/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 51 Use the following information to... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 6: Q. 51 (page 387)

Use the following information to answer the next four exercises: X~N(54,8)

Find the probability thatx<30

Short Answer

Expert verified

The value of p(x<30)is0.0013.

Step by step solution

01

Given Information

It is given that, X~N(54,8)

渭=54

蟽=8

02

Solution of the Problem

Now, the required probability can be calculated as below:

P(x<30)=Px-渭蟽<30-渭蟽

=PZ<30鈭�548

=P(Z<鈭�3)

=0.0013From standardnormal table

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose X ~ N(8, 1). What value of x has a z-score of 鈥�2.25?

In China, four-year-olds average three hours a day unsupervised. Most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.5 hours and the amount of time spent alone is normally distributed. We randomly select one Chinese four-year-old living in a rural area. We are interested in the amount of time the child spends alone per day.

a. In words, define the random variable X.

b. X ~ _____(_____,_____)

c. Find the probability that the child spends less than one hour per day unsupervised. Sketch the graph, and write the probability statement.

d. What percent of the children spend over ten hours per day unsupervised?

e. Seventy percent of the children spend at least how long per day unsupervised?

Suppose X~N(4,2). What value of x is two standard deviations to the right of the mean?

In a normal distribution, x = 鈥�2 and z = 6. This tells you that x = 鈥�2 is ____ standard deviations to the ____ (right or left) of the mean.

An expert witness for a paternity lawsuit testifies that the length of a pregnancy is normally distributed with a mean of 280days and a standard deviation of 13days. An alleged father was out of the country from 240to 306days before the birth of the child, so the pregnancy would have been less than 240days or more than 306days long if he was the father. The birth was uncomplicated, and the child needed no medical intervention. What is the probability that he was NOT the father? What is the probability that he could be the father? Calculate the localid="1653472319552" z-scores first, and then use those to calculate the probability.
See all solutions

Recommended explanations on Math Textbooks

Logic and Functions

Read Explanation

Geometry

Read Explanation

Decision Maths

Read Explanation

Calculus

Read Explanation

Theoretical and Mathematical Physics

Read Explanation

Applied Mathematics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.