula
Unlike a recursive formula, an explicit formula allows you to jump directly to the calculation of the population size at any given point in time without the need to calculate every intermediary step. This form of the equation is particularly helpful for predicting future events and populations over longer time frames.

In the context of our bacteria, the explicit formula uses the initial population and growth rate to determine the population size at any given hour, \( t \). The explicit formula derived from the problem is given by:
  • \( P(t) = 300 \times e^{0.142t} \)
  • Where \( P(t) \) is the population at time \( t \), \( 300 \) is the initial number of bacteria.
  • The term \( e^{0.142t} \) captures the effect of continuous growth over time \( t \).
This formula is flexible and powerful for quickly calculating the population at any point, such as 24 hours for a daily estimate.
Growth Rate
The growth rate in an exponential growth problem is a crucial component as it determines how quickly the population increases. It's often presented as a constant that modifies the exponential function, enabling predictions at any time in the future.

In our bacteria problem, the growth rate \( r \) was found by utilizing the exponential growth model. This required us to solve the equation using the initial and observed population at a given time:
  • We identified that in 4 hours, the population grew from 300 to 500.
  • Using the formula \( \frac{500}{300} = e^{4r} \), and then solving \( r = \frac{\ln(\frac{5}{3})}{4} \), we found \( r \approx 0.142 \).
  • This rate tells you how quickly the bacteria multiply, and directly feeds into both the recursive and explicit formulas.
Understanding this growth rate allows for accurate predictions of future population sizes and is key to understanding the behavior of exponential growth.
Population Growth
Population growth is a fascinating and complex topic, especially when modeled exponentially, as in our bacteria culture example. When populations grow exponentially, they increase by a set percentage over equal time intervals. This differs dramatically from linear growth, which adds a constant number each interval.

For the bacteria, we started with 300, and after 24 hours, the population soared to approximately 9054, showcasing exponential growth's rapid escalation. Key takeaway points include:
  • Exponential growth causes populations to increase much faster over time compared to linear growth.
  • The concept helps answer questions like how long it will take for a population to reach a particular size, such as tripling, which we calculated to be about 7.63 hours for our bacteria.
  • In applications, understanding exponential growth helps predict trends, guide resource allocation, and manage environments sustainably.
Grasping the fundamentals of population growth empowers us to make informed decisions based on the modeled predictions.

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Most popular questions from this chapter

Suppose that you have a bowl of 500 M\&M candies, and each day you eat \(1 / 4\) of the candies you have. Is the number of candies left changing linearly or exponentially? Write an equation to model the number of candies left after \(n\) days.

Recursive equations can be very handy for modeling complicated situations for which explicit equations would be hard to interpret. As an example, consider a lake in which 2000 fish currently reside. The fish population grows by \(10 \%\) each year, but every year 100 fish are harvested from the lake by people fishing. a. Write a recursive equation for the number of fish in the lake after \(n\) years. b. Calculate the population after 1 and 2 years. Does the population appear to be increasing or decreasing? c. What is the maximum number of fish that could be harvested each year without causing the fish population to decrease in the long run?

Inflation causes things to cost more, and for our money to buy less (hence your grandparents saying, "In my day, you could buy a cup of coffee for a nickel"). Suppose inflation decreases the value of money by \(5 \%\) each year. In other words, if you have \(\$ 1\) this year, next year it will only buy you \(\$ 0.95\) worth of stuff. How much will \(\$ 100\) buy you in 20 years?

In 1968 , the U.S. minimum wage was \(\$ 1.60\) per hour. In 1976 , the minimum wage was \(\$ 2.30\) per hour. Assume the minimum wage grows according to an exponential model where \(n\) represents the time in years after 1960 . a. Find an explicit formula for the minimum wage. b. What does the model predict for the minimum wage in \(1960 ?\) c. If the minimum wage was \(\$ 5.15\) in \(1996,\) is this above, below or equal to what the model predicts?

A new truck costs \(\$ 32,000\). The car's value will depreciate over time, which means it will lose value. For tax purposes, depreciation is usually calculated linearly. If the truck is worth \(\$ 24,500\) after three years, write an explicit formula for the value of the car after \(n\) years.

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