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91Ó°ÊÓ

Is there a difference between the distribution of community college statistics students and the distribution of university statistics students in what technology they use on their homework? Of some randomly selected community college students, 43 used a computer, 102 used a calculator with built in statistics functions, and 65 used a table from the textbook. Of some randomly selected university students, 28 used a computer, 33 used a calculator with built in statistics functions, and 40 used a table from the textbook. Conduct an appropriate hypothesis test using a 0.05 level of significance.

Read the statement and decide whether it is true or false.

Short Answer

Expert verified

There is sufficient evidence to insure that the distribution of college statistics students is different from the distribution of university statistics students.

Step by step solution

01

Given Information

Given that randomly selected community college students, 43 used a computer, 102 used a calculator with built-in statistics functions, and 65 used a table from the textbook.

Of some randomly selected university students, 28 used a computer, 33 used a calculator with built-in statistics functions, and 40 used a table from a textbook.

02

Null Hypothesis

The null hypothesis is shown below: H0: The distribution of college statistics students is same as the distribution of university statistics students.

03

Alternative Hypothesis

Against the alternative hypothesis as shown below:

Ha:The distribution of college statistics students is different from the distribution of university statistics students.

04

Degrees of Freedom

The degrees of freedom can be calculated by the formula given below:

df=(numberofcolumn-1)

Therefore

df=3-1

=2

df=3-1

05

Distribution

From above calculation, it is clear that the distribution for the test is χ22.

06

Expected  Frequencies

The observed value table is already given in the textbook. Calculate the expected frequencies by using the formula given below:

E=(row total)(column total)overall total

All calculations can be done in excel worksheet. Hence, the expected localid="1649136146590" (E)values table is shown below:

07

Test statistic

The test statistic of the independence test is given below

Test statistic=∑(i×f)(O-E)2E

To calculate (O-E)2Eapply the formula

=(B4-B11)2/B11

same formula up to cell D19. After that, take the total of columns total and rows total. The table of the test statistics is shown below:

08

p-Value

The p-value can be calculated in excel by using CHIDIST ( ) formula as shown below:

Hence the p-value is 0..29

09

The Chi-square Sketch

The Chi-square sketch is given below

10

Final Answer

i. Alpha:0.05

ii: Decision: Reject the null hypothesisH0

iii. Reason for decision: Becausep-value <α

iv. Conclusion: There is sufficient evidence to insure that the distribution of college statistics students is different from the distribution of university statistics students.

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Most popular questions from this chapter

A psychologist is interested in testing whether there is a difference in the distribution of personality types for business majors and social science majors. The results of the study are shown in Table. Conduct a test of homogeneity. Test at a 5%level of significance.

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Use the following information to answer the next seven exercises: Transit Railroads is interested in the relationship between travel distance and the ticket class purchased. A random sample of \(200\) passengers is taken. Table 11.31 shows the results.

The railroad wants to know if a passenger’s choice in ticket class is independent of the distance they must travel.

What is the \(p-\)value?

Transit Railroads is interested in the relationship between travel distance and the ticket class purchased. A random sample of 200passengers is taken. Table 11.31 shows the results. The railroad wants to know if a passenger’s choice in ticket class is independent of the distance they must travel.

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State the hypothesis:

H0:

Hα:

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