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Use the concept of a continuous dynamical system.Solve the differential equation dxdt=−kx. Solvethe systemdx→dt=Ax→ whenAis diagonalizable overR,and sketch the phase portrait for 2×2 matricesA.

Solve the initial value problems posed in Exercises 1through 5. Graph the solution.

  1. dxdt=5xwithx(0)=7.

Short Answer

Expert verified

The solution is y=7e5t.

Step by step solution

01

Definition of the differential equation

Consider the differential equationdydx=kx with initial valuex0 (k is an arbitrary constant). The solution isrole="math" localid="1659551917942" x(t)=x0ekt .

The solution of the linear differential equationdydx=kxandy(0)=C is y=Cekx.

02

Calculation of the solution

Given the differential equation dxdt=5xwith the initial condition x(0)=7.

Substitute in the solutiony=Cekxas follows.

y=Cekxy=7e5t

Hence, the solution for the differential equationdxdt=5x is y=7e5t.

03

Graphical representation the equation

The graph of the equation y=7e5tis sketched below as follows:

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