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91Ó°ÊÓ

Consider a polynomial f(λ)with real coefficients. Show that if a complex numberλ0is a root off(λ), then so is its complex conjugate,λ→0.

Short Answer

Expert verified

The complex conjugate ofλ0isf(λ0¯)=0.

Step by step solution

01

Define the complex number

A complex number is basically a combination of real number and symbolic number. The complex number is in the form of a + ib.

02

Step 2:Find the complex number λ0 is a root of f (λ)

Letfλ=anλn+anλn-1+...+a1λ+a0

Where all the coefficients are real, andλ0bearootoff

Then,

fλ0¯=anλ0n¯+an−1λ¯00n−1+…+a1λ0¯+a0=anλ0n¯+an−1λ0n−1¯+…+a1λ0¯+a0=anλ00n+an−1λ0n−1+…+a1λ0+a0¯=0¯=0

So, λ0¯isalsoarootoff.

The solution is the complex conjugate ofλ0 is fλ0¯=0.

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