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We flip a coin \(100\) times \((n = 100)\) and note that it only comes up heads \(20% (p = 0.20)\) of the time. The mean and standard deviation for the number of times the coin lands on heads is \(\mu=20\) and \(\sigma=4\) (verify the mean and standard deviation). Solve the following:

a. There is about a \(68%\) chance that the number of heads will be somewhere between ___ and ___.

b. There is about a ____chance that the number of heads will be somewhere between \(12\) and \(28\).

c. There is about a ____ chance that the number of heads will be somewhere between eight and \(32\).

Short Answer

Expert verified

Part a. There is about a \(68%\) chance that the number of heads will be somewhere between \(16\) and \(24\).

Part b. There is about a \(95%\) chance that the number of heads will be somewhere between \(12\) and \(28\).

Part c. There is about a \(99.7%\) chance that the number of heads will be somewhere between \(8\) and \(32\).

Step by step solution

01

Part a. Step 1. Given information

\(X\) is a random variable that denotes the number of times the coin lands on heads.

Number of times the coin is flipped, \(n=100\)

Probability that it comes up heads, \(p=20%=0.2\)

02

Part a. Step 2. Calculation

Mean, \(\mu=np=100*0.2=20\)

Standard deviation, \(\sigma=\sqrt{100*0.2(1-0.2)}=4\)

For \(z=\pm1, x_{1}=\mu-z\sigma\) and \(x_{2}=\mu+z\sigma\)

\(\Rightarrow x_{1}=20-1*4=16\) and \(x_{2}=20+1*4=24\)

Thus, \(68%\) of the values of \(X\) lie between \(16\) and \(24\).

03

Part b. Step 1. Calculation

Mean, \(\mu=np=100*0.2=20\)

Standard deviation, \(\sigma=\sqrt{100*0.2(1-0.2)}=4\)

For \(z=\pm2, x_{1}=\mu-z\sigma\) and \(x_{2}=\mu+z\sigma\)

\(\Rightarrow x_{1}=20-2*4=12\) and \(x_{2}=20+2*4=28\)

Thus, \(95%\) of the values of \(X\) lie between \(12\) and \(28\).

04

Part c. Step 1. Calculation

Mean, \(\mu=np=100*0.2=20\)

Standard deviation, \(\sigma=\sqrt{100*0.2(1-0.2)}=4\)

For \(z=\pm3, x_{1}=\mu-z\sigma\) and \(x_{2}=\mu+z\sigma\)

\(\Rightarrow x_{1}=20-3*4=8\) and \(x_{2}=20+3*4=32\)

Thus, \(99.7%\) of the values of \(X\) lie between \(8\) and \(32\).

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