/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 79 Suppose that the duration of a p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 21 days and a standard deviation of seven days.

a. In words, define the random variable X.

b. X ~ _____(_____,_____)

c. If one of the trials is randomly chosen, find the probability that it lasted at least 24 days. Sketch the graph and write the probability statement.

d. Sixty percent of all trials of this type are completed within how many days?

Short Answer

Expert verified
  1. X:The duration (in days) of a particular type of criminal trial.
  2. X~N(21,7)
  3. The probability that it lasted at least 24 days is localid="1653649659113" P(x=24)=0.3341
  4. The time it takes to finish 60 percent of the text of a criminal trial is 2 2. 77 days.

Step by step solution

01

Part(a) Step 1: Given information 

the duration of a particular type of criminal trial is known to be normally distributed with a mean of 21 days and a standard deviation of seven days.

We have to define the random variableX.

02

Part(a) Step 2: Explanation 

A random variable is a variable that reflects the probability in a random experiment. Upper case alphabets such as X,Y,and so on are used to represent it.

The given case entails keeping track of the length of a specific type of criminal trial. Every trial at a particular interval has a different duration. As a result, it can be thought of as a random variable with the following definition:

X:The number of days that a certain sort of criminal trial lasts (in days).

Xseems to be a continuous random variable because it can take an endless number of values in a given interval.

03

Part (b) Step 1: Given Information 

We have to fillX~_____(_____,_____)

04

Part (b) Step 2: Explanation 

Xis a random variable with a mean of 21and a standard deviation of 7that represents the length (in days) of a specific sort of criminal trial. If a random variable Xhas a normal distribution with a mean of μand a standard deviation of s, it is denoted as X~N(μ,s). As a result, the random variable Xin this situation is denoted as: X~N(21,7)

05

Part (c) Step 1: Given Information 

We need to figure out what the chances are that a randomly picked trial will last at least 24 days.

06

Part (c) Step 2: Explanation 

The probability that a randomly selected trial will last at least 24 days is calculated as follows:

P(x≥24)=Px-μσ≥24-217=P(z≥0.4286)

The shaded zone in the graph below depicts the needed probability. As a result, it can be written:

P(z≥0.4286)=0.5-P(0≤z≤0.4286)=0.5-0.1659

From normal table : 0.3341

07

Part (d) Step 1: Given Information 

We must determine the number of days required to complete 60% of criminal cases.

08

Part (d) Step 2: Explanation 

The needed probability is calculated as follows:

P(x<k)=Px-μσ<k-217=Pz<z1=0.6

We get the following results from the normal distribution tables:

z1=0.2533

From the equation x=μ+zσ, we have to replace xwith kand zwith z1

k=21+0.2533*7=22.77

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If the area to the right of x in a normal distribution is 0.543, what is the area to the left ofx?

A NUMMI assembly line, which has been operating since 1984, has built an average of 6,000 cars and trucks a week. Generally, 10% of the cars were defective coming off the assembly line. Suppose we draw a random sample of n=100 cars. Let X represent the number of defective cars in the sample. What can we say about X in regard to the 68-95-99.7 empirical rule (one standard deviation, two standard deviations and three standard deviations from the mean are being referred to)? Assume a normal distribution for the defective cars in the sample.

Thuy Dau, Ngoc Bui, Sam Su, and Lan Voung conducted a survey as to how long customers at Lucky claimed to wait in the checkout line until their turn. Let \(X=\) time in line. Table below displays the ordered real data (in minutes):

a. Calculate the sample mean and the sample standard deviation.

b. Construct a histogram.

c. Draw a smooth curve through the midpoints of the tops of the bars.

What is the z-score of x=12, if it is two standard deviations to the right of the mean?

In 2005,1,475,623students heading to college took the SAT. The distribution of scores in the math section of the SAT follows a normal distribution with mean µ=520and standard deviation σ=115

  1. Calculate the z-score for an SAT score of 720. Interpret it using a complete sentence.
  2. What math SAT score is 1.5 standard deviations above the mean? What can you say about this SAT score?
  3. For 2012, the SAT math test had a mean of 514 and standard deviation 117. The ACT math test is an alternate to the SAT and is approximately normally distributed with mean 21 and standard deviation 5.3. If one person took the SAT math test and scored 700 and a second person took the ACT math test and scored 30, who did better with respect to the test they took?
See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.