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There exists an invertible 2 脳 2 matrix A such that A-1=[1111].

Short Answer

Expert verified

The statement is false.

Step by step solution

01

Explaining

The claim is that there exists an invertible 2x2 matrix A such that A-1=1111. IfA-1=1111then:A=A-1-1

A-1=1111-1

Now we know that1111 is invertible as long asdet11110

02

Conclusion

If we calculatedet1111 we have det1111=1-1=0.

Thus the inverse does not exist and the statement is false.

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Most popular questions from this chapter

Give a geometric interpretation of the linear transformations defined by the matrices in Exercises16through 23. Show the effect of these transformations on the letter L considered in Example5. In each case, decide whether the transformation is invertible. Find the inverse if it exists, and interpret it geometrically. See Exercise13

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Let Lbe the line in R3that consists of all scalar multiples of[212]. Find the orthogonal projection of the vector[111]onto line L.

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