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Find all solution of the liner DE f'''(t)+3f'(t)3f'(t)+f(t)=0.

Short Answer

Expert verified

The solution isft=e-tc1+c2t+c3t2 .

Step by step solution

01

Determine the auxiliary equation of f'''(t)+3f'(t)3f'(t)+f(t)=0 .

Consider the linear differential equationf'''(t)+3f'(t)3f'(t)+f(t)=0 .

Assume Dn=fnt, substitute the value D3for f''t, D2forf''t , D forf't and 1 forft in the equationf'''t+3f''t+3f't+ft=0 as follows.

f'''t+3f''t+3f't+ft=0D3+3D2+3D+1=0D+13=0

02

Determine the solution of (D+1)3=0 .

The solution of the differential equationD±an=0 isrole="math" localid="1660805138475" ft=eTat∑i=0n-1ci+1ti .

Using the definition, the solution of the linear differential equationD+13=0 is defined as follows.

ft=e-t∑i=0n-1ci+1tift=e-tc1t0+c2t1+c3t2ft=e-tc1+c2t1+c3t2

Hence, the solution of the linear differential equationf'''t+3f''t+3f't+ft=0 is

ft=e-tc1+c2t1+c3t2

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