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Use the concept of a linear transformation in terms of the formula y=Ax, and interpret simple linear transformations geometrically. Find the inverse of a linear transformation from 2to2(if it exists). Find the matrix of a linear transformation column by column.

Consider the transformations from 3to3defined in Exercises 1 through 3. Which of these transformations are linear?

2.

y1=2x2y2=3x3y3=x1

Short Answer

Expert verified

The given transformationy1=2x2y2=3x3y3=x1 is linear

Step by step solution

01

Step1: System of equation

We have given that system of equation is y1= 2x2y2= 3x3y3=x1.

For the transformation of 3to 3it can be written as

T(x1,x2,x3)=(y1,y2,y3)T(x1,x2,x3)=(2x2,3x3,x1)

02

Linear Transformation 

A transformation fromRmRn is said to be linear if the following condition holds:

  1. Identity ofmshould be mapped to identity ofn .
  2. T(a+b)=T(a)+T(b)For alla,bRm .
  3. T(ca)=cT(a)Where c is any scalar andaRm .
03

Checking for linear transformation

Identity of R3is (0,0,0) .

Now we will find the transformation of identity element.

T(0,0,0)=(2(0),0,0)=(0,0,0)

Now let a=(u1,u2,u3),b=(v1,v2,v3)R3.

Then the transformation,

T(a+b)=T((u1,u2,u3)+(v1,v2,v3))=T(u1+v1,u2+v2,u3+v3)T(u1+v1,u2+v2,u3+v3)=(2(u2+v2),3(u3+v3),u1+v1)T(u1+v1,u2+v2,u3+v3)=(2u2+2v2,3u3+3v3,u1+v1)T(u1+v1,u2+v2,u3+v3)=(2u2,3u3,u1)(2v2,3v3,v1)=T(a)+T(b)T(a+b)=T(a)+T(b)

Now for condition 3 Let a=(u1,u2,u3)R3and cbe any scalar.

T(ca)=T(c(u1,u2,u3))=(2cu2,3cu3,cu1)=c(2u2,3u3,u1)=cT(a)T(ca)=cT(a)

Thus, all the conditions are true, so the given transformation is a linear transformation.

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