/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.6.67 In 2005, 1,475,623 students he... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In 2005,1,475,623students heading to college took the SAT. The distribution of scores in the math section of the SAT follows a normal distribution with mean µ=520and standard deviation σ=115

  1. Calculate the z-score for an SAT score of 720. Interpret it using a complete sentence.
  2. What math SAT score is 1.5 standard deviations above the mean? What can you say about this SAT score?
  3. For 2012, the SAT math test had a mean of 514 and standard deviation 117. The ACT math test is an alternate to the SAT and is approximately normally distributed with mean 21 and standard deviation 5.3. If one person took the SAT math test and scored 700 and a second person took the ACT math test and scored 30, who did better with respect to the test they took?

Short Answer

Expert verified
  1. The z- score of 720is 1.74standard deviation above the mean value.
  2. The value of the z- score 1.5is 692.5.
  3. The z-score for the ACT score is greater than the z-score for the SAT score. So second person did better than the first person.

Step by step solution

01

Given information (Part a)

Given in the question that

Normal distribution with Mean =520

Standard diviation=115

02

Solution (Part a)

Here we need to calculate the z-score of x=720

The calculation is given below,

z=x−μσ

=720−520115

=1.74

03

Given information (Part b)

Given in the question that

Mean=520

Standard deviation=115

04

Solution (Part b)

Here we need to find the SAT math's score of 1.5standard deviations above the mean,

So the calculation is,

z=x−μσ

1.5=x−520115

x=1.5×115+520

=692.5

05

Given information (Part c)

Given in the question that

Mean=520

Standard deviation=115

06

Solution (part c)

We need to calculate the z-score for both tests to get the desired result.

Here is the z-score for the SAT score is calculated below,

z=x−μσ

=700−514117

=1.59

So, the z-score for the ACT score will be,

z=x−μσ

=30−215.3

=1.70

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

About what percent of the x values from a normal distribution lie within two standard deviations (left and right) of the mean of that distribution?

Suppose X ~ N(4, 2). What value of x is 1.5 standard deviations to the left of the mean?

The life of Sunshine CD players is normally distributed with a mean of 4.1 years and a standard deviation of 1.3 years. A CD player is guaranteed for three years

Find the 70thpercentile of the distribution for the time a CD player lasts

a. Sketch the situation. Label and scale the axes. Shade the region corresponding to the lower 70%.

b. P(x<k)=__________Therefore,k=_________

An expert witness for a paternity lawsuit testifies that the length of a pregnancy is normally distributed with a mean of 280days and a standard deviation of 13days. An alleged father was out of the country from 240to 306days before the birth of the child, so the pregnancy would have been less than 240days or more than 306days long if he was the father. The birth was uncomplicated, and the child needed no medical intervention. What is the probability that he was NOT the father? What is the probability that he could be the father? Calculate the localid="1653472319552" z-scores first, and then use those to calculate the probability.

The heights of the 430National Basketball Association players were listed on team rosters at the start of the 2005–2006season. The heights of basketball players have an approximately normal distribution with mean, µ=79inches and a standard deviation, σ=3.89inches. For each of the following heights, calculate the z-score and interpret it using complete sentences

a. 77inches

b. 85inches

c. If an NBA player reported his height had a z-score of 3.5, would you believe him? Explain your answer

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.