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Use de Moivre’s formula to express cos(3θ) and sin (3θ) in terms of cos θ and sin θ.

Short Answer

Expert verified

cos3θ=cos2θ-3cosθsin2θsin3θ=3cos2θsinθ-sin3θ

Step by step solution

01

Step 1:The de Moivre formula

The de Moivre formula (also known as de Moivre's theorem and de Moivre's ID) states that in any real number x and the whole number n holds that (cosx+isinx)n=cosnx+isinnx

02

Expressed cos (3θ) and sin(3θ) in terms of cos θ and sin θ:

Let 2∈C,|z|=1

Now ∃θ<0.2π]

z=cosθ+isinθ

By de Moivre's formula, we can see that

z=cosθ+isinθ

However, by direct computation, we can see that

z3=cos3θ-3cosθsin2θ+i3cos2θsinθ-sin3θ

We conclude that the solution is

cos3θ=cos2θ-3³¦´Ç²õθ²õ¾±²Ô2θsin3θ=3cos2θ²õ¾±²Ôθ-sin3θ

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