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91Ó°ÊÓ

Solve the differential equationf'(t)−5f(t)=0and find all real solutions of the differential equation.

Short Answer

Expert verified

The solution isf(t)=Ce5t .

Step by step solution

01

Definition of first order linear differential equation.

Consider the differential equationf'(t)-af(t)=g(t) where is a smooth function and'a'is a constant. Then the general solution will be f(t)=eat∫e-atg(t)dt.

02

Determination of the solution

Consider the differential equation as follows.

f'(t)-5f(t)=0

Now, the differential equation is in the form as follows.

f'(t)-af(t)=g(t), whereg(t) is a smooth function, then the general solution will be as follows.

f(t)=eat∫e-atg(t)dt

03

Compute the calculation of the solution.

Substitute the value0 forg(t) and5 fora inf(t)=eat∫e-atg(t)dt as follows.

f(t)=eat∫e-atg(t)dtf(t)=e5t∫e-5t×0×dtf(t)=e5t∫0×dtf(t)=e5t⋅C

Hence, the solution for the linear differential equation f'(t)-5f(t)=0is f(t)=Ce5t.

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