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For each of the matrices in Exercises 1 through 13, find all real eigenvalues, with their algebraic multiplicities. Show your work. Do not use technology.

[2-2001-100003-4002-3]

Short Answer

Expert verified

Eigenvalues are:

1=0,almuu(0)=12=-1,almu(-1)=24=1,almu(1)=1

Step by step solution

01

Eigenvalues

  • In linear algebra, an eigenvector or characteristic vector of a linear transformation is a nonzero vector that changes at most by a scalar factor when that linear transformation is applied to it. The corresponding eigenvalue, often denoted by , is the factor by which the eigenvector is scaled.
  • Eigenvalues of a triangular matrix are its diagonal matrix.
02

Step 2: Finding all real eigenvalues, with their algebraic multiplicities

Since, given matrix is triangular its eigenvalues arethe entries on the main diagonal.

Find eigenvalues using characteristic equation as:

det(A-l)=02--2001-1-00003--4002-3=02--1-+23--3-+8=0

=0,2,3=-1,4=1

Hence, the answer is:

1=0,almuu(0)=12=-1,almu(-1)=24=1,almu(1)=1

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