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91Ó°ÊÓ

The marital status distribution of the U.S. male population, ages 15and older, is as shown in Table 11.35.

Martial Status Percent Frequency
never married 31.3
married 56.1
widowed 2.5
divorced /separated 10.1

Short Answer

Expert verified

Data does not fit the distribution.

Step by step solution

01

Given Information

Martial Status Percent Frequency
never married 31.3
married 56.1
widowed 2.5
divorced /separated 10.1
02

Explanation

Martial Status Percent Frequency
never married 31.3 125.2
married 56.1 224.4
widowed 2.5 10
divorced /separated 10.1 40.4

The data fits the distribution.

The data does not fit the distribution.

chi-square distribution with df=3.

03

Explanation

α=0.05

Decision: Reject null.

Reason for decision: p-value<α.

Conclusion: Data does not fit the distribution.

04

Final Answer

Data does not fit the distribution.

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Most popular questions from this chapter

Decide whether the following statements are true or false:

As the number of degrees of freedom increases, the graph of the chi-square distribution looks more and more symmetrical.

The mean and the median of the chi-square distribution are the same if df=24.

The table provides a recent survey of the youngest online entrepreneurs whose net worth is estimated at one million dollars or more. Their ages range from 17to 30. Each cell in the table illustrates the number of entrepreneurs who correspond to the specific age group and their net worth. Are the ages and net worth independent? Perform a test of independence at the 5%significance level.

Age Groupl Net Worth Value (in millions of US dollars)1-56-24≥25Row Total17-258752026-3065920Column Total14121440

use a solution sheet to solve the hypothesis test problem. Go to Appendix E for the chi-square solution sheet. Round expected frequency to two decimal places car manufacturers are interested in whether there is a relationship between the size of the car an individual drives and the number of people in the driver’s family (that is, whether car size and family size are independent).To test this, suppose that 800car owners were randomly surveyed with the results in Table 11.44. Conduct a test of independence.

Family SizeSub & CompactMid-sizeFull-sizeVan & Truck
1
20
35
40
35
2
20
50
70
80
3-4
20
50
100
90
5+
20
30
70
70

Table 11.44

Use a solution sheet to solve the hypothesis test problem. Go to Appendix E for the chi-square solution sheet. Round expected frequency to two decimal places.

A manager of a sports club keeps information concerning the main sport in which members participate and their ages. To test whether there is a relationship between the age of a member and his or her choice of sport, 643members of the sports club are randomly selected. Conduct a test of independence.

Sport18-2526-3031-4041andover
racquetball42583046
tennis58763865
swimming72606533
See all solutions

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